The question of Cu reaction with acid, can Cu react with hydrochloric acid

2cu+6hno3=2cu(no3)2+no2+no+3h2o

The method of the trim equation: This problem obviously needs to be matched with a valency change of 0, cu->cu(no3)2 cu rises by 2 (the valency of cu is 0, and the valency of cu in cu(no3)2 is +2).

Hno3-> N decreased by 1 (the valency of N in Hno3 was +5, and N in KnO2 was +4).

Hno3-> N decreases by 3 (the valency of N in Hno3 is +5, and N in N is +2).

Therefore, Cu(No3)2:No2:No is 2:1:1, and the valency change is 0So the other coefficients are added.

Hey, chemistry... It's already something I did 10 years ago. Some nouns are forgotten = =

As for adding a small amount of dilute sulfuric acid to the "copper sheet", there will be gas production, in fact, it means that after the reaction between copper and concentrated nitric acid, there is a surplus of "copper", nitric acid is gone, and others are generated, but there are always No3- ions in Cu(NO3)2 in the solution, and this ion is combined with the H+ ions in dilute sulfuric acid to form dilute nitric acid, and dilute nitric acid will also react with copper, so the above chemical reaction is produced, and 2 kinds of gases are generated.

I don't understand. Concentrated sulfuric acid is a nitrogenous n compound from H2SO3 and water, and copper together?

You're talking about concentrated nitric acid......-#

The reaction between iron and concentrated flow acid (heating) is trivalent iron, which has nothing to do with excess, and the reaction with dilute flow acid is divalent iron, because concentrated flow acid is also oxidizing, and the reaction between iron and concentrated nitric acid is basically the same as copper, and passivation is also a special chemical reaction on the surface of the object.

At the secondary level, we think of copper and concentrated hydrochloric acid.

is not reacting. But in fact, copper and dilute hydrochloric acid cannot react, but it can react with very concentrated hydrochloric acid. The reaction formula is:

2Cu 4HCl (concentrated) 2H[CuCl2] H2 The reason why this reaction can occur is that when the hydrochloric acid is very concentrated, it can produce a more stable complex.

2H[cuCl2], so it is reactive.

will react. The chemical equation for the reaction of Cu and dilute sulfuric acid is Cu+H2SO4=CuSO4+H2. Dilute sulfuric acid refers to an aqueous solution of sulfuric acid with a solute mass fraction of less than or equal to 70%.

Because the sulfuric acid molecules in dilute sulfuric acid have been completely ionized, dilute sulfuric acid does not have special chemical properties such as strong oxidation, water absorption, and dehydration (commonly known as carbonization, that is, strong corrosiveness) of concentrated sulfuric acid.

Copper (Cu) Huiyin cannot react with hydrochloric acid (HCl) mainly because of its high electrochemical potential, that is, it is more difficult to lose electrons than hydrogen ions (H+), therefore, it cannot be oxidized by H+ ions in HCl.

Copper hydroxide (Cu(OH)2) can react with hydrochloric acid in the following process:

Cu(OH)2 + 2HCl CuCl2 + 2H2O In this reaction, the H+ ions in HCl react with the OH- ions in copper hydroxide to form water (H2O), while the Cu2+ ions combine with Cl- ions to form copper chloride (CuCl2), thus completing the reaction.

It should be noted that copper hydroxide partially decomposes into copper ions and hydrogen-carrying oxygen ions (OH-) in the presence of copper hydroxide in water, so it is actually copper ions (Cu2+) that are actually reacting.

Answer: Cu (copper) is a metal hidden pants element, in the order of metal activity deficiency, Cu is located behind H, copper can not replace the hydrogen in the acid, and hydrochloric acid does not have strong oxidation, can not oxidize copper, so Cu and HCl can not react. Cu(OH) belongs to the alkali group, and the alkali can react with volcanic acid to form salt and water, so Cu(OH) can react with hydrochloric acid.

Several scenarios:

1. Heating and concentrated sulfuric acid react to produce copper sulfate, but sulfur dioxide is generated, polluting the environment, and it is not approved.

2. Considering the reaction between metal oxides and acids, Cu is burned in the air and then reacted with sulfuric acid. But the burning process can not be very sufficient, because of the internal copper.

3. The landlord's idea. Iron sulfate and copper are reacted to form ferrous sulfate and copper sulfate. But the product cannot be removed.

But it seems that what the landlord said seems to be similar to the reaction of silver sulfate and copper, although the product can be obtained, but how the silver sulfate came from is unknown, isn't it? Landlord? So this method is still not good.

4. Reaction with electrolytic cell, the anode is Cu, the solution is H2SO4 solution, and the cathode PT or graphite. Copper sulphate can be generated when energized.

To sum up, the fourth is the most environmentally friendly, the most effective, and the most difficult to think of.

If you don't understand, please ask. Thank you.

It should be said that copper cannot react with non-oxidizing acids, non-oxidizing acids mean that only hydrogen ions show oxidation, and acid ions do not show oxygen, so oxidizing acids are of course mainly acid ions showing oxidation, such as concentrated sulfuric acid, nitric acid, chloric acid (HCO3). Copper sulfate will be formed by coheating copper with concentrated sulfuric acid, and copper sulfate can also be formed by reacting copper oxide with dilute sulfuric acid.

