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a: ammonium sulfate b: ammonium nitrate c: ammonium bicarbonate d: chlorine wheel preparation tung can potassium e: phosphate rock powder.

f: Ammonia wheel destroys water.

A: Ammonium sulfate B: Ammonium nitrate C: Ammonium bicarbonate D: Potassium chloride E: Phosphate rock powder F: Ammonia.

Ammonia is an aqueous solution of ammonia gas, which is unstable According to the information in 1,2, f is ammonia.

The stability of ammonium bicarbonate is poor, and it is easy to decompose, and c can be judged as ammonium bicarbonate by 2.

Potassium chloride will not be alkaline and will not release ammonia under the condition of heat and distribution, and 4 d is potassium chloride.

The re-given substance that can react with BA ions to form a precipitate is only barium sulfate, so A is ammonium sulfate, and only ammonium nitrate can not react with barium chloride, so B is ammonium nitrate.

The solubility of phosphate is generally poor, so E is phosphate rock powder.

F is ammonia, E is phosphate rock powder, C is ammonium bicarbonate, A is ammonium sulfate, B is ammonium nitrate, and D is potassium chloride.

nh4)2so4+bacl2=baso4+2nh4cl1.Measure the pH value Dissolved in pure water, and a glass rod was dipped in the manuscript of the sample and tested on the test strip Sodium carbonate is alkaline while sodium chloride is neutral.

2.Addition of acid: Sodium carbonate is produced by adding hydrochloric acid and bubbles.

A: Ammonium sulfate B: Ammonium nitrate C: Ammonium bicarbonate D: Potassium chloride E: Phosphate rock powder F: Ammonia.

If carbon reacts with concentrated nitric acid, carbon dioxide and nitrogen oxides (no no2 content is not necessarily).

When lime water is introduced, nitrogen dioxide reacts with water to form nitric acid, and even if the carbon dioxide produced reacts with lime water, it will be decomposed by nitric acid.

In the first step, the nitrogen dioxide generated by the original reaction will be consumed to produce nitric oxide, and after being introduced into barium hydroxide, only carbon dioxide will be reflected with only barium carbonate to form barium carbonate, and the equation will be written by yourself.

If a sufficient amount of hydroxide is introduced, all carbon dioxide will be consumed. So only nitric oxide remains.

There is precipitation in "one", charcoal is red hot, carbon dioxide is generated, and lime water reacts to form calcium carbonate precipitation.

Ba(OH)2+H2N03==BAN03+H2O water vapor.

Requires 98% concentrated sulfuric acid volume =

The quality of the water required =

Volume of water =

2000* Take 408ml of concentrated sulfuric acid and add it to a beaker with water and transfer it to a 2000 volumetric flask.

Sulfuric acid volume:

Volume of water: The density of water is assumed to be.

In the narrative related to this, the error is: b

The ratio of the amount of alkali used to obtain the maximum precipitation of tartaric acid to the amount of alkali consumed when the precipitation is completely dissolved is 1:1, while the ratio of aluminum salts is 3:1

Because when 1 L of 1mol lkoh solution is added, the maximum precipitate is obtained.

hooc(choh)2cooh+koh=hooc(choh)2cook+h2o

So the solubility of potassium bitartrate is less.

Potassium bitartrate can react with hydrochloric acid.

hooc(choh)2cook+hcl=kcl+hooc(choh)2cooh

The molar volume is greater than at room temperature and pressure, so the gas is insufficient.

Sodium acetate is twice as much as hydrochloric acid.

So after the occurrence of Naac + HCl = HAC + NaCl, the solute becomes 1:1:1 sodium acetate acetate and sodium chloride are known to be greater than chloride ions in the final solution.

This indicates that the degree of ionization of acetic acid is greater than that of acetate ions. (Because hydrolysis makes AC- less, HAC ionization makes it more).

hac = h+ +ac-

AC- +H2O = HAC + OH- Since the former is greater than the latter of the two reversible processes, then H+ is greater than OH- in solution and is acidic. A right.

b is the conservation of materials and that's right.

c is also right, acetate is greater than chloride ions, and acetic acid molecules.

d According to the conservation of charge [H+]+Na+]=[Ac-]+OH-]+Cl-],Na+]= [Cl-]=, it is easy to tell that D is wrong.

The answer is D

Acetate is greater than chloride ions, indicating that the hydrolyzed acetate ions are less than. That is, it is proved that d is not correct, and the concentration of acetate ions is greater than that.

ps.Is it the same person?

1. False ** contains copper and zinc, zinc is more active, ranked in front of h in the metal activity order table, copper and zinc can react with oxygen in the air, and zinc can replace hydrogen in acid solution.

Plan 1: Take the jewelry and roast it on the fire, if there is no change, it is a real ** jewelry; If the jewelry turns black, it means that there is copper in it, which is a fake jewelry.

Plan 2: Take the jewelry and put it in vinegar, if there are bubbles, the bubbles are produced by the reaction of zinc and vinegar in the fake ** jewelry, so