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The dividend and the divisor are multiplied by 10 at the same time, the quotient (unchanged), and the remainder (the remainder multiplied by 10).
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder expands by a factor of 10.
For example, the original formula is 9 2 = 4 ......1
The dividend and the divisor are multiplied by 10 at the same time.
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Dividend Divisor = quotient....Remainder.
When the dividend and divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder is 10 times the original.
For example, if the dividend is 10 and the divisor is 3, the resulting quotient is 3 and the remainder is 1, when the dividend and the divisor are both multiplied by 10, the quotient is 3 and the remainder is 10, so the quotient does not change, and the remainder becomes 10 times the original.
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient does not change.
Multiply the remainder by 10, e.g. 8, 3, 2......2
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Assuming that the dividend a = divisor b quotient c + remainder d, then the dividend 10a = divisor 10b quotient c + remainder 10d, so the dividend and the divisor are multiplied by 10 at the same time, the quotient is unchanged, and the remainder is also multiplied by 10,
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder is multiplied by 10
Example: 10 8 = 1 surplus 2
100 80 = 1 surplus 20
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The results remain the same. For example, 4 2 = 2, the dividend.
Multiplying by 10 at the same time as the divisor makes 40 20 = 2. It's good to make an appointment.
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The dividend and the divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder becomes 10 times.
For example, 30 14 = 2....2
becomes 300 140 = 2....20
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Multiply the dividend and divisor by 10 at the same time, the resulting quotient is unchanged, and the remainder is multiplied by 10.
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient is constant and the remainder is multiplied by 10
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Because the dividend divisor = quotient. If the dividend and the divisor are multiplied by 10 at the same time, then the quotient does not change, and the remainder is 10 on the original basis
For example: 7 2 = 3 ......1, if the dividend and the divisor are 10 at the same time, then it becomes 70 20 = 3 ......10。
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder is 10 times the original remainder.
e.g. 5 2 = 2....1,50÷20=2…10
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If the dividend and the divisor are multiplied by 10 at the same time, for example, 6 2 = 3, then, 6 10) (2 10) = 60 20 = 3, so the quotient is constant. If there is a remainder, it is also constant.
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If the dividend and the divisor are multiplied by ten at the same time, then the quotient does not change, and the remainder is also multiplied by ten.
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient is (the original number remains unchanged) and the remainder is (becomes 10 times the original). Examples:
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder is multiplied by 10 at the same time.
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder expands by a factor of 10.
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If both the dividend and the divisor expand (or shrink) by the same multiple, the quotient does not change. But the remainder should be enlarged (or reduced) by the same multiple.
In your problem, the quotient remains the same, but the remainder is multiplied by 10
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The dividend and divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder is also multiplied by 10
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The dividend and the divisor are multiplied by 10 at the same time
Then, the quotient does not change, and the remainder becomes 10 times.
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In a division equation with remainders, if the dividend and the divisor are multiplied by 10 at the same time, the quotient does not change, and the remainder is also multiplied by 10.
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If the dividend and the divisor are multiplied by 10 at the same time, the quotient will not change, and then the remainder will become one-tenth of the original number.
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Dividend = x divisor = y
Quotient = k remainder = m
x=ky +m
If the dividend and the divisor are multiplied by 10 at the same time
10x=10(ky +m)
10x=10ky +10m
quotient = k: unchanged.
Remainder = 10m : 10 times remainder.
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If the dividend and divisor are expanded by 10 times at the same time, the quotient remains unchanged and the remainder is also expanded by 10 times.
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The result is the same. For example, 4 2 = 2. When the dividend and the divisor are multiplied by 10 at the same time, it becomes 40 20 = 2 minus.
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Answer: The quotient remains unchanged. The remainder is expanded by a factor of 10. For example:
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Summary. At the same time, divide by ten, the quotient is 50, and the remainder is 3.
The remainder is the dividend quotient of the divisor.
The dividend and the divisor are reduced by 10 times at the same time, and the quotient is still 50, because the dividend is reduced by 10 times, so the remainder is also reduced by 10 times to 3.
If the quotient of two numbers divided by 50 is more than 30, if the dividend and the divisor are divided by 10 at the same time, what is the quotient and remainder obtained.
At the same time, divide by ten, the quotient is 50, and the remainder is 3. Remainder Dividend Quotient The divisor is reduced by 10 times at the same time, and the quotient is still 50, because the dividend is reduced by 10 times, the remainder is also reduced by 10 times to 3.
Classmate, like this.
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Summary. Hello, multiply the dividend and divisor of 930 70 by 10, the quotient is 13, and the remainder is 2.
Multiply the dividend and divisor of 930 70 by 10 quotient and remainder.
Hello, multiply the dividend and divisor of 930 70 by 10, the quotient is 13, and the remainder is 2.
Because 930 70 13 surplus 2930x10 70x10 = 13 surplus 2 scattered, the divisor and divisor of 930 70 are multiplied by 10 quotient is 13, and the remainder is 2.
Pro, the dividend and the divisor are multiplied or divided by the same non-0 number at the same time, and the quotient does not change.
