Grade 6 solves problems and is eager for answers QAQ

The first question should be: 270 tons.

The second question should be: 28 blocks.

The third question should be: 16 people.

The fourth question should be: A total of 546 trees have been planted.

The fifth question should be: 3/2 packets.

Actually, yes. It's a scumbag under it.,But at least the first year of junior high school to solve the sixth-grade questions is still OK.,It's not guaranteed to be all right.,If you're really in a hurry to do your homework, copy it.,If it's not recommended, wait for other science tyrants to tell you the accurate answer.,Thank you for understanding.

1.420x sixths = 360 (tons) 360x three-quarters = 270 (tons) A: 270 tons of water in March.

2.206x27/103 = 54 (block) 54x14/27 = 28 (block) Answer: There are 28 finger bones in the human body.

3.42x1/3 = 14 (name) 14x8/7 = 16 (name) Answer: 16 students participated in the making of greeting cards.

4.260x3/5 + 260x3/2 = 156 + 390 = 546 (trees) 546 260 A: They planted a total of 546 trees and completed the tree planting task.

5.24x1x3/48 = 3/2 (pack) Answer: Yangyang takes 3/2 sachet per day.

Are you sure it's a 6th grade question? How easy is it that the landlord can't write? It's so simple.

a).In a tree planting activity, 6th grade students planted 260 trees, 30% more than 5th grade, how many trees were planted in 5th and 6th grades?

A total of 442 trees were planted in grades 5 and 6.

ii).1) There are 120 girls in the sixth grade of a school, which is exactly 120% of the number of boys, how many boys are there?

2）.There are 120 girls in the sixth grade of a school, and the number of boys is 20% less than the number of girls.

3）.There are 120 girls in the sixth grade of a school, 20% more than the number of boys, how many boys are there?

1.Solution: Set up a total of x trees in the fifth grade.

x+30%x=260

1+30%）x=260

130%x=260

130%x÷130%=260÷130%

x=200200+260=460 (trees).

1.Solution: Let's say there are x number of boys.

120%x=120

120%x÷120%=120÷120%

x=1002.120-120x20%=120-24=96 (person)3Solution: Let's say there are x number of boys.

120%x=120

120%x÷120%=120÷120%

x=100 I'm tired!!

1 hour = 3600 seconds. The diameter of the water pipe is 2 dm = m, radius = m.

Calculate how many cubic meters in 1 hour - 500 meters of water in the water pipe = how many cubic meters of water is pumped to the water tower.

Calculation of total pumped volume: cubic meters;

Calculate the water in the pipe for 500 meters: cubic meters;

Calculate the amount of water actually pumped into the tower: cubic meters.

Set: The speed of the fast train is x, and the speed of the slow train is y

x +y=960/6

10x=960

Solution x gets 96, and y gets 64

Knowing the speed of the slow train, after that, the trouble LZ is forgotten. Mathematics is do-it-yourself.

Question 1: The cross-sectional area of the water pipe is = (square meters, 1 hour = 3600s, the length of the water flow = 3600s * 2m s = 7200m total volume = s * length = 7200 * cubic meters = cubic meters.

Question 2: The speed of the fast train s1=960 (12-5+3)=96km h, so there is a slow train speed s2= (11-5)=64km h, so the total time of the slow train = 960 s2=15h

Therefore, the slow train arrives at Station A at 8 p.m., that is, 8 p.m.

1 hour = 3600 seconds. The diameter of the water pipe is 2 dm = m, radius = m. Cubic metre; Cubic metre; Cubic metre;

Set: The speed of the fast train is x, and the speed of the slow train is y

x +y=960/6

10x=960

Solution x gets 96, and y gets 64

1 That's not all.

2-5 hours.

The express train traveled from A to B for a total of 10 hours and traveled 960 meters, so the speed of the express train is 960 10 = 96km h The two cars depart at 5 o'clock and meet at 11 o'clock, a total of 6 hours. The fast train went 96 6 = 576 km, so the slow train went 960-576 = 384 km. And because the slow train traveled for 6 hours, its speed was 384 6 = 64km s.

