What is the probability of having a sick girl?

If the title is normal AA or AA diseased, AA is known; Because the younger brother is sick with AA, both parents are AA, and the phenotype of himself and his parents is normal, so it can be known that the female genotype is 1 3AA or 2 3 AA. For normal males who are not related to the local area, because the probability of the local population is aa=1 10000, a=1 100, aa=99 100, a=2*1 100*99 100, and the prevalence of normal males is aa=2 3*2*99 100*1 100=

The female genotype is 2 3 AA, and the male is affected AA = 2 3 * 2 * 99 100 * 1 100 =

When both parents are AA, they will give birth to a 1 4AA, and finally give birth to a sick child AA=1 4*2 3 *2 3*2*99 100*1 100=

In the end, the sick girl multiplied by 1 2, and finally calculated the answer.

Girls with disease AA = 1 2 * 1 4 * 2 3 * 2 3 * 2 * 99 100 * 1 100 = 11 10000

It is assumed that the causative gene is a non-a

It has been determined that the younger brother is AA

Both parents are AA, girls 1 3 AA 2 3 AA married male 198 10000AA 99 * 99 10000AA 1 10000AA (excluded).

Because of the 1 in 10,000 probability of disease, it is formed by the combination of 1 percent of the disease-causing gene and 1 percent of the disease-causing gene.

That's how I understand it.

1/4...

After subtracting 1, it's either xxyy, yy, or xx, yyyy

If a boy is born, then there must be a y, and it can be seen that to have a genotype of xy, it can only be the first case, so the probability is 1 4That is, subtract 1 to separate the probability of separation in the first case 1 2 times the probability of y 1 2

I guess it's like this personal opinion.

The disease is autosomal dominant, so there is a 1 8 chance of it.

Genetic mutations can cause albinism, and according to you, the probability of your child getting the disease is less than 5 percent, so it is almost impossible to get the disease.

may3721007

That's right.

I remember reporting it.

But that's just for grants, not absolutely.

may3721007

Makes sense.

I've seen it occasionally.

I wish you all the best.

The older generation said that when walking, the left leg is the first to give birth to a son, and the right leg is to give birth to a daughter.

If there is! Then the creature will disappear?

From a biological point of view, isn't the probability of having a boy or a girl 50%?

Those who gave birth to men were strangled, one after another, and one was always a girl.

may3721007 seems to make sense! I don't know if there is data to back it up!

What to give birth to is not determined by the mother ?

If the couple is normal, they are genetically AA

aControl dominant genes.

A controls recessive genes (i.e., albinism AA). The children they give birth to are aa, aa, aa, aa

The probability of having another boy without albinism is 75%.

3/16

A normal couple who give birth to a girl with albinism has a genotype of aaaa aa aa and the probability of giving birth to a diseased aa is 1 4, and the probability of not having a disease is 3 4 4 The probability of a normal one being a disease is 1 4 * 3 4 = 3 16

Is this a biological probability calculation problem The solution should be.

Albinism is often hidden, so the genotype of an albinistic girl should be AA, then her parents are AA and AA respectively, if you want to have a normal genotype, the genotype must be a[ ], so the probability is 3 4, the probability of disease is AA, the probability is 1 4, that is normal, the probability of disease should be 1 4 * 3 4 = 3 16

That's right.

Come on! The odds of having a boy or a girl are 1:1, and there are no shortcuts at all.

No, as far as I know, women who have a lot of nightlife, smoke, and drink alcohol have a higher chance of having a girl.

No, but the children born to beautiful women are certainly beautiful too.

No, I can't say for sure.

You haven't read a book.