a b 45 b how many of b and a are added to b and a respectively, and are solved by arithmetic?

Arithmetic is the process of calculating a problem or formula according to the prescribed rules and sequences, and finding the result. Including: addition, subtraction, multiplication, division @, power, open square and other forms of operation.

However, your problem is a system of equations. There is no way to do the math with arithmetic. It is only possible to solve the equation method. Substitute b equals five a's.

That's 5a 2=45

a^2=9a=3，a=-3

Because b=a+a+a+a+a+a=5a, from a*b=45, get.

a*(5a)=45，5*a*a=5*9

a*a=9 gives a=3, then b=5*3=15.

a×b＝45

b 5a takes the lower equation to the upper equation to get 5a 45

Then it is solved that a is equal to 3. Then bring a is equal to 3 to the following equation, and we get b equal to 5 and 3 equal to 15. So the value of a is 3 and the value of b is 15

ab 45, b a a 5a, substituting 5a into ab 45 gives 5b 2 45, b 3, and when b 3, a 15

b 3, a 15

Through the description of the problem, we can list two equations, the first equation, a+b 62, the second equation a+b 5 46, then, through observation, we can find that there are two equations, and the two equations contain two unknowns, so the essence of this problem is to solve a binary equation. When solving the dualistic one-time square ascension process, the most common method is the elimination method. If we multiply the left and right sides of equation two by five at the same time, then we can get a new equation, 5a + b 230, then we can combine the newly obtained equation with the first equation, subtract equation one from the left and right sides of the new equation, and we can eliminate the unknown number b, and wait until a unary equation, which is 4a 230-62, so that it is converted into solving a unary equation, and we can solve a 42.

Disadvantages: If we substitute the solved a 42 into equation 1, we can get 42 + b 62, then b 62-42, and the solution b 20 is obtained. So, it can be concluded that a 42, b 20. After solving the values of a and b, we can substitute a and b into the two equations respectively, substituting 42+20 62 in equation 1, and 42+20 5 46 in equation 2, so the values of a and b can make both equations true, that is, the solved values are correct.

Assuming that A and B are two numbers, Nazai knows that the condition is:

a + b = 62

a + b) ÷5 = 46

According to the second condition, it is possible to launch:

a + b = 46 × 5

a + b = 230

Bringing this result to the first condition, we get:

a + b = 62

a + b = 230

Since the left sides of both equations are equal, you can subtract them to get:

This is false, indicating that under the two known conditions, A and B are not susceptible to snuggling at the same time. Therefore, the solution to this problem should be unsolvable, there may be problems or incomplete information, which needs to be further verified and supplemented.

Summary. Kiss, the specific analysis and answer are shown in the figure below, please check A plus B equals 62, A plus B divided by 5 equals 46, so how much is A and B.

Dear, the specific analysis and answer are shown in the figure below, please check

Dear, if there is anything you can't understand, you can continue to ask me.

According to the question, Li is bored: Grilled feast a+b=45 4a=b

So a+4a=45

a=9b=4a=36

1. (a+b)(a-b)=55, if a, b are required to be positive integers.

Then 55 = 55 * 1 = 11 * 5

a+b=55,a-b=1

a+b=11,a-b=5

So a=28, b=27

or a = 8, b = 3

2. If a and b are required to be integers, then negative numbers should also be considered, that is.

a=-28,b=-27

a=-28,b=27

a=28,b=-27

a=-8,b=-3

a=-8,b=3

a=8,b=-3

3. If there is no requirement for A and B, then there are countless solutions.

You have a rock bracket for this, right?

Does a flat liquid bright square minus b square?

Both of these data are unknown, and there are many possible jujube deficiencies.

55 = 5 * 11 is not a collapse oak has other approximate numbers.

a+b, a-b, one of which is equal to 5, and a 11 hypothesis (a+b), (a-b) are both positive.

and (next to a + b) = 11, equation 1

a-b) = 5 Equation 2

Equation 1 + Equation 2.

2a=16, a=8, bring in b=3

Suppose (a+b) and (a-b) are both negative.

(a +b)=-11, Equation 3

a-b) = -5 Equation 4

Equation 3 + Equation 4.

2a=16, a=8, bring in b=3

So when a=8, b=3 or a=-8, b=-3.

a=b+4a-b=4

a-b)^2=16

a^2-2ab+b^2=16

a^2+b^2=18

a+b)^2-2ab=18

a+b)^2=20

Then the silver A + B = 2 root number 5 or minus 2 root number 5

Because the feast of God a-b=4

Then a = 2 + root number 5 or 2- root number blind 5

b = root number 5-2 or -2 - root number 5