Analysis of high school biology questions, answers to high school biology questions

The preparation of monoclonal antibodies and the production of insulin in the first figure is genetic engineering, and cell engineering mainly refers to the culture of cells and tissues, so d is correct.

In the second picture, the extraction of orange peel essential oil is by pressing method, and the distillation method will produce burnt paste, so A is wrong, and option C tests the totipotency of plant cells and is also a form of cloning, which can quickly reproduce specific plants, so it is correct.

After the increase of the wavelength of option b on the third figure, the light energy absorption rate of chlorophyll a increases, that is, the photoreaction increases, the photoreaction products ATP and Nadph increase, and the C5 content should decrease after entering the dark reaction. The decrease in temperature in option d affects the activity of enzymes, and the absorption of light energy by chlorophyll will also use biological macromolecules such as enzymes, so it has an effect, and option d is correct.

The first figure shows that the production of monoclonal antibodies does not belong to cell engineering, and generally the process is mass production, which is not only the preparation of monoclonal antibodies, but also the preparation of monoclonal antibodies. The production of human insulin from yeast is genetically engineered. Banana detoxification seedlings are the use of plant cell tissue culture shoot tips for detoxification.

The second figure shows that orange peel essential oil is pressed and distilled is used for rose essential oil. There are words in the textbook explaining why you can't use the distillation method, so read the textbook carefully.

The third picture is the fifth question, right? Option b is because the light reaction is enhanced, which promotes the dark reaction, and C3 will accelerate the utilization, so C3 decreases and C5 increases.

The basics are to read the textbook. If you don't understand, you can ask.

The high school biology test is very detailed, and there are many knowledge points, but it is not difficult. There are many concepts that need to be mastered, so you need to read more books and memorize more books. Compared with physical chemistry, it is the liberal arts in science, and generally students who work hard can get close to full marks in the exam by memorizing more.

It's not very difficult, it's as difficult to learn as geography in the liberal arts, and it's a little more difficult to learn than history and politics<>

High School Biology Question Answers.

The biology test in high school is very detailed, and there are a lot of knowledge points, but it is not difficult. There are many general links that need to be mastered, so you have to read more books and memorize more. Compared with physical chemistry, it is the liberal arts in science, and generally students who work hard can get close to full marks in the exam by memorizing more.

It's not very difficult, and the difficulty of learning is comparable to that of geography in the liberal arts, and it is a little more difficult to learn than history and politics<>

Can students send specific questions to the teacher This is more convenient to answer, it's troublesome

The fifth question of the first picture and the first three questions of the second picture.

The teacher can see everything for me, maybe I chose the wrong one.

The fifth question in the first picture is wrong to choose that histone modification changes in C islet repentance B cells cause a weakening of DNA replication and normalization, which can induce diabetes. Epigenetic changes play an important role in the occurrence of various diseases such as diabetes and early urination, but the ways of epigenetic changes and the mechanisms that lead to the disease are diverse and need to be studied in depth.

The second first question cHemoglobin needs to be processed by the endoplasmic reticulum and the Golgi apparatus in order to function in the chain car, and the description is wrong, calling that hemoglobin is fully formed in mature red blood cells and there is no need for further processing.

The first three questions are b. Structure refers to the chloroplast in photosynthetic, which is distributed with pigment molecules that are able to absorb light energy. The structure is the outer and inner membranes of chloroplasts, but the inner membrane area is smaller than the outer membrane area, so option A is wrong.

Structure refers to the nucleus of a cell, which contains genetic information but cannot be directly involved in the synthesis of the enzyme containing the head in photosynthesis. In the last option, the photosynthetic pigments are reduced after shading, but the number of structures (i.e., chloroplasts) and membrane area are not drastically reduced, as they are the main sites of photosynthesis.

This is the third question: bAfter protein dust form 2 is activated by HO, it transports Ca+ by constantly changing the conformation.

Other options are not exactly as described: aProtein 1 should be involved in the consumption reaction of O rather than the reaction of the growth chain brother. c.

Proteins that assist in diffusion transport are not transported out of Na+ but by Na+ or other ions; d.Under hypoxic conditions, changes in salt tolerance are not directly related to the decrease in cellular respiration rate.

The one above is the second question.

The answer to the third capers is b"Add salt and knead to emerald green" takes advantage of the fact that chlorophyll can be dissolved in a high concentration of ground state NaCl solution, which is wrong. In fact, the emerald green color of capers is due to the addition of some green vegetables, peppers and other ingredients by Tian Feng, and has nothing to do with salt.

The answer to the last question in the third picture is a bit incomplete, can you take a complete picture? <>

Summary. The first empty is the second level, and the second is that the interspecific relationship between the green shrimp and zooplankton is a predatory relationship. Green shrimp feed on zooplankton, which helps to maintain the ecological balance of rice and crab integrated cultureThe third empty can help remove weeds in the rice field and promote the growth of the rice field, and their excrement can also provide nutrients for the rice field, which helps to improve the yield and quality of rice.

