Sixth grade math problem, urgent process, a sixth grade math problem urgent. process

Pour 18 kg from the first barrel into the second barrel, the weight of the two barrels of oil is equal, the weight of the first barrel is 18 * 2 = 36 kg more than the second barrel, the first barrel uses 7 9, the second barrel uses 3 5, the remaining weight of the two barrels of oil is equal, then the (1-7 9) = 2 9 of the first barrel is equal to the (1-3 5) = 2 5 of the second barrel, so the weight of the first barrel is more than the weight of the second barrel = 9:5

So the weight of the first barrel of oil = 36*9 (9-5) = 81 kg, and the weight of the second barrel of oil = 81-36 = 45 kg.

If 18 kg is poured from the first barrel into the second barrel, the weight of the two barrels is equal, indicating that the first barrel is 18 2 = 36 kg more than the second barrel.

The first barrel is the second barrel of (1-3 5) (1-7 9) = 9 5 difference multiple problem The second barrel: difference (times - 1) = 36 (9 5-1) = 45 (kg) The first bucket 45 + 36 = 81 (kg).

Let the first barrel of oil (x+36) kg, and the second barrel of oil xkg.

x+36)*7/9=x*3/5

35x+35*36=27x

x=35*3=105

So for 141 kg and 105 kg.

Column Equation System Answer:

Let the first barrel of oil be x kilograms and the second barrel of oil be y kilograms, then the system of equations can be listed:

x-18=y+18

x*(1-7/9)=y*(1-3/5)

Solution: x=81, y=45

Girls: Boys = 1:2 = 4:8

Girls: Boys = 5:8

Per serving: 4 (5-4) = 4 (names).

The tour room originally had: 4x(4+8)=48 (people).

The girl is x, and the total person is y.

x=1/3y，y=3x；

x+4)/(3x+4)=5/13.

Solution x=16

y=48.The tour room turned out to be 48 people:

Start Girls: Boys = 1:2

After transferring 4 girls, girls: boys = 5:8

Because the boys are the same, the ratio of 4 girls to the boys is 5 8-1 2 = 1 8, so the number of boys = 4 * 8 = 32 The original number of girls = 32 2 = 16 people, that is, the tour room originally had 16 + 32 = 48 people.

The number of female students is set to x, and since in the school tour room, girls account for one-third of the total number of people in the room, so the tour room originally had 3x

Later, when 4 more girls came in, the number of girls was (x+4), the number of women in the room was (3x+4), and the ratio of girls to the whole room was 5:13

So (x+4):(3x+4)=5:13

x = 16 people.

3x = 48 people.

That is, the tour room originally had 48 people.

The original girl x people, the original boy y people.

Since girls make up one-third of the room, so: x (x+y)=1 3 so y=2x

Because 4 more girls came in later, the ratio of girls to the whole room was 5:13. So: (x+4) [(x+40+y]=5:13

So x=16

y=32 x+y=16+32=48, so there were originally 48 people in the tour room.

(x+4) (3x)=5 13 x=26 i.e. there are 26 original girls. The tour room originally had 26 * 3 = 78 people.

450*13 45 = 130 yuan (little red).

450-130=320 yuan.

320 * 5 (11+5)=100 yuan (Xiaoqiang)320 * 11 (11+5)=220 yuan (Xiaoming).

Xiao Hong's money is 13 45 of the total, then Xiao Qiang and Xiao Ming's money is 32 45 of the total, and the ratio of their 2 money is 5:11 can also be seen as 10:22, then Xiao Qiang's money is 10 45 of the total, and Xiao Ming's money is 22 45 of the total

So Xiaohong's money is 450 45*13=130

Xiaoqiang's money is 450 45*10=100

Xiao Ming's money is 450 45*22=220

The number of small red money: 450 13 45 130 (yuan) the sum of Xiaoqiang and Xiaoming money: 450-130 = 320 (yuan) Xiaoqiang money:

320 5 (11+5)=100 (yuan) Xiao Ming money: 320 11 (11+5)=220 (yuan).

If Xiaohua answers the Y question incorrectly, there will be a total of 4Y questions. The number of questions that both of them answered incorrectly is 4yx(1 6)=(2 3)y, and the number of correct answers is.

4y-【y+5-(2/3)y】

List two inequalities: the number of questions that both of them answer incorrectly must be less than the number of questions that Xiaohong answers incorrectly 5 (2 3)y<5

Both Hua and Hong answered more than half of the total number of questions in the test: 4y-[y+5-(2 3)y]>2y

Solution: 3, because the total number of 4y is a multiple of 4,6, so 4y=24,y=6, so 4y-[y+5-(2 3)y]=17

Let the total number be x, then Xiaohua answers 1 4x wrong, and both of them get 1 6x wrong, so there are 1 4x-1 6x questions where Xiaohua is wrong and Xiaohong is right, and 5-1 6x is wrong and Xiaohua is right.

x-[1 6x+(1 4x-1 6x)+(5-1 6x)] greater than 1 2x

The solution is greater than 12

x must be a common multiple of , then x must be a multiple of 12, so when x is 24, Xiaohua is wrong 6, Xiaohong is wrong 5, both of them are wrong 4, Xiaohua is wrong and Xiaohong is right There are 2 questions, Xiaohong is wrong and Xiaohua is right 1, so both are right is 17, and more than half of 24 12.

When x 36, Xiaohua is wrong 9, Xiaohong is wrong 5, and both of them are wrong 36*1 6 6, which is greater than Xiaohong's 5 questions, so there is no question attached to 36 or more.

