Which master will answer the question?

You don't need to fight at the beginning of the first year of high school, just do it step by step, you can do what the teacher says, and what you should do is to adapt to the rhythm of life and learning in high school, you must adapt as soon as possible, and early adaptation means that learning is faster and more efficient than others! High.

First, the early stage of the second year of high school is to lay the foundation, and the second half of the second year of high school is to improve, and the third year of high school begins to sprint steadily! Therefore, in the early stage of high school, you have to go with the teacher, in the middle of the year, you have to add your own efforts, and in the later stage, you have to rely more on yourself, everything must be active, take the initiative to find questions to do, take the initiative to ask the teacher, don't pay attention to the opinions of others, and talk to the teacher or parents more about the troubles and confusion (or find me, hehe)! Also, if you are divided into arts and sciences, you have to prepare in advance and find a subject that you like.

If I go back to my freshman year of high school. I'll do my best. It is useful to fight for 3 years in high school. It's true. But the body is more important. Exercise should be intensified.

I think you should fight it, but it doesn't take all your strength, but it depends on your individual learning ability. Because throughout high school, most of the knowledge is in the first year of high school, and there are four books on Chinese, four books on mathematics, four books on English, and two books on others. If you do a good job in the first year of high school, you can also enter the key class in the second year of high school.

It's worth fighting for a high one.

It's a computer question, you ask this question.

I digress.

Number of rats = 5 5 5 5 5 = 3125

Number of kittens = 5 5 5 5 = 625

Number of big cats = 5 5 5 = 125

Number of bags = 5 5 = 25

Number of people = 5 + 1 = 6 (assuming that the driver is not in 7 people and the driver does not have a backpack) Total number of legs = 3125 4 + 625 4 + 125 4 + 6 2 = 15512 If you don't consider the driver at all, it is 15510

Hey, I didn't panic when I encountered this kind of problem, and I could solve at least 3 solutions, but now I look at the problem with a confused face, which confirms the sentence:

Back then, I urinated against the wind, and now I have wet shoes with the wind!

Uncle Ben wants to ask what to say here.

Look at the teacher's class and refine the steps.

1. Each figure is equal to; The 4-sided and 5-sided squares and the 6-sided squares are equal to 15, 15 + 15 + 15 = 45

A root banana is equal to 1, and 8+15 is equal to 23

3. The banana represents 4, and each clock represents 3, so it is equal to 104, the clock is at 2 o'clock, so it represents 2, and the banana has only three, and then there is less of a square with 4 sides, 2+3+3*11 is equal to 38;

Multiply and divide first, then add and subtract, and then look at the banana.

And that box.

There are also clocks and clocks minus one. 38

1. 15 + 15 + 15 = 45 "The multilateral box is 15".

2. 4+4+15=23 "Banana is Four".

3 4 + 3 + 3 = 10 "Quartz Clock is 3".

4. 2+4+4x15=66 "Quartz Clock is 2".

Three pentagons 45 a 15

Two bananas plus 15 equals 23

One banana is equal to 4, 4 plus two clocks is equal to 10 clocks and one 3

1. Look at the first figure: I draw two lines with the same pink line, and the two lines with yellow are also of equal length. So the first figure is the base of the big triangle = the bottom of the red right triangle and the bottom of the dark green right triangle.

Height = height of the red right triangle The height of the dark green right triangle.

2. Compare the bottom and height of the first figure and the second figure.

Although their height is equal.

However, if we look at the line segments versus the bottom, their bottoms are not equal, the bottom of the second figure is smaller than the bottom of the first figure, so the area of the second figure will definitely be smaller than the area of the first figure, so there is a gap.

I used CAD to make the following figure, and found that the two hypotenuse edges are not straight lines, and I checked whether the area is concave and convex and adds up to just one, indicating that the following figure releases a subtle space. Just look at the picture and understand the attached drawing.

I tried to draw it, and the reason is that the hypotenuse doesn't form a straight line.

If you lean down with a ruler, you will naturally see it.

The hypotenuse of the first picture is concave, and the junction of red and blue in the second picture is convex, so the entire area of the second picture (including the blank space) will be larger than that of the first picture, and only the area of the colored area of the last two pictures will be the same if one piece is missing.

It's not so mysterious, it should be an illusion caused by the different proportions of the upper and lower figures.

If the small squares are not equal in height, if the first graph is not in equal height.

Because the length has changed, the total length has not changed, but the position length of the four zones has changed.

Question 93: C first clarifies that PIQ is the operational IQ, and then the Split Silver question gives the operational IQ table divided into two percentage grades (16 and 84) for the feast, and WAIS-RC is based on 100 as the average and 15 as the standard deviation, so PIQ=115 is one more standard deviation so his percentage grade is 84 (PS: just remember:

Choose 84 if the question is one standard deviation larger, and 16 if the question is less than one standard deviation! VIQ, Yuyuan PIQ, and FIQ are all the same! So you can see the answer at a glance! ）