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Anonymous users2024-02-15It's okay, I'll do it for you.
a^2+b^2)^2-2a^2b^2-a^2-b^2+2a^2b^2-6=0
a 2+b 2) 2-(a 2+b 2)-6=0, let (a 2+b 2) be x
So the original test = x 2 - x - 6 = 0
x+2)(x-3)=0
x= -2 or x=3
So a 2 + b 2 = -2 or 3
and a 2+b 2 > 0
So a 2+b = 3
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Anonymous users2024-02-14a 4+b 4-a 2-b 2+2a 2 b 2-6=0a 4+b 4+2a 2 b 2-a 2-b 2-6=0a 2+b 2) 2-( a 2+b 2)-6=0a 2+b 2-3)( a 2+b 2+2)=0 There are two solutions 3,-2
Because a 2 + b 2 is equal to 0
So the only meaningful solution to the above equation is a 2 + b 2 = 3
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Anonymous users2024-02-13Because a 2 + b 2 = 4
So (a+b) 2-2ab=4
Again, the socks are stuffy because a+b=4
So 4 2-2ab=4
2ab=12
So it is good to have ab=6
The value of the bend swam to ab is 6
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Anonymous users2024-02-12(a+b) 2=4, (a-b) 2=6, a +2ab+b =4 a -2ab +b =6 +.
2(a²+b²)=4+6
So a +b = 5
2ab=4-(a²+b²)
So ab=-1 2
Find the values of a2+b2 and ab.
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Anonymous users2024-02-11It's good to make use of the squared difference formula, why subtract? (a+b) 2-(a-b) 2=[a+b+a-b][a+b-a+b]=2a*2b=4ab=-2, the squared difference formula will be more efficient than subtraction.
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Anonymous users2024-02-10Solution: Because a+b=4 (a+b) 2=16 and because a 2+b 2=4 ab=[(a+b) 2-(a 2+b 2)] 2=6
Then a 2b 2=(ab) 2=36
a-b) 2=a 2-2ab+b 2=4-12=-8 (haha this is an impossible event, please ask if the question is wrong).
It would be impossible for a+b and a 2+b 2 to equal 4 at the same time.
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Anonymous users2024-02-09Answer: The main use of the sum difference squared formula:
a-b)²=a²-2ab+b²
a+b)²=a²+2ab+b²
a+b=4, square both sides get:
a+b)²=4²
a²+2ab+b²=16
A + b = 4 substituting into the above equation to obtain:
4+2ab=16
ab = 6 so: a b = 36
a-b)²=a²-2ab+b²=4-2×6=-8(a-b)²=-8
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Anonymous users2024-02-08It is obtained by a + b = 4, b = 4-a, and substituted a + b = 4a + (4-a) = 4
Open the parentheses, move items, merge similar items, get.
2a²-8a+12=0
That is: a -4a + 6 = 0
Because, discriminant = -8 0
Therefore, there is no solution to the equation.
Therefore, there is no real solution that satisfies the question.
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Anonymous users2024-02-07Big brother, it's best to put a bracket when you ask a question.
a^4+b^4)/(a^2*b^2)=a^2/b^2+b^2/a^2=(a/b)^2+(b/a)^2=2^2+(1/2)^2=17/4
Hello! This question is a question to investigate the basic properties of inequalities, and the answer is as follows, 1 n 2+1 m 2=(1 n) 2+(1 m) 2>=2*(1 n)*(1 m), so 1 mn<=((1 n) 2+(1 m) 2) 2=(a 2+b 2) (2*a 2*b 2), multiply 1 2mn by 1 2 on the left and right, and get 1 2mn<=(a 2+b 2) (4*a 2*b 2), so the maximum value of 1 2mn is (a 2+b 2) (4*a 2*b 2), I wish you good progress!
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