System of equations thirds m quarters n 1 half m thirds n 7 15

There's an unknown and two equations that can be solved, so why are there two equations below? Are there two topics?

one-thirds m - quarters n = -1;Half m + third n = 74m - 3n = -12 3m - 2n = 42

m=150 n=204

It is known from one that 4m-3n=-12

Known by 2: 3m-2n=42

From 1 and 2, we can see that m-n=-54

Therefore, m=150;n=204

Is the condition under the question something else? Is it (m+n) or m+n].

m Split state 2 + n 3 = 13

m/3+n/4=3

The above two equations are divided to obtain the following system of equations.

8m+6n=72

9m+6n=234

Untie the fiber royal cherry blossom side to destroy the cong Cheng group to get.

m=162n=-204

,, n=(13-m)*3Substituting n = (13-m) * 3 = 39-3m into 2 formula m 3-n 4 = 3 gives m 3-(39-3m) 4 = 3Multiply both sides by 12 at the same time to get 4m-117+9m=36, and the solution is m=153 13, so n=48 13

m-n=3 multiplied by 12.

4m-3n=36..1

2/2 m - 3/3 n = 13 multiplied by 6.

3m-2n=78..2

Multiply Eq. 1 by 2 and subtract Eq. 2 by 3.

m=162, then n=204

m+n)/3-(n-m)/4=2

Multiply both sides by 124m+4n-3n+3m=24

7m+n=24

n=24-7m

Substituting 4m+n 3=8

4m+(24-7m)/3=8

Multiply both sides by 312m+24-7m=24

5m=0m=0

n=24-7m=24

m of 2 + n of 3 = 13

3m+2n=78

9m+6n=234

m/3 - n/4 = 3

4m-3n=36

8m-6n=72

Add the two formulas. 9m+8m=234+72

17m=306

m=183*18+2n=78

2n=24n=12