The equation for a circle with a known center of 0,1 and a radius of 2 is

The center of the circle is (0'1) The equation for a circle with radius 2 is :

x-0)^2+(y-1)^2=2^2

x 2+y 2-2y-3=0 is what is sought.

Formula for perimeter:Circle: c = d = 2 r (d is the diameter, r is the radius, ) triangle.

The circumference of c = a+b+c (abc is the three sides of a triangle) quadrilateral. c=a+b+c+d (abcd is the side length of a quadrilateral) special: rectangle:

c = 2 (a + b) (a is long, b is wide) square: c = 4a (a is the length of the sides of the square).

Polygon. c = sum of all edge lengths.

The standard equation for a circle with a radius of 2 is x 2+(y-1) 2=, the center of the circle is the point (3,4), and the standard equation for a circle that passes through the coordinate origin: (x-3) 2+(y-4) 2=253

Substitute each point into x 2+y 2, if it is greater than 4, it is outside the garden, equal to 4 is on the circle, less than 4 is in the circle, etc

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The equation for a circle with a center of (0,1) and a radius of 2 is x +(y-1) = 4.

In the standard equation for a circle (x a) + y b) = r, there are three parameters a, b, r, that is, the coordinates of the center of the circle are (a, b).

All you want is:

x²+(y－1)²=4

Solution: Let the coordinates of any jujube banquet point on the circle be (x,y), according to the coordinates of the center p of the circle is (dry 3,-2), the radius of the circle r=2, and the standard equation of the circle is obtained as: (x-3)2+(y+2)2=4

Forget about the garden equation.

x-3)^2+(y+2)^2=4

x-3)^2+(y+2)^2=4

1] Answer the general equation of the stool punch: (x-3) 2+(y+1) 2=4 The formula of the equation for the circle: (x-a) 2+(y-b) 2=r 2 The center of the circle is (a, b) The radius is r 2] Standard equation:

x 2-6x+y 2+2y+14=0 x 2+y 2+dx+ey+f=0

Dear, I'm glad to find the equation for a circle with the center of c(3,-2) and a radius of 10 is (x-3) +y+2) 10 I hope it can help you!