Simple Clock Olympiad Questions, Olympiad Clock Problem Formulas Urgently Needed Online, etc

The first method: simple, the minute hand is divided into 6 degrees forward, and the hour hand is divided into degrees, at 7 o'clock the hour hand and the minute hand clamp 30 7 210 is set to x minutes then the column formula 210 + gets 20 that is 7 o'clock 20. The second problem is that the clock hand at 8 o'clock has traveled 30 8 240 degrees, which is set to x minutes, and the column formula 240+ gives x that is not divisible and is an infinite loop 81.

Because the second hand does not have half a second (unless there is a special instrument), the solution is wrong! It can be set to x hours y seconds, x hours, the hour hand has gone 30x degrees (30 degrees per hour) can also be arranged 30x+ x with 8 11 in turn, from 12 o'clock the minute hand is faster than the hour hand, the formula becomes 6y- (30x+. There is still no integer solution, that can only mean that the topic is not demanding, then you write 8:21:49 or 50 seconds, maybe the gears are crooked!

The second method: at 7:20, the minute hand lags behind the hour hand one, and these are according to the clockwise degree from the minute hand to the hour hand.

Clearer conditions are needed.

1 second: the second hand rotates 6 degrees; Degree of rotation of the minute hand; The hour hand rotates 1 120 degrees for 1 minute: the second hand rotates 360 degrees; The minute hand is rotated 6 degrees; Rotation of the hour hand.

At 7:20, the minute hand lags behind the hour hand.

These are according to the clockwise degree from minute to hour.

Clearer conditions are needed.

1 second: the second hand rotates 6 degrees; Degree of rotation of the minute hand; The hour hand is rotated 1 120 degrees.

1 minute: 360 degrees rotation of the second hand; The minute hand is rotated 6 degrees; Rotation of the hour hand.

In grid minutes, the speed of the minute hand is 1 square minute, and the speed of the hour hand is 5 square hours = 1 12 square minutes.

In degrees, the speed of the minute hand is 360° 60=6° minutes, and the speed of the hour hand is 6*1 12=minutes.

The number of minutes required for the two needles to coincide = the number of squares between the original two needles (1-1 12) or = the number of degrees between the original two needles (6°).

The number of minutes required for two needles to form a straight line (excluding overlapping) = (the number of squares separated by the original two needles is 30) (1-1 12).

or = (the original two pins are separated by 180°) (6°

The number of minutes required for two needles to be at right angles = (15 squares apart) (1-1 12) or = (90° between the two needles) (6°).

Can you give more points? Thank you.

The speed of the hour hand is 30° h, the speed of the minute hand is 360° h, and the time of going out (that is, the time it takes for the hour hand and the minute hand to rotate) is x hours, then the angle of the hour hand rotation is 30° h times x = 30x degrees, and the minute hand has made more than two revolutions and falls in front of the hour hand, then the angle of timing rotation is 360° h multiplied by (3-x) = 360x (3-x).

The angle between the two remains the same... That is, 30x = 360x (3-x) solution gives x = hours.

The minute hand rotates 360 60 = 6 degrees per minute.

The hour hand rotates 360 (12 60) = degrees per minute.

At 7 o'clock, the minute hand lags behind the hour hand

7 12 360 = 210 degrees.

When the two hands are in a straight line, the minute hand is 180 degrees behind the hour hand.

Duration: (210-180) (minutes.)

When the two hands coincide, the minute hand catches up with the hour hand, and the time is 210 (minutes.

It took 420 11-60 11 = 360 11 minutes to write the homework.

The hour hand travels 1 12 times per hour.

The minute hand makes 1 revolution every hour.

At the time of the operation, the minute hand catches up with the hour hand exactly half a turn.

It's time-sensitive. Half of a lap (1/2 per hour) Speed difference: 1 lap per hour - 1/1/1 (1 - 1 12).

6 11 hours.

Minute.

The time when the hour and minute hands on the clock face are exactly in a straight line is about 7:05.

First overlapping of the hands: 7:38 a.m.;

Second coincidence: 8:44 a.m.;

And so on. Wang Hua's time to do homework can be subtracted to get the answer.

This is a chase problem, the difference is 180°, the minute speed is 6° minutes, and the clock minutes.

The job time is 180 (

Let's say a 24-hour clock. Set x hours later and then be on time.

24h=86400s

x*20s=86400s

x=4320h

4320h 24h = 180 days.

So August 28 at 12 noon will be accurate again.

If it's a 12-hour clock, it's 90 days, which is accurate on May 30.

Fuck, it's a hard fight.

180 days later, at twelve o'clock in the afternoon.

According to the title, the hour hand lags behind the minute hand during class.

The position of the two pins is reversed, then the two pins rotate a total of 360° per minute, and the minute hand rotates: 360 60 = 6°

Hour hand turn: 360 12 60=

The two needles rotate in total: 6+

The two needles rotate a total of 360°, and it takes :360 (minutes can only be found for 720 13 minutes.)

I can't be sure what time classes start.

The hour hand reaches the position of the minute hand, and the minute hand reaches the position of the hour hand and goes one circle, the minute hand goes 6 degrees per minute, and the hour hand moves every minute.

Then the time is 360 (6+ minutes.)

Between 8:47 and 8:48 a.m., the class starts at about 55 minutes and 24 seconds. 、