Solve the following equations in an appropriate way, and solve the following equations in an appropr

Updated on educate 2024-02-08
12 answers
  1. Anonymous users2024-02-05

    Hehe, I'm glad to receive your request for help, the title is written like this.

    Solution: 4x(x+1)=15

    4x^2+4x-15=0

    2x-3)(2x+5)=0

    x1=3/2 x2=-5/2

    2.3/3 (2x-1) = 1/4-2x Looks like a hassle.

    4(2x-1)^2=3(1-2x)

    4(4x^2-4x+1)=3-6x

    16x 2-10x+1=0 factorization.

    16x-2)(x-1/2)

    So x1 = 1 8 x2 = 1 2

    Hehe, I'm so tired, hope, thank you.

  2. Anonymous users2024-02-04

    4x(x+1)=15

    4x^2+4x-15=0

    2x-3)(2x+5)=0

    x1=3/2 x2=-5/2

    3/3 (2x-1) = 1/4-2x

    Is the score in**? It means that the topic is very unclear.

  3. Anonymous users2024-02-03

    Equation 14x +4x-15=0 δ=16+4*4*15=256 so x1,2=(-4 16) 8=-5 2 or 3 2

    Equation 2Cross-multiplication has 16x -10x+1=0, and factoring has (8x-1)(2x-1)=0, so x1,2=1 8 or 1 2

  4. Anonymous users2024-02-02

    1).4x squared - 256 = 0 (2x + 16) (2x - 16) = 0

    x=-8 or x=8

    2) .x squared - 6x-10 = 0 (x-3) 2 = 19

    x-3=±√19

    x=3±√19

    3).5x squared = 4x-15x 2+4x-1=0

    5x-1)(x+1)=0

    x=1 5 or x=-1

  5. Anonymous users2024-02-01

    Dizzy. It's that simple! .4

    x)^2=256---4x=+-16---x=+-4...x 2-6x-10=0 gives x 2-6+9=19 (x-3) 2=19---x-3)=+- 19 under the root--- x=3 + 19 under the root or 3 minus 19 under the root....

  6. Anonymous users2024-01-31

    (1) x square = 64 x = 8

    2) x = -3 + root number 26 x = -3 - root number 26

    3) 5x squared + 4x-1 = 0 (5x-1) (x+1) = 0 x = x=-1

  7. Anonymous users2024-01-30

    3x square - 4x = 2x, one, when x = 0, two, when x is not equal to zero 3x square = square = 2x, x = 2

  8. Anonymous users2024-01-29

    ①(2x-1)²-2(2x-1)=3

    Solution: Let 2x-1=y

    The original equation is: y -2y-3 = 0

    y+1)(y-3)=0

    y1=-1, y2=3

    When 2x-1=-1, x=0

    When 2x-1=3, x=2

    The solution of the original equation is x=0 or x=2.

    x²-4ax+3a²+2a-1=0

    Solution: x -4ax + 4a -a +2a-1 = 0 (x -4ax + 4a )-a -2a + 1) = 0 (x -2a ) -a -1) = 0

    i.e.: |x-2a|=|a-1|

    x-2a = a-1 or x-2a = -a+1

    x = 3a-1 or x = a+1

    The solution of the original equation is x=3a-1 or x=a+1.

  9. Anonymous users2024-01-28

    1. Solution(2x-1) -2(2x-1)-3=0[(2x-1)+1]*[2x-1)-3]=02x*(2x-4)=0

    Get 2x=0 or 2x=4

    x=0 or x=2

    2、 x²-4ax+3a²+2a-1=0

    x²-4ax+(3a-1)(a+1)=0

    x-(3a-1)] [x-(a+1)] = 0x=3a-1 or x=a+1

    If you don't understand, you can ask.

    If it helps, remember to adopt it, thank you.

    Good luck with your studies!

  10. Anonymous users2024-01-27

    First of all, to correct the mistake upstairs, both sides cannot be divided by (3x-2) at the same time, because if 3x-2 = 0, according to the rules, both sides cannot be divided by 0 at the same time. So, the correct way is to dissolve first, then merge the same terms, and then find the answer by crisscrossing it. Comparing the two approaches, you will find that x=2 3, which does not appear in the upstairs answer, is also the answer to the equation, so the upstairs solution is wrong.

  11. Anonymous users2024-01-26

    For example, the chaotic cherry blossom picture: 12 questions: <>

    Question 13: The cover of the cave is withered <>

  12. Anonymous users2024-01-25

    <> try to call for caution and respect.

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