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The meaning of the title is said upstairs.,Here's a **.。
string ss="aabbccddeegggddd";
string s = "";
string temp = "";
string sss = "";
for (int i = 0; i < i++)s = , 1);
if (temp != s)
sss += s;
temp = s;;
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If you want to remove sequential characters that have no break and are repeated from the first place, you can write it like this.
string s = ;
string s1 = "aaaabcdefg";
string s2 = "abcdezxcvl";
for(int i=0;i<;i++)
elseelse}}
Probably this is the idea, there is no environment, and it cannot be tested. It's stupid.
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Just use a hashtable to record the values that appear.
static void main(string args),"s);
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Convert it into an array with split, then read the array data loop in turn for comparison, delete it if it has it, and add it to another string if it doesn't. This is a more straightforward method, and another is to use a regular rule:
str="a,b,c,d,ccc,ee,cc,ccc,ee,d,b,h,b,";
var reg =/b([a-z]+)1\b)/g;
alert(,""
Note: If you are familiar with the regular, use it, if you are not familiar, you can use the loop, the regularization is just a little less, the execution efficiency is actually about the same, and the regularization is also performed in a loop. It is impossible not to use loops.
I've left this kind of work to JS, so if you want C you might have to change the syntax. c is a server-side operation, no matter how you deal with it, it will use loops, it is impossible not to use loops, and this kind of data will not be burdened by js when it is committed.
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string sps = ', and then use hashtable storage, it will automatically remove the duplication, and then stitch together the data of the hashtable.
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First, save this string in the collection, and the collection has properties that can directly find the duplicates.
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Are the characters all in English?
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string wordfilepath = @"d:\wwwroot\readwordtoxml\readwordtoxml\bin\debug";
int b = wordfilepath .lastindexof(@"\");Get the last ' position first.
string wordfilepath1 = , b);Truncate the string before the last ' to get "d: wwwroot readwordtoxml readwordtoxml bin".
wordfilepath1 .lastindexof(@"\");Get the last ' position of wordfilepath1, which is the position of the second ' you want, is 38, right, haha.
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Do you mean that a particular word appears in this example, or does it mean that all the repetitions in the center are combined?
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The algorithm doesn't know, and the practical application can be done with a regular expression: (.).1
if(strcmp(*n[i],*n[j]))temp=n[i]; n[i]=n[j]; n[j]=temp;
Here's the problem. >>>More
Just take a look at this one**.
Hope it helps. >>>More
stuff deletes characters of the specified length and inserts another set of characters at the specified starting point. >>>More
There are many ancient poems that reflect the characteristics of Chinese characters, such as: 1. Reading to go to a thousand miles of smoke and waves, twilight Shen Shen Chu Tiankuo. Liu Yong's "Yulin Bell". >>>More
Summarize the process of making zongzi in one word? There is a word to describe him, and that word should be tied.