Trouble with a few math problems, please teach a math problem?

1. If there are x people in the class, then.

x/6-1=x/9+1

Solution: x=36

2. Let the two numbers be 4x and 4y, then there is:

4xy=140

xy=35, so x=5, y=7 or x=1, y=35 so the numbers are: 20, 28 or 4,140

1. Set x boats, 6(x+1)=9(x-1) x=5So the number is 36

My proof method is different, but the idea is more concise than Mu Xiao, and you can quickly get the communication and draft explanation of the relationship between the size of A, B, and C, for reference.

Finally, the potato fruit, in connection with the previous article, b>c, the hall.

by LGAA

Is the shaded part a square except for the fan-shaped part?

A square has an area of a quarter circle and a shaded part area.

The square of the area (perimeter divided by 4) of the square.

1 4 The area of the circle The square has the square of the side length *1 4 <>

16 divided by 4) squared by 4) squared * 1 4 = square centimeters.

Good guy, you're not a math problem. You should ask a programmer.

How easy it is to solve the math problem, set the range of variable values, and then set the range of interest values. For example: amount = y, interest = x

0≤y≤1000 x=

1000＜y≤10000 x=

And so on.

In fact, if you are not very good at math, you can use piecewise functions according to the suggestions of the friends above. Different interest rates are set according to different segments.

However, if you want a better way to function, you can suggest that you use a mathematical drawing software, which has a lot of functions, basically all of them, and then point out the function graph you are satisfied with.

Hello, I have seen your question and am sorting out the answer, please wait a while Oh Ask. <>

A math problem.

Questions. 20 questions.

Can you send it by typing?

Questions. Hurry up and solve it.

2) If AR and the x-axis intersect at the point D (different from the point), the value range is obtained.

s adm s fdm.

20.(This question is worth 12 points) It is known that the right focus of the ellipse c: =1 is f, and the straight line that passes through the point f and is not perpendicular to the x-axis intersects 43c at two points of a and b, and passes through a and b respectively to make two straight lines parallel to the x-axis, b2, and let b intersect with the straight line x=4 respectively at the point m, n, and the point r is the midpoint of mn (1) Verification:

ar fn(1) is defined by the ellipse and conditional, 2 a =|f 1 b |+f 2 b |=10, we get a =5, and c =4, so b = 3So the elliptic equation is =1(2) From the point b (4, y b) on the ellipse, we get | f 2 b |=y b |= Because the equation for the right alignment of the ellipse is x = the eccentricity is , according to the ellipse definition, there is | f 2 a |=x 1 ),f 2 c |=x 2 ), by | f 2 a |、f 2 b |、f 2 c |into a series of equal differences, we get ( x 1 ) + x 2 ) = 2 , from which we get:

x 1 + x 2 =8.Let the midpoint of the chord ac be p ( x 0 , y 0 ), then x 0 = 4(3) Solution 1:

consists of a ( x 1 , y 1 ) and c ( x 2 , y 2 ) on an ellipse. 9 ( x 1 2 x 2 2 ) + 25 ( y 1 2 y 2 2 ) = 0, that is, 9 = 0 ( x 1 ≠ x 2 ) substituting ( k ≠0) into the above equation to get 9 4 + 25 y 0 ( 0 ( k ≠ 0) i.e. k = y 0 (when k = 0 is also true).From the point p (4, y 0 ) on the perpendicular bisector of the chord ac, we get y 0 = 4 k + m, so m = y 0 4 k = y 0 y 0 = y 0

From the inside of the segment bb (b and b symmetrical with respect to the x-axis) of the point p (4, y 0 )**, we get y 0 so m

You can increase the calculation period, for example, you don't calculate the interest once an hour, you can't do it once a day, or longer, your idea of changing the interest rate can also be ah, isn't it just a matter of a few lines, you can set a few gears, it depends on how you want to limit the number of gold coins of the player.

Use the piecewise function, and you're good to go.

You shouldn't have all the conditions for this question, but the general idea is as follows:

ao/ad=bo/bc

ao/(ao+od)=bo/(bo+oc)(ao+od)/ao=(bo+oc)/bo1+od/ao=1+oc/bo

od/ao=oc/bo

Because it's to the top corner aob= doc

You just need to find a way to prove that AOB and doc are similar.

Find another pair of diagonal oba= ocd or oab= odc, just prove that ab and cd are parallel.

What are the known conditions? According to the data on the graph, ao:ad≠bo:bc

If the conditions are not enough, go back and take another one**.

Solution: Difference: The biggest difference between folding and symmetry is that these two are fundamentally two different levels of concepts, "folding" refers to a kind of graphic movement, and "symmetry" represents the positional relationship between two figures.

Connection: Fold a figure along a straight line, and the resulting figure must be axisymmetric with respect to the straight line of the original figure.

Difference: Symmetry is the axis of symmetry and the pattern on both sides must be the same.

Folding is a casual fold and the graphics on both sides are not necessarily the same.

Connection: Folds may be symmetrical Symmetry must be folds.

1/(1+ξ)e²n

Multiply the left and right sides by 1+ at the same time

1=e²n*(1+ξ)

Divide the left and right sides by e n at the same time

1/e²n=1+ξ

Transposition. =1/e²n-1