How does python store each different substring in a string in a list?

The string is immutable, and the list is mutable.

That is to say, once the meaning of the string is determined, it cannot be changed, but the list can.

abc"d = a','b','c']'e'And.

new_s = s + e'

Moreover, immutable means that it can be used as a dictionary key, while mutable is not messy.

Also, the approach to both things is different.

list_tmp=f = open('file_','r'for i in :list list tmp It's okay to have a shift faction to argue the mu?

If the file is not very large:

def findstrinfile(filename, lookup):

return lookup in open(filename,'rt').read()

Dealing with large files:

def findstrinlargefile(filename, lookup):

with open(filename, 'rt') as handle:

for ln in handle:

if lookup in ln:

return true

else:return false

You can use '' to split this string to get a list.

For example, if your string input is stored in the variable test string, then test'') is a list of 3 elements, each of which is a string (without line breaks).

>>>string = a_b_c_001a_b_c_002

a_b_c_003'''

>['a_b_c_001', a_b_c_002', a_b_c_003']

String operation, the splitlines function splits the string into rows and returns a list.

Separated by split. Or regular ...

a=""a_b_c_001

a_b_c_002

a_b_c_003

import re

p="(n]+)n")

result=;

print result

As a result, it was. [('a', b', c', 001'),a', b', c', 002'),a', b', c', 003')]

print sum(map(ord,list(where str1 is the input string.

Take ABC as an example:

Turn all letters into lowercase ABC.

list( turns the string into ['a', 'b', 'c']ord turns letters into ASCII numbers.

map(ord,list(Turns all letters in the list into numbers [97,98,99].)

sum.

After summing, since the ascii of a is 97, each letter has to be subtracted by 96.