If the complex number Z 2 I, I is an imaginary unit, and Z is the conjugate complex number of Z, the

The "*" and " in the title are typical, are they the same? , then since z -- is the conjugate plural of z, z --= i-2

Original = (1-i+2) (1-2+i )

3-i)/(1-i)

3-i)(1-i)/(1-i)(1-i)-(2-4i)/(2i)

2-4i)/(-2i)

1-2i)/(-i)

1-2i)(-i)/(-i)(-i)

1-2i)(-i)/(-1)

1-2i)(-i)×(1)

1-2i)(-i)(-1)

1-2i)(+i)i-2

The "*" and "" of the theme are wrong and are the same, right? i-2 due to z-=

The original formula = (1-i-2) (1-2 +)3-z,z-complex conjugation) (1-i).

3-i) (1-) (1-i) (1-i).

2-4i) (2i) > = (2-4i) (-2i) (1-2i) (-.)

1-2i) (- ( -

1-2i) (-1).

1-2i) (-1).

1-2i) (i) (-1).

1-2i) (- ( -

I-2

It has been known that i is an imaginary unit, and the number of repentance trapped holes z is full of blue dry feet zz-2z=3+4i, then the conjugate complex of z is a-1-2ib.-1+

Kiss [open Li Lianxin] <>

Hello, I'm glad to answer your <>

<> the complex number z is expressed as the form x+yi, where x and y are real numbers, then the conjugate defeat complex of z is x-yi. Substituting z = x+yi into the given equation yields: (x+yi)(x+yi) -2(x+yi) =3+4i, and then we get:

x 2 + y 2 - 2x - 2yi = 3+4i equalize the real and imaginary parts respectively, yielding: x 2 + y 2 - 2x = 3 (1)-2y = 4 (2) from (2) gives y = 2, and substituting (1) gives x = 1. Therefore, the conjugate complex of z = is -1+2i, option b

1+2i is the correct answer.

z=(1+i)(1-2i)=1-2i+i-2i²=1-i+2=3-i

So the conjugate complex of z is 3+i

Calculate z and you get it.

From z(1+i)=2-2i, obtained.

z＝2?2i1+i＝(2?2i)(1?i)(1+i)(1?i)＝?4i2＝?2i．

The conjugate complex of the complex number z is 2i

So the answer is: 2i

( ) from the meaning of the title.

z=1+2i，z1=4+3i

1+2i(4+3i)(1?2i)

1+2i)(1?2i)

10?5i5=2-i．

z is a root of the equation 2x2+px+q=0 about x, then. z is also a root of the equation 2x2+px+q=0 about x, z+

z=2=?p

2,2, the solution gives p=-4, q=10

∵i²=-1

z=1+i+..i to the power of 2013.

1 + i + i to the fourth power + .i to the 2012 power) + (i + i + i to the fifth power +.i2013 power).

(1+i)+i-4th power+i-6th)+.i2008 to the power + i2010 to the power) + i2012 to the power] + [i + i ) + i to the fifth power + i to the seventh power) +i2009 to the power + i2011 to the power) + i2013 to the power].

i2012 power + i2013 power.

1+i

z-2=2 (1-i)=[2(1+i)] 1-i)(1+i)]

2+2i)/2

1+i, so z=3+i, then the positive number of the co-cultivated yoke of collapse z is 3-i.

The solution is to dismantle the acre: the solution can be obtained from the question.

Z-3-i, and then by Xun Noisy Jujube.

zz1=4+3i, available.

z1=4+3iz4+3i

3-i4+3i)(-3+i)

3-i)(-3+i)15-5i

i, the coordinates of the corresponding point in the complex plane are (-

2. Therefore, C. is chosen

Answer: Solution: z=1+i,

z=1-i, then. z2

z(1+i)21-i

2i1-i2i(1+i)

1-i)(1+i)

1+i, the corresponding point is (-1, 1), so choose c