Cu + 2H2SO4 (concentrated) condition heating CuSO4 + SO2 (gas symbol) + 2H2O

cuo+h2so4=cuso4+h2o

Reacts with concentrated sulfuric acid under heated conditions.

There are others, such as reacting copper with nitric acid and then adding sulfate ions. Cu+O2 is heated to generate CuO, and CuO+H2SO4 is generated to CuSo4

.Copper is oxidized to become copper oxide, copper oxide, and sulfuric acid.

Cu is oxygenated, heated, and Cuo is generated, which is a black solid. Add sulfuric acid to produce CuSO4!

Chemical formula CuSO4, white powder, solubility in water at 25 g, commonly known as bile alum, copper alum, or blue alum, relative density is.

**Partial spring water.

Legend has it that during the Three Kingdoms, Zhuge Liang led his troops to a certain place and found a "dumb spring". After drinking, the mild ones are dumb, and the severe ones are poisoned and die. The latter has been shown to have copper sulphate among them.

How did it come about???

There are all kinds of ions, mixtures...

Cu ions, and sulfate ions, , when they collide together, naturally produce CuSO4, why ??? Because they are stable.

People who have studied chemistry should know, but in nature,,, CuSO4 is unstable, they are easy to absorb water, and CuSO4·5H2O exists in nature, also called bile alum or blue alum.

It does not have to be a direct reaction, and it can also be obtained by substitution.

The reaction flow is:

2cu + O2 = Heating = 2Cuo

cuo+h2so4=cuso4+h20

Or it can be heated with concentrated sulfuric acid and copper:

Cu + 2H2SO4 = Heating = CuSO4 + SO2 (gas) + H20

Obvious displacement reaction! No need to ignite.

Hello, hydrochloric acid should be strong enough.

At the secondary level, we consider copper and concentrated hydrochloric acid to be non-reactive. But in fact, copper and dilute hydrochloric acid cannot react, but it can react with very concentrated hydrochloric acid. The reaction formula is:

2Cu 4HCl (concentrated) 2H[CuCl2] H2 This reaction can occur because when the hydrochloric acid is very concentrated, it can produce a more stable complex 2H[CuCl2], so it can be reacted.

Copper is an inactive metal.

This reaction is very difficult to carry out.

Conventional hydrogen-generating reactions are not carried out.

If you don't understand, please ask!

The essence of this reaction is that first Cu reacts with oxygen to form copper oxide, and then copper oxide reacts with hydrochloric acid to obtain this equation.

cu2h2so4=cuso4

so2|2h2o

The first question, no, the second question, less than 2mol

Because concentrated sulfuric acid does not react after thinning, the third question, 2mol

It is passivated with concentrated sulfuric acid or nitric acid!

Sufficient nitric acid is followed to produce nitric oxide, and nitrogen dioxide is produced in excess!

I want extra points!

Cu reacts with concentrated sulfuric acid to form copper sulfate, water, and sulfur dioxide. The main reason is that the concentrated sulfuric acid oxidizes the Cu.

Cu does not react with dilute sulfuric acid because the metal activity order of Cu is placed after H.

1. No, the concentrated sulfuric acid becomes thinner, and it cannot react.

2. The sulfur dioxide produced must be less than 1mol, because copper cannot react with dilute sulfuric acid, so when the sulfuric acid is thinned, the reaction will stop, so that the sulfuric acid participating in the reaction is less than 2mol, and the sulfur dioxide must be less than 1mol.

3. Because there is a reaction between 1molCu and 2molCu, only 1molH2SO4 is reduced as an oxidant to form SO2, and 1molH2SO4 reacts to form CuSO4 as an acid, so 2molH2SO4 is reduced to 2molSO2 to be generated.

Satisfied with the adoption of Ha, I don't understand that you can continue to ask.

o(≧v)o~~

Upstairs wrong. fe or.

mg and concentrated sulfuric acid or.

concentrated nitric acid reaction will be passivated.

Cu is formed by reaction with concentrated sulfuric acid.

Copper sulphate. water and.

Sulphur dioxide...Dilute sulfuric acid.

Heating. Sulfur monoxide is generated.

and dilute nitric acid. Produces nitric oxide.

Thick generation. Nitrogen dioxide.

No, there is too much copper.

According to this reaction, Cu + 2H2SO4 = Heating = CuSo4 + So2 + 2H2O can be known.

1molCu corresponds to 2molH2SO4

Now n(cu) = 2n(h2so4).

That is to say, n(cu) is now consumed 4 times that of n(h2so4), so there is an excess of copper.

Even if it's n(h2so4).

2n(cu), also not fully reactive. Because as the reaction progresses, concentrated sulfuric acid becomes dilute sulfuric acid, and dilute sulfuric acid does not react with copper.

cu 2h2so4=cuso4 so2|2h2o, the first question, can't, the second question, less than 2mol, because the concentrated sulfuric acid does not react after thinning, the third question, 2mol