Chinese mitten crab can also provide food for crabs, promote the growth of crabs, and increase breeding income. The fourth empty trash fish is an important biological bait. They provide food for crabs and promote their growth, while also removing debris and plankton from ponds to maintain stable water quality.

22 questions no, thank you.

The first empty is the second level, and the second is that the interspecific relationship between the green shrimp and zooplankton is a predatory relationship. Green shrimp feed on zooplankton, which helps to maintain the ecological balance of rice and crab integrated culture, and the third empty can help to clear and eliminate weeds in the rice field, promote the growth of the rice field, and their excrement can also provide nutrients for the rice field, which helps to improve the yield and quality of rice. Chinese mitten crab can also provide food for crabs, promote the growth of crabs, and increase breeding income.

The fourth empty trash fish is an important biological bait. They can provide food for crabs, promote the growth of crabs, and when accompanied by the same chain, they can also remove debris and plankton from the pond and maintain stable water quality.

The third question, the integrated farming model of rice crab can be used with oak rows, for the following reasons: it is contrasting, and the amount of rice is the same1The integrated rice and crab farming model can improve the yield and quality of paddy fields.

The excrement of crabs and green shrimp can provide nutrients for rice fields, helping to improve the yield and quality of rice. 2.The comprehensive pure side culture of rice crabs can promote the growth of rice.

Crabs and green shrimp can help remove weeds from rice paddies and promote the growth of paddy fields. 3.The integrated farming model of rice crab can improve the income of aquaculture.

Chinese mitten crabs and small trash fish can provide food for crabs, promote the growth of crabs, and increase the income of farming.

Question 4. 1。Large, Medium, Small2Put in shrimp fry 3Yield.

Summary. The answer is as follows: (1) B, ATP, CA (2) A, C, the viability of the patina microalgae (3) is reduced because the ratio of acid (HCO3-) and carbon dioxide (CO2) concentrations in the water body has changed at this time, and the concentration of HCO3 is low and is not enough to provide enough substrate for the CA reaction.

High concentration of CO2 can inhibit the activity of CA and lead to a decrease in CA activity. <>

20 questions will not, thank you.

The first three questions.

Dear, the answer is as follows: (1) B, ATP, CA (2) A, C, Rust microalgae (3) The activity of the sorrel is reduced because the ratio of acid (HCO3-) and carbon dioxide (CO2) concentrations in the water body has changed, and the concentration of HCO3 is low, which is not enough to provide enough substrate for the CA reaction. High concentration of CO2 can inhibit the activity of CA and lead to a decrease in CA activity.

In fact, the focus of these two answers lies in the question of whether the question is equal mass concentration or equal molar concentration.

If it is an equal mass concentration, as shown in the question, B should be chosen

If it is equal to the molar concentration, you should choose d,2,kathywu403 to report.

I think the focus of this question is whether glucose permeates the semi-permeable membrane, and the question says that the semipermeable membrane only allows water to permeate, and the same mass concentration means that the concentration of the two solutions is the same? Glucose must not pass through the semi-permeable membrane, and glucose enters the cell in the cell.

As shown in the figure, a water tank with a semi-permeable membrane (only allowing water molecules to pass through) is spaced at intervals, and equal concentrations of glucose solution and maltose solution are added to each side. Then the same mass of maltase is added on both sides of the semi-permeable membrane, and the change of liquid level on both sides of A and B before and after the addition of maltase is theoretically ( ).

A rises on the A side before the enzyme is added, and the B side rises after the enzyme is added and is equal to the height of the A side.

B rises on the A side before the enzyme is added, and the B side rises and is higher than the height of the A side after the enzyme is added.

C Before and after adding enzyme, the liquid surface on both sides of A and B remained unchanged.

D The liquid level on both sides of A and B remained unchanged before enzyme addition, and the height of B side rose and was higher than that of side A after enzyme addition.

When asked which one to choose B or D?

There is an answer to choose B, the reason is that the glucose molecule weight of glucose solution and maltose solution of equal mass concentration is small, the amount concentration of substances on side A is high, and there are more water molecules entering side A, and side A rises; After adding the same mass of maltase on both sides of the semi-permeable membrane, the 1 molecule of maltose on the B side is decomposed into two molecules of glucose, because the mass of 1 molecule of maltose is less than the mass of two molecules of glucose, the concentration of the substance on the B side is greater than the concentration of the substance on the A side, according to the principle of osmosis, the water molecules entering the B side increase, so the B side rises and is higher than the height of the A side after adding the enzyme.

Another answer is to choose D, the reason is that before adding enzymes, because the semi-permeable membrane can only permeate water molecules, but the concentration of glucose and maltose on both sides is equal, the water in and out is dynamically balanced, and the liquid level on both sides remains unchanged. After the addition of maltase, one molecule of maltose decomposes to produce two molecules of glucose, but the glucose side remains unchanged, and the concentration of the B side increases, so the water molecules are transported from side A to side B, causing the liquid level on side B to rise and be higher than the height of the liquid level on side A.