X 1 The sum of the coefficients of the even terms in Eq. 10

Method 1, the sum is C10

0+c102+c10

4+c106+c108+c10

Method 2: Substituting x=1, then the sum of the coefficients of each term is 0, indicating that the coefficients of odd terms and even terms are equal and inverse to each other.

Substituting x=-1, then the sum of the absolute values of the odd and even coefficients is 2 10=1024, so the coefficient of the even term is 1024 2=512

Method 3: The coefficient of the even term has x, x, x 4, x 6, x 8, x 10x is: (-1) 10=1

The coefficient of x is: c10

The coefficient of x 4 is: c

The coefficient of x 6 is: c

The coefficient of x 8 is: c

The coefficient of x 10 is: 1

The above adds up so it's 512

Either way, it means that the answer you provided is incorrect, or the question is copied in error.

Hope this helps

x-1)11 formula.

For. tr+1=cr

1）r?x11-r, so that 11-r is even, and r is odd, so r=1,3,5,7,9,11, and the sum of the coefficients of all even terms of x in the open formula is -ccc

ccc-210=-1024, so the answer is: -1024

The sum of the coefficients of all terms of even power = [(1-1) 11 + 1-1) 11] 2=-1024

Summary. Firstly, the general term formula of the binomial is used to find the general term, so that the exponent of x is 0 to obtain the constant term. Let the binomial where x be 1 to find the sum of the coefficients and solve the problem

x+2 x-1) 4 where the sum of the coefficients except the constant term is.

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Firstly, the binomial general term public observation megastate formula is used to find the general term guess rent, and the exponent of x is 0 to obtain the constant term. Let the binomial where x be 1 to find the sum of the coefficients and the source of defeat to solve the problem

Calculated as a result, his coefficient sum is 81

When x = 1, (2-1) 10 = 1 This is the sum of the coefficients of the even power term and the coefficients of the + odd power terms.

When x = 1, (return-2-1) 10 = 3 10 This is the coefficient of the even power term and the coefficient of the odd power term and the band.

So 1 - 3 10 = 2 * the coefficient of the odd power term and the coefficient.

So the sum of the odd power terms is equal to (1-3 10) 2 = 29524

(x-2) to the power of 10 = a0 + 1x to the power of 1 + .A10x to the 10th power.

Let x=1(-1) to the power of 10 = a0 + a1 + .A10. a0+a1+..a10=1

The sum of the coefficients of all terms is equal to = 1

The coefficient of the primary term of the x-1) equation is (-2).

x-1)²=x^2-2x+1

The sum of the coefficients of all terms of even power = [(1-1) 11 + 1-1) 11] 2=-1024

Solution: Original formula = a0(x) 11 +a1(x) 10+a2(x) 9+a3(x) 8+...a9(x)2+a10(x) -1

The maximum number of times is 11 times, so it can be written as the general formula above. (The last constant term can be obtained using x=0).

So find the value of a1 + a3 + a5 + a7 + a9.

Let x=1 have 0=a0+a1+a2+a3+a4+a5+a6+a7+a8+a9+a10-1

Let x=-1 have (-2) 11=-a0+a1-a2+a3-a4+a5-a6+a7-a8+a9-a10-1

The sum of the two formulas has -2 !1=2(a1+a3+a5+a7+a9)-2

So: a1+a3+a5+a7+a9=-2 10+1