Rush to death and ask for an answer in an hour. Lower grade 5 math problems

One: 3-3 times the meter multiplied by 1/3 = the meter.

Two: 1/4 completed in the first half 1/4 plus 1/6 in the middle is equal to 5/12 5/12 completed in the second half 3 add up = 13/12 is greater than 1 So it can be completed.

Three: Suppose the distance is 1The speed of the express train is 1/24.

The slow speed is 1/28. After 10 hours of driving, the two buses drove together (1/24 plus 1/28) multiplied by 10 and that equals 65/84 and 19/84 remaining.

Four: The length of the rectangle is 5/14 plus 1/7 equals 1/2There are two lengths and only one wide, so the length of the fence is 1/2 multiplied by 2, plus 5/14 equals 19/14

Five: The three parentheses are: 13/9, 5/6, 29/12

Let the quantity of work be 1, the efficiency of A is 1/4, B is 1/5, A and B complete 1/5 every day, plus 1/4 is equal to 9/20

Six: 9/10 3/11 5/11 = 9/10 (3/11 + 5/11) = 9/10 - 8/11 = 19/110

Seven: The smallest composite number is 4, and 31 need to be added.

Eight: Adds up to 1

9: 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 = (1-1/2) + (1/3 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6) + (1/6 - 1/7) = 1-1/7 = 6/7

-2 5-1 3 = 34 15 meters.

4+1 4*(1+1 6)+5 12=23 24, the task cannot be completed.

4. Length = 5 14 + 1 7 = 1 2 km, if the long side is against the wall, the fence is 1 2 + 2 * 5 14 = 17 14 km; If the wide side is against the wall, the length of the fence is 2*1 2+5 14=19 14 km.

7. The minimum composite number is 4, and 31 need to be added.

8. The exchange of addition.

.2 meters. 2. Able to exceed the task.

3. 19/84 of the whole journey

5/14 or 1/3/14

5, 13/9; 5 out of 6; 198/12/12, commutative of addition.

9, 6 out of 7

2: No, only 10 12 completed

5:13/9, 5/6, 29/12, 9 206: 1/10.

7: I don't know.

8: Principle of addition.

9, 6 out of 7

1.Let the unit price of the ballpoint pen x, then the unit price of the fountain pen is.

3x+x=So the unit price of the ballpoint pen is yuan, and the unit price of the fountain pen is the hunger yuan.

2.After x hours, the distance is 500 kilometers away.

x=5 so after 5 hours, the distance is 500 km.

Answer: There are x boys and 156-x girls

x(1-1 11)=3*(156-x-12) can obtain: x=43 33*144, which is not an integer, so there is a problem with the problem.

If 3 times is changed to 2 times, the above method can be obtained:

x = 99, i.e. 99 boys and 156-99 = 57 girls.

There are x number of boys.

Girls have (10x 11)*1 3+12

There are 156 people in total, girls and boys.

10x/11）*1/3+12+x=156

You don't need to solve the equation.

156-12 144, which is the total number of boys plus the number of girls remaining.

The remaining number of girls is (10 11) 2 10 22, the number of boys is 144 (1+10 22) 99, and the number of girls is 156-99 57.

Boys: (156-12) (1-1 11) 3+1

It's a score, and this question is wrong. . .

There seems to be a problem with the numbers in this question. A total of 156 minus 12 girls made 144. The boy's 10 11 is 3 times that of the girl, and the remaining 10 33 of the girl is found for the boy, and the boy is regarded as 1 + the remaining 10 33 for the girl is 43 33, and 144 people are divided by 43 33 to find the boy.

If there are x girls, then 156-x will be for boys

The remaining boys are 10 11

So there is 10*(156-x) 11=3*(x-3), and the solution is x=1659 43 (not an integer) (there is a problem).

Is it a math workbook? Or a math book?

This is asking you for the least common factor, such as 4 and 6 is 2

A flower "number" .Flower "bouquet" ....The number of one flower in each bouquet is 52....=4×..13

36...=4×..9 (ellipsis is what I used to separate).

A bouquet of flowers is a bunch of flowers of any kind.

Because they are the same bouquet (that is, the same number of flowers in each bouquet), you can tie up to 4 bouquets.

The Mathematics Q&A team will answer for you, I hope it will be helpful to you.

Namely: 36 and 52 greatest common divisor 4

So: up to 4 bundles can be pierced.

I wish you progress in your studies and go to the next level! (

The greatest common divisor of 52 and 36 is 4, so you can tie up to 4 bundles. 13 flowers of the first type and 9 flowers of the second type are used in each bouquet.

2l52 36

2 l26 18

A: You can tie up to 4 bouquets.

l is a divisive sign.

4 bunches, 13 for each of the 52 flowers, and 9 for the other.

It can be calculated by finding the greatest common factor, and the equation of short division is short, and finally (52,36)=4

Because the greatest common factor of 52 and 36 is 4, a maximum of 4 bundles can be pierced.

Solution: Actually, it is to find their greatest common factor.

The greatest common factor for 52 and 36 is: 4

A: You can tie up to 4 flowers.

It's not easy to answer on the phone--

Four bunches (52 flowers of one kind), 14 per bunch (36 flowers of one kind), 9 per bunch

It is made with the greatest common divisor of 52 and 36 4, and you can tie up to 4 bunches, and you can just run out.

I don't know if it's right or not, just calculate the greatest common factor of 52 and 36, and it is best to use short division to find the greatest common factor and the least common multiple.