Dear, division is one of the four nucleus operations, which is an operation to find the product of two factors and one of the non-zero factors. The division of two numbers is also called the ratio of two numbers that destroy the number of blind digs.
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Summary. The quotient remains unchanged, and the remainder expands by 10 times. For example, 5 2 = 2 ......150÷20=2……10
In division with remainders, if the dividend and the divisor are multiplied by 10 at the same time, then what is the quotient? What is the remainder?
The quotient remains unchanged, and the remainder expands by 10 times. For example, 5 2 = 2 ......150÷20=2……10
In division with remainders, the quotient of multiples of the dividend and the divisor is unchanged. The remainder is also expanded by a corresponding multiple.
In division with remainders, if the dividend and the divisor are 10 at the same time, then what is the quotient and what is the remainder?
The quotient does not change, and the remainder is multiplied by 10
It's not the same amount, there is no exact value. It is necessary to have a corresponding change. That is, the quotient does not change, and the remainder is multiplied by 10.
How do you drop the equation of 396 57?
Quotient 6, remainder 54
Do you need to calculate vertically?
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The quotient remains the same. Remainder.
It's not stupid to change. Suppose a b = integer c + remainder d, 20xa 20xb = a b = c + d
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Solution: The quotient remains unchanged. The remainder is enlarged by a factor of 20.
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600 90, the dividend and the divisor are divided by 10 at the same time, what is the quotient and what is the remainder.
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The answer to this question is that the quotient is six, and the remainder is also six.
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The dividend and the divisor are multiplied by 10 at the same time, indicating that the original quotient and the remainder are multiplied by 10 at the same time, and the original quotient is x and the remainder is y, then the following equations can be listed:
10a + 10b) ÷10c + 10d) =7 ..1)
10a + 10b) %10c + 10d) =10 ..2)
among others"Indicates divisible,"% indicates the surplus.
Divide the divisor and the dividend in isometric rubber equation (1) by 10 at the same time, and we get the following system of equations:
a + b = 7(c + d) .3)
a + b = 10c + 10d + 1 ..4)
Substituting equation (3) to the right into equation (4) gives 7c + 7d + 1 = 10c + 10d + 1, i.e. 3c = 3d, so c = d.
Subtracting 70 from both the left and right sides of the equation (1) gives a - 7c = 10d - b, which, combined with the conclusions drawn in the previous section, gives a = 10, b = 40, c = 1, and d = 1.
Therefore, the original quotient is 10 and the remainder is 40% 10 * 1 + 10 * 1) =20.
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According to the question and eye conditions, we can list the equations:
10x + 10) ÷10y + 10) =7...
10x + 10) mod (10y + 10) =10...
where x is the dividend and y is the divisor. Since the remainder is 10, we can get another equation:
10x + 10 - 7(10y + 10) =1010x - 70y = 80
x - 7y = 8
Next, we need to find the integer solution that fits the above equation. Since the problem does not explicitly require that the quotient and remainder are positive integers, we can solve the equation directly. Obviously, when y = 2, x = 6 satisfies the equation x - 7y = 8, satisfying both the system of equations and the group of equations.
So, the original quotient is 6 and the remainder is 10.
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The original quotient is 7 and the remainder is 1
For example, 15 2=7....1
The dividend and the divisor are multiplied by 10 at the same time, and it becomes.
The remainder of 10 is for Qi Chun in terms of the divisor 20. You can't take the result of the covenant and say that Gao trembling told Dong Hui to ......
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According to the inscription, the following equations can be listed:
10x + 10) ÷10y + 10) =7 ..1)10x + 10) mod (10y + 10) =10 ..2) Move equation (1) and simplify it to obtain:
x = 7y - 6
Substituting x into Eq. (2) and rounding the kernel yields:
y = 3 Therefore, the original Kaishan quotient is x = 7y - 6 = 15, and the remainder is 10 in Eq. (2), i.e., the original remainder is 10.
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Solution: According to the law of quotient invariance, the original Shang Sui mu is still 7, and the deficiency is only that the remainder is 1, and the remainder is 10 times because the dividend and the divisor are expanded by 10 times at the same time, and the remainder has changed from 1 to 10.
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Summary. The quotient of the division of two numbers is 15, and the remainder is 40. If the dividend and the divisor are multiplied by 5 at the same time, the quotient is 15 and the remainder is 5
The quotient of the division of two numbers is 15, and the remainder is 40. What is the quotient if the dividend and the divisor are multiplied by 5 at the same time? What is the remainder?
For example, 655 41 = 15....40655×5=327541×5=2053275÷205=15…200
Dividend Divisor = quotient .........Remainder.
Dividend = Divisor Quotient + Remainder. >>>More
Because of the dividend.
Divisor = quotient + remainder. >>>More
Dividend = Divisor Quotient + Remainder.
Here, remainder = 0. So, the dividend = the divisor quotient. >>>More
This statement is false.
Method 1. The formula expression for division is: Dividend divisor = quotient, since the quotient of two numbers is 8, it can be obtained: dividend divisor = 8. >>>More
According to the meaning of the title, the dividend + divisor + 7 + 2 = 219 So, the dividend + divisor = 210 >>>More