Let the total number of questions be n.

n/6 < 5

n/4 > 5

n < 30

n > 20

then there are 20 < n < 30

Because n 4 > 5

n = 24 or 28

Because n is a multiple of 6, n = 24.

Therefore, Xiaohua answered 18 questions correctly and Xiaohong answered 19 questions correctly.

So, the question they all answered correctly was question (18).

The total number of questions for 17 questions is x

From the meaning, 1 6<5 x < 1 4, then 20 So the number of questions that Xiaohua and Xiaohong answered correctly = 24-24*(1 6)-[6-24*(1 6)]-5-24*(1 6)]=17.

There are a total of A questions, and the following formula is obtained according to the meaning of the question:

a-5-(5-1 6a)=3 4a-(1 4a-1 6a) solves a=12, bring it a, and the questions that are answered correctly should be a-5-(5-1 6a)=12-10+2=4.

5÷(1/4-1/6)=5÷1/12=60

The number of questions that Xiaohua answered correctly = 60 3 4 = 45 questions.

The number of questions answered correctly = 45 + 5 = 50.

Q: Which one is left?

A buys 2 times as much as B, then the two people buy 3 times as much as B, and the total amount they buy is a multiple of 3.

Six goods, total: 15 + 16 + 18 + 19 + 20 + 31 = 119 kg 119 3 = 39 more than 2

For the rest, the remainder divided by 3 is also 2

Only 20 satisfied.

So the rest is 20 kilograms.

B bought: (119-20) 3 = 33 kg.

A bought: 33 2 = 66 kg.

There's nothing to complain about, and there's still a long way to go.

Total weight of 6 boxes: 15 + 16 + 18 + 19 + 20 + 31 = 119kg; ,119 3=39 remainder 2;

Because part of the 5 boxes of goods bought is 2 times that of the other part, the total weight of 5 boxes must be 3 times the number of kilograms, that is, an integer multiple of 3; And because the total weight of 6 boxes is an integer multiple of 3 and more than 2, then the weight of the remaining box must be a number divided by 3 and 2.

Check the weight number of 6 boxes, only 20 = 6 3 + 2 is the number divided by 3 and the remaining 2, so the remaining 1 box of goods weighs 20kg.

Attached: 5 boxes sold: one 15 + 18 = 33;The second is 16 + 19 + 31 = 66, and the latter is twice as much as the former.

Solution: 15 + 16 + 18 + 19 + 20 + 31 = 119kg A customer buys the weight of the goods is 2 times that of another customer, then the weight bought is a multiple of 3 only 119-20 = 99,2 (15 + 18) = 16 + 19 + 31 = 66kg, in line with the topic.

Therefore, the remaining 1 box of goods in the store weighs 20kg

Total: 15 + 16 + 18 + 19 + 20 + 31 = 119 kg 119 3 = 39 surplus 2

For the rest, the remainder divided by 3 is also 2

Only 20 satisfied.

So the rest is 20 kilograms.

B bought: (119-20) 3 = 33 kg.

A bought: 33 2 = 66 kg.

（16+19+31）÷（15+18）=2

The remaining 1 box of goods in the store weighed 20 kg.

16+19+31=66

The weight of 1 box of goods left in the store = 20

(1) 42-16 = 26 (pages).

26 1/5 = 130 (pages).

A: The book is 130 pages long.

2) 1 - 2 out of 9 = 7 out of 9.

7/9 - 2/9 = 5/9.

15 Five-ninths = 27 (ton).

27 Two-ninths = 6 (ton).

A: 6 tons were transported.

3) 4/15: 3/8 5/16 = 4/15: 6/5 = 2/3.

4) 1500-300 = 1200 meters.

1200 Three-fifths = 2000 meters.

2000 + 1500 = 3500 meters.

A: The road is 3,500 meters long.

1. "The third day starts on page 42"That is, if you read 41 pages in the first two days, and deduct the 16 pages you read on the first day, you can get the number of pages you read on the second day 41-16 = 25 (pages), which is a fifth of the book, then the total number of pages in the book is 25 5 = 125 (pages).

2. The remaining seven-ninths are five-ninths more than the two-ninths transported away, that is, five-ninths is 15 tons, 15 (5 9) = 27 (tons).

3, (4 15) :( 3 8 5 16) = 2 9 that is, two-ninths 4, the remaining three-fifths are 1500 - 300 = 1200 (meters), so that the length of the remaining road is 1200 (3 5) = 2000 (meters), so that the total length of the road is 2000 + 1500 = 3500 (meters).

The first question is 41 pages from page 17, a total of 41-17 + 1 = 24 pages, these are one-fifth of the number, that is, book 24 5 = 120

The second question has 7/9 left, which is 5/9 more than the transport, that is, 5/9 is 15 tons, 15 (5 9) = 27

Question 3 4 15: (3 8 5 16) = 2 9 i.e. 2 out of 9 Question 4 explains that the remaining three-fifths are 1200, so that the rest is 1200 3 5 = 2000. So the total road is 2000 + 1500 = 3500

Cement = 192 (2+3+5) 2=ton.

Sand = 192 (2+3+5) 3=tons.

Pebbles = 192 (2+3+5) 5=96 tons.

Set cement, sand and gravel with 2x, 3x, 5x respectively

The column equation 2x+3x+5x=192

Solution x = so cement sand is needed for ton, ton, 96 ton.

The savings in the original plan were multiplied by 100 percent.

Equal to 6.5 per cent.

The second question is that the minute hand walks in one hour.

Total 3 laps 3* * Approximately equals.