After 10 hours of travel, the slow train is 10 64 = 640 km, and there are 960-640 = 320 km left, so it will take 320 64 = 5 hours to reach station A.

Teach you a way to solve the problem: first look at the unit "1" known is unknown, known to use multiplication and not known to use division, look at the unit 1 after the more or less use 1 + more percentage, less use 1 - less percentage.

1. There are two baskets of apples A and B, their weight ratio is 8:7, if you take out 3 kg from basket A and put it in basket B, it means that the difference between the two baskets is 6 kg, then it is a difference, that is, A has 48 kg, and B has 42 kg.

2. There are two bags of rice, bag A is 10 kg, if you pour 1/3 from bag B into bag A, the two bags of rice are the same weight, which means that there are 10 + 1 3 bags in A, and 2 3 bags are left in bag B, and the two bags of rice are the same weight at this time, that is, B has 30 kg.

1.There are two baskets of apples A and B, their weight ratio is 8:7, if A has 8 parts, then B has 7 parts, if you take out half of 3 kg from A basket and put it in B, the weight of the two baskets is equal, so 1 part = 6kg, and the two baskets of apples originally weighed 48kg and 42kg kg respectively.

2.There are two bags of rice, bag A is 10 kg, if you pour 1/3 from bag B into bag A, at this time bag A = 10 + 1 3 bag B, bag B is left 2 3, at this time the two bags of rice are the same weight, get 1 3 bag B = 10, bag B originally had 30 kg of rice?

can be solved with a univariate equation).

69 (48%-25%) = 300 (km) ......The total length is 38*85%=yuan).

485 1-3%) = 500 (pcs) ......The total number is 500*3%=15 (pcs) ......Unqualified.

69/（48%-25%）=300km

38* yuan. 485 97 percent * 3 percent = 15 yuan.

(1) If the total length is X, then A, the two teams will repair together. x=300

3 Total number of parts: 485 ( Nonconforming: 500.)

(1) Solution: Team B repaired 48%-25%=23%69 23%=300 (km) of the total length

2) 38 85% = yuan).

3) Qualified accounted for 97% of the total

The total number of parts is: 485).

Unqualified are: 500-485 = 15 (pcs).

1.Overall length = 69 (48%-25%) = 300 meters.

2.Current price = 38 85% = yuan.

3.Unqualified = 485 (1-3%) 3% = 15.

2.The original area is 500, the length is 50, and the original width is 10.

Knowing that the length remains the same, the width becomes 12, so that the area is 50 times 12 = 600, which is 100 more than the original area of 500

Therefore: 100 divided by 500 = 20%.

Therefore, the area of the expanded swimming pool has increased by 20% compared to the original

3.Divide the number of participants by the corresponding score to equal the total number of grade 6 students, so the total number of grade 6 students is 81 divided by 15 times 2 equals 270

Hope it can help you to adopt.

(1) The current price is 10% off, indicating that 10% of the original price is equal to 1200, so the original price is equal to 12000

2) The original area is equal to 500, so the original width is equal to 10 meters, so the width after expansion is 22 meters, so the area after expansion is 50 * 22 = 1100 square meters, so after the expansion has increased by 1100-500 = 600 square meters, so the expansion has increased by 120 percent compared with the original

3) Let the number of students in the whole grade be x, so x=300

1.Set to the original price x, the current price, to get x=12000

2.Conditional 500 divided by 50 = 10, 10 + 12 = 22, 22 * 50 = 1100, 1100-500 = 600

It can also be 50*12=600

3.Set to x, one person cannot participate in these two competitions at the same time), x=300

The number of A is 20% less than the number of B. If a "B" is a unit of 1, then A is 1--20%=, and the number B is several percent more than the number of A? is 1 in units of "A", so: (

60 kg is a percentage of 150 kg: 60 150 100% = 40%.

Let B be x and A be (1-20%)x=

B is more than A (60kg 150kg = 2 5 = 40%)

Solution: Let the distance between the two cities be x kilometers, according to the title:

240 (x 10)=(x-240) (x 8) gives x=540 km.