How to find the amount of electron transferred substances in high chemistry

Updated on educate 2024-02-08
16 answers
  1. Anonymous users2024-02-05

    It can be determined by the change in valency and the amount of substances participating in the reaction.

  2. Anonymous users2024-02-04

    First of all, we need to know that electrons are negatively charged, and when we get electrons, the valency will decrease (equivalent to adding a negative number).

    On the contrary, the valency increases, and electrons are lost.

    The number of valency changes is the number of electrons gained and lost.

    For example: h2+cuo=cu+h2o

    Elemental 0 valence, h2 from 0 valence hydrogen to +1 valence hydrogen, each atom loses 1 electron, a hydrogen molecule has 2 hydrogen atoms, so it loses 2 electrons.

    The valence of the oxygen-resistant Li Yan element in copper oxide is Changyin-2 before and after the reaction, and it does not change, so it is not considered, only copper is considered, +2 valence before the reaction, and the reaction obtains elemental copper, 0 valence, the valency is reduced by 2, and 2 electrons are obtained.

    This example ok no?

  3. Anonymous users2024-02-03

    This is the number of electrons transferred in a chemical equation. 6 electrons are incorrect and are two electrons. The main reason is that only the -1 valence oxygen atom in sodium peroxide is involved in the redox reaction.

    Among the reactants, the other oxygen atoms in sodium carbonate are converted from the oxygen atoms in carbon dioxide.

  4. Anonymous users2024-02-02

    There are 4 O's in 2na co, which are from co

    SoThere are a total of 4 O's with constant valence. Only 2O's are disproportionated to 2na co, which is just 2 electrons transferred

  5. Anonymous users2024-02-01

    Incorrect. There are two types of oxygen in Na2CO3, one is from carbon dioxide and the other is from sodium peroxide. The oxygen in carbon dioxide is negative divalent, and there is no transfer of electron pairs to sodium carbonate. Only sodium peroxide has the transfer of electron pairs in the reaction.

  6. Anonymous users2024-01-31

    Figure 1 is correct, because the oxygen in the carbonate is not only from the peroxide, but also from the carbon dioxide itself, and the oxygen from the peroxide is oxidized to produce oxygen, the oxygen in the element, and at the same time, some of it is reduced to become the oxygen in the carbonate.

  7. Anonymous users2024-01-30

    Taking 2HCl+Zn=ZnCl2+H2 as an example, it is known that 1mol of zinc participates in the reaction, and the zinc element is converted into zinc ions and loses two electrons, then the number of electrons transferred is 1mol multiplied by 2=2mol, that is, the number of electrons transferred by a substance multiplied by the amount of a substance.

  8. Anonymous users2024-01-29

    28gn2 is one mole n from +4 to 0 valence decrease ** shift) four electrons, 1molN2 has 2moln so transfer 8mol electrons.

    Na2O2 is 1mol, and O is reduced from -1 to 0 valence, and there is only 1mol, so 1mol of electrons is transferred.

    The transfer of electrons is only based on the increase or decrease in price multiplied by mol

  9. Anonymous users2024-01-28

    pbs+4h2o2=pbso4+4h2o

    What is the amount of electrons transferred when 1molH2O2 participates in the reaction, and the valency of O in hydrogen peroxide is -1, and the valency of O becomes -2 when it comes to water, so it decreases by 1.

    1 part hydrogen peroxide contains 2 parts O, so 1 part hydrogen peroxide reduces the 2 valence and transfers 2 electrons, so the amount of electrons transferred when 1molH2O2 participates in the reaction is 2mol

  10. Anonymous users2024-01-27

    H2O2 to H2O are 4 O atoms and your description is correct here, but you will find that there are only 2 mol of electrons in 1mol of H2O2.

    Moreover, PBSO4 also has 4 O atoms. It is also -2 valence. So there are a total of 8 o atoms transferring electrons.

    For the equation, PBS+4H2O2=PBSO4+4H2O

    1mol 1mol

    o There is an electronic transfer.

  11. Anonymous users2024-01-26

    pbs+4h2o2=pbso4+4h2o

    Note: The question is what is the amount of the species that transfer electrons when 1molH2O2 participates in the reaction?

    The valency of O in hydrogen peroxide is -1 to the valency of O in water and sulfuric acid is -2, so the valence is reduced by 1, and 1molH2O2 has 2mol of oxygen atoms, which is exactly 2mol of electrons.

  12. Anonymous users2024-01-25

    He has 2 oxygen atoms in each of them, each of which transfers 1mol, and 1mol has 2 oxygen atoms in it, so 2mol...Electronic Transfer.

  13. Anonymous users2024-01-24

    If the mnO2 responds completely. Loss of 2mol electrons according to 1mol mno2.

    Transfer electrons n=

  14. Anonymous users2024-01-23

    According to the reaction equation analysis:

    Total number of electrons transferred Total number of electrons gained Total number of electrons lost Number of atoms of the element that are converted The amount of valence of a single atom of the valence element.

    The amount of electron transferred matter The total number of electrons transferred is the amount of substance that is completely reacted.

    Ratio of the number of particles The ratio of the amount of matter of the particles.

    MnO2 + 4HCl (concentrated) MnCl2 + Cl2 + 2H2O

    mn: +4 +2 change 2 (decrease-get), 1 mn (+4) in the reaction becomes mn (+2), the total number of electron transfers is 1 2e-;

    Cl: -1 0 Change 1 (elevated - lost), 2 Cl-(-1) in the reaction become Cl(0), and 2 Cl-(-1) do not have valence (MnCl2), and the total number of electron transfers is 2 E-

    So if 1mol mno2 (molar mass 87g mol) is completely reacted, the total number of transferred electrons (the amount of the substance) (2E-) 1mol 2mol(E-).

    MnO2 + 4HCl(concentrated) MnCl2 + Cl2 + 2H2O transfer electron number.

    87g 2mol

    78g xx= 2mol×78g÷87g=

  15. Anonymous users2024-01-22

    Just look closely at the valency change of the elements in the equation.

    Find the total number of increases or decreases in valence that is the number of electrons transferred.

    Add this item to the end of the equation and then calculate the proportion with the relevant substance column, such as mno2 for the laboratory

    and concentrated hydrochloric acid to make Cl2

    The reaction is known to have shifted in the reaction.

    electrons, find the volume of Cl2 produced under standard conditions.

    4hclmno2==δ==mncl2

    cl2↑2h2o

    Electronic Transfer. This figure is derived from the total number of valence changes.

    mol...v...v=

  16. Anonymous users2024-01-21

    Write the chemical equation, indicate the rise and fall of valence, and then mark the number of transferred electrons, so that the ratio of the number of transferred electrons to the amount of a substance of a certain substance is obtained, and the amount of the substance that transfers electrons can be calculated according to the mass of a substance participating in the reaction or the amount of substance known in the problem.

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