PHP determines if the first element in two arrays is identical

function assoc_unique($arr, $key) {

tmp_arr = array();

foreach($arr as $k => $v) {

if(in_array($v[$key], tmp_arr))

unset($arr[$k]);

else {

tmp_arr = $v[$key];

sort($arr);

return $arr;

aa = array(

array('id' => 123, 'name' => 'Zhang San'),array('id' => 123, 'name' => 'Li Si'),array('id' => 124, 'name' => 'Wang V'),array('id' => 125, 'name' => 'Zhao Liu'),array('id' => 126, 'name' => 'Zhao Liu')

key = 'name';

assoc_unique(&$aa, $key);

print_r($aa);

This is array deduplication** Don't know what you mean.

What kind of results do you want, post it directly. I can't understand your language.

$arr1=array(1,2,3,4,5,6,7,8,9,1,2,3,4,5);Set the array to be judged.

num1 = count($arr1);the number of the array to be extracted$arr2 = array unique($arr 1); Merge the same elements.

num2 = count($arr2);Extract the number of the merged array if($num 1>$num 2) to determine the size else

Determine if array intersect (array1, array2) is an empty array.

Determine if array intersect (array1, array2) is an empty array.

Loop the array $a you want to count, put the value you want to count into another array $b, and add 1 if there is this value in $b

First of all, I saw that the description in this problem is "how to remove the same element in two arrays", although the person wrote a lot of it, and actually used array unique(), from the analysis to the demo given, it has been solving how to remove "duplicate" elements in "one" array. Sweat! The answer to the question is not accepted.

Here, a brief analysis of the true intentions of the questioner is divided into the following two situations:

1.Now that we have 2 one-dimensional arrays, $arr 1 and $arr2, we now want to remove the element in $arr 1 that exists in $arr 2.

Solution: Use the array diff to return values that are in array1 but not in array2 and any other parameter array, as follows:

arr1 = array(1, 2, 3, 4);

arr2 = array(2, 4);

This sentence is sufficient.

arr1 = array_diff($arr1,$arr2);

var_dump($arr1);

2.First of all, let me state that I read the answer given by the great god of lt318025, and his thinking is very active, and he has divided into 2 situations.

Now there are 2 one-dimensional arrays, $a and $b, i.e. delete the element that exists in $b in $a, remove the element that exists in $a in $b, and merge back after the group.

However, the php version used by LT318025 is too high, and the demo given fails to run under the low version PHP, so here's a correction:

a=array(1,2,3);

b=array(2,3,4);

Get an array of elements that exist in $a but not in $b.

c=array_diff($a,$b);

Here we simply find the elements that are in $a but not in $b.

var_dump($c);

Get the union of an array of elements that exist in $a but not in $b and an array of elements that exist in $b but not in $a.

d=array_merge(array_diff($a,$b),array_diff($b,$a));

The elements that exist in both $a and $b are completely eliminated here.

var_dump($d);

Exactly which situation is up to the questioner's needs.

$a=array("First"=>12,"Second"=>23,34,45);

b=array("First"=>11,"Second"=>22,33,45);

foreach ($a as $key=>$v1) }print_r($a);

print_r($b);

"How to determine which is the first element of the array is the execution of the statement"", "If it's the first element of the array".

Thus describing the absence of a subject, 'judging is the array' who is the first and who is compared to the first?

Suppose the question is intended to be the first comparison between a variable $n and an array. PHP arrays are also a special data structure, and there are two cases of just saying 'first element'.

a=array ( 0] => 10 [1] => 6 [2] => 8 ……

Written 1if($n===current($a)) is the first element of the array internal pointer sequence.

Spellwise 2if($n===$a[0]) is the first element of the array's key intro.

foreach($arr as $key => $value) $arr data is replicated to $v in a loop

Array sorting: result: array

0 => int 1

1 => int 2

2 => int 3

3 => int 5

4 => int 6

For the time being, think of your first array as $a and the second as $b, which can be done with PHP's foreach loop.

b) else

Get the typeid array to compare and the title array of the drug assignments.

tid = array();

title = array();

foreach ($typeid as $k =>v) starts pointing to additive calculations.

foreach ($arr as $k =>v)

2 foreach, compare, if the same put into a new array.

Use array diff

print_r(array_diff($a,$b));

Result: Outputs the first value of two arrays that are different.

if(array_diff($a,$b) |array_diff($b,$a))else

I'm a little dizzy, I don't know what you want to express, can you get on**.