There are 100 chickens and rabbits, and the rabbit s feet are 16 more than the chickens.

Suppose all 100 chickens are chickens, then the total number of feet is 2 100 = 200 (chickens) The number of rabbit feet is 0, and there are 200 more chicken feet than rabbit feet, when in fact there are 16 fewer chicken feet than rabbit feet. Therefore, the difference between chicken feet and rabbit feet is more than known (200 + 16) = 216 (only), because the rabbit in it is replaced by a chicken. For each rabbit that is replaced with a chicken, the number of chickens will increase by 2 and the number of rabbit feet will decrease by 4.

Then, the difference between the chicken's feet and the rabbit's feet increases (2+4)=6 (only), so the rabbit that is replaced by a chicken has 216 6=36 (rabbits).There are chickens (100-36) = 64 (only).

64 chickens and 36 rabbits.

There are x chickens, then there are 100-x rabbits:

4*(100-x)-2x=16

400-4x-2x=16

6x=-384

x = 64, rabbits: 100-64 = 36.

A: There are 64 chickens and 36 rabbits.

Rabbit: (100 2 16) (2 4) = 216 6 = 36 chickens: (100 4 16) (2 4) = 384 6 = 64 2 means a chicken has two legs, 4 means a rabbit has 4 legs.

2+4 means that 6 feet are needed to form a combination.

Rabbits have more feet than chickens, but rabbits have always had 4 legs, which means that rabbits must have fewer than chickens.

Therefore, rabbits: (100 2 16) (2 4) = 216 6 = 36 instead of 100 4 16) (2 4) = 384 6 = 64.

You are right.

This is to be proved by the hypothetical method.

Assuming that these 100 are all chickens, then there should be 100 2 = 200 feet, and the rabbit has 16 more feet than the chicken, and the actual rabbit should have 200 + 16 = 216 feet, then each chicken and a rabbit have a total of 2 + 4 = 6 legs, then the rabbit should have 216 6 = 36 (only).

The equation is (100 2 16) (2 4) = 36 (only) - rabbit.

Assuming that these 100 are all rabbits, then there should be 100 4 = 400 feet, and the rabbit has 16 more feet than the chicken, and the actual chicken should have 400-16 = 384 legs, then each chicken and a rabbit have a total of 2 + 4 = 6 legs, then the chicken should have 384 6 = 64 (only).

The equation is (100 4 16) (2 4) = 64 (chickens).

That's the truth, I hope the landlord can understand!

Your answer is right.

Rabbit 36 Chicken 64

Suppose there is a rabbit and a chicken has b, and the equations can be listed: a+b=100, 4a-2b=16Then solve the equation to get a=(100*2+16) (2+4), b=(100*4-16) (2+4).

Make a 2-yuan system of equations, set rabbits x and chickens y.

1）x+y=100

2）4x-2y=16

Eq. (2)+2*Eq. (1) gives (2+4)x=2*100+16 and x4*Eq. (1)-Eq. (2) obtains (4+2)y=4*100-16 and obtains y

55 chickens and 45 rabbits.

1. First of all, if there are x rabbits, then there are 100-x chickens, then there are 4x legs of rabbits, and there are (100-x) legs of chickens 2, and then according to "the number of legs of chickens is 70 less than the number of legs of Brother Bi rabbit," that is, the number of legs of rabbits argues that the number of legs of chickens = 70, and the equation is solved.

2. Secondly, if there are x rabbits, then there are 100-x chickens, 4x-(100-x) 2=70, 4x-200+2x=70.

3. The last 6x=270, x=45, 100-45=55 (only). So there are 55 chickens and 45 rabbits.

If there are x chickens with tonghan, there are 100-x rabbits.

2x-4 (100-x) 26

2x-400+4x＝26

6x＝400+26

x Old Liquor 426 6

x=71.

There are rabbits: 100-71 = 29.

First method:

20 2 = 10 (only).

100-10=90 (only).

Rabbit: 90 (1+2)=30 (only) key fierce.

Chickens: 100-30 = 70 (only) scattered.

The second draft method of digging bridges: ,

If there are x chickens, then 100-x rabbits.

2x-4(100-x)=20

2x-400+4x=20

6x=420

x = 70 chickens and 70 rabbits.

If 10 chickens are removed, there are as many chickens and rabbit feet, and at this time, there are all animals.

100-10=90 (only).

Among them, the number of chickens is twice that of rabbits, so, rabbits have.

90 (2+1)=30 (only).

There are 100-30 = 70 chickens

The second method: ,

If there are x chickens, then 100-x rabbits.

2x-4(100-x)=20

2x-400+4x=20

6x=420

x = 70 chickens and 70 rabbits.

First method:

20 2 = 10 (only).

100-10=90 (only).

Rabbit: 90 (1+2)=30 (only).

Chickens: 100-30 = 70 (pcs).

The second method: ,

If there are x chickens, then 100-x rabbits.

2x-4(100-x)=20

2x-400+4x=20

6x=420

x = 70 chickens and 70 rabbits.

20 more chicken feet than rabbit feet, then chicken is equal to 2 times the number of rabbits + 20 2.

So rabbits have (100-10) 3=30.

There are 100-30 = 70 chickens

20 2 = 10 (only).

100-10=90 (only).

Number of rabbits: 90 (1 2) 30 pcs.

Number of chickens: 100-30 70 chickens.

A: There are 30 rabbits and 70 chickens.

The chicken's feet are 26 more than the rabbit's feet, which means that there are 13 more chickens' feet, and minus 13 chickens, the remaining chickens are equal to the rabbit's feet. The number of chickens and rabbits left is 100-13 = 87, because the feet of one rabbit are equal to the feet of two chickens, which is equivalent to one rabbit equal to two chickens, and the number of chickens left in this group is equal to 2 times the number of rabbits, that is, 3 times the number of rabbits in this group is 87, so the rabbits are equal to 87 3 = 29, and the number of chickens is equal to 29 * 3 + 13 = 71.

A: There are 71 chickens.

Because one rabbit's foot is equal to the feet of two chickens, which is equivalent to one rabbit equal to two chickens, the number of chickens left in this flock is equal to 2 times the number of rabbits, that is, 3 times the number of rabbits in this flock is 87, so rabbits are equal to: 87 3 = 29.

There are 70 chickens and 30 rabbits.

Solution: There are x chickens.

Since there are 100 chickens and rabbits, then the number of rabbits is (100-x).

Then according to the fact that there are 20 more chicken feet than rabbit feet, the columnable equation is, 2x-4*(100-x)=20

2x-400+4x=20

6x=420

x = 70 means there are 70 chickens. Then the number of rabbits is (100-70) = 30.

If 10 chickens are removed, there are as many chickens and rabbit feet, and at this time, there are all animals.

100-10=90 (only).

Among them, the number of chickens is twice that of rabbits, so, rabbits have.

90 (2+1)=30 (only).

There are 100-30 = 70 chickens

Suppose 100 are all chickens, then rabbits have: (100 2-20) (4+2)=30 (only).

There are 100-30 = 70 chickens

20 2 = 10 (only).

100-10=90 (only).

Rabbit: 90 (1+2)=30 (only).

Chickens: 100-30 = 70 (pcs).

A: There are 30 rabbits and 70 chickens.