Splitting of the chemical formula of the chemical ion reaction of the higher one

BaCO3 is a slightly soluble substance, so it cannot be disassembled. Nitrates are all soluble in water!

Remember the following mantra:

Alkalis only dissolve potassium, sodium, calcium and barium, potassium, sodium, ammonium nitrate are all soluble in water, sulfate is not allowed to barium sulfate, carbonate is not allowed to barium carbonate, chloride salt is not allowed to silver chloride.

Splitting principle: "write": write the chemical equation about the reaction.

Dismantling": Soluble strong electrolytes (strong acids, strong bases, soluble salts) are represented by ion symbols, and other insoluble substances, gases, water, etc. are still expressed by molecular formulas. Slightly soluble strong electrolytes should be seen whether they exist mainly in the form of free ions, "deleted":

Remove ions on both sides of the equation that do not participate in the reaction.

Check": Check whether the number of atoms and the number of charges on both sides of the formula are equal (to see whether they are balanced), and also see whether the obtained stoichiometric number of the formula is the simplest integer ratio, if not, it should be reduced to the simplest integer ratio.

Because baCO3 is a precipitate, it cannot be disassembled.

In fact, the ionic equation is to see that the substances that can be ionized in water become the substances that cannot be ionized in water, such as salt solutions, acid-base solutions (note that they are solutions), these solutes can be ionized, so these can be written as ionic formulas. Like precipitation, you can't write ionic formula, because it can't be ionized in aqueous solution.

Insoluble substances such as baco3 cannot be written in ionic form.

Only the ions present in the solution in large quantities can be written in the ionic form.

Barium carbonate is solid in water, so it is not written in ionic form.

In the general ionic reaction equation, the higher stage is mostly acid-base neutralization, as well as salt reaction. You can write the equation (nothing more than the anion and cation of two substances swapping positions), and then split the separable ones, keep the non-separable ones, and reduce the identical ions on both sides, and you're good to go. Of course, don't forget the gas symbol and the precipitation symbol if you can't separate it.

What about the ionic reaction equation?

1. Weak electrolytes cannot be disassembled, such as: water, acetic acid and other weak acids, ammonia monohydrate and other weak bases.

2. Oxides cannot be dismantled, such as CO2, and iron oxide is precipitated and cannot be disassembled.

3. The gas cannot be disassembled. Gases have a molecular structure or an atomic structure, and to write ionic compounds, only soluble ions that can move freely in solution can be dismantled.

Triacids (HCl, HNO3, H2SO4) tetrabases (NaOH, BA(OH)2, KOH, Ca(OH)2) soluble salts.

Soluble table and formula of common substances.

Cation: OH, NO3, Cl, SO4, S SO3, CO3, SIO3, PO4

Anions are soluble, volatile, volatile, and insoluble.

NH4 solubility, volatile solubility, solubility, solubility, solubility.

K+ soluble soluble solubility.

Na+ soluble.

BA2+ soluble insoluble no.

Ca2+ microsoluble microsoluble microscopic no, no, no.

Mg2+ insoluble soluble soluble micro no.

Al3+ insoluble is not.

Mn2+ insoluble soluble no.

Zn2+ is insoluble and soluble is not soluble and soluble is not soluble and in

Cr3+ is insoluble and soluble is not.

Fe2+ is insoluble and soluble is not soluble and soluble is not soluble and insoluble and insoluble is not soluble and insoluble and insolu

Fe3+ insoluble soluble no.

sn2+ insoluble soluble no.

PB2+ is insoluble and micro-not, no, no.

Bi3+ is insoluble and insoluble is not not.

Cu2+ is insoluble and soluble is not.

Hg+ dissolves not slightly, no, no, no.

Hg2+ solubility is not no, no, no.

ag+ dissolves not slightly, no, no, no, no.

Formula 1: potassium, sodium, ammonium, nitric acid dissolving; Hydrochloric acid except silver mercurous; Sulfuric acid does not tolerate barium lead; Carbon phosphorus dissolves only potassium, sodium ammonium. Alkalis: potassium, sodium, ammonium and barium.

Carbonates are mostly precipitated, but are fully soluble in acids).

Formula 2: potassium sodium ammonium brine soluble, nitrate into the water without a trace, insoluble lead sulfate and barium, as well as silver chloride mercurous, as for phosphate carbonate, most of the water is insoluble, carbon magnesium (magnesium carbonate) sulfur calcium (calcium sulfate) and sulfur silver (silver sulfate), slightly dissolved in clear water,

I always feel that what you think is too complicated, and you shouldn't remember what can be dismantled, and you shouldn't remember what you can't dismantle.

If you can't dismantle it, remember that the rest can be dismantled.

Undismantled such as some common precipitation, calcium carbonate, barium sulfate, silver chloride and so on ......There are also some weak electrolytes, such as NH3, H2S, and in particular, H2O is also a weak electrolyte.

There are also complex ions, silver ammonia complex ions that will be learned in the second and third years of high school.

The rest can be dismantled.

Strong electrolytes that are soluble in water can be removed.

Equation:

NH3·H2O+CO2 (a small amount) ====(NH4)2CO3+ H2O

2. NH3·H2O+CO2 (excess)*****NH4HCO3 ion equation:

1,2NH3·H2O + CO2 (a small amount) ====2NH4+ CO3 2- H2O

2, NH3·H2O+CO2 (excess)*****NH4+ HCO3-

1 and 4 when potassium bicarbonate is in excess: 2HCO3-

2oh-ca2+caco3

CO32-2H2O When there is an excess of clarified lime water: HCO3-

oh-ca2+caco3

When H2O iron reacts with dilute nitric acid, there is a side reaction: Fe2Fe3+

3Fe2+ Therefore, when iron is insufficient, the products are water, nitric oxide and iron ions.

When there is an excess of iron, the products are water, nitric oxide, and ferrous ions.

When the amount of iron is in between, there are both ferrous and iron ions in the product.

When sodium sulfite reacts with dilute sulfuric acid:

When sulfuric acid is insufficient: SO32-

h+=hso3-

When the amount of sulfuric acid is sufficient: SO32-

2h+=h2so3

Or s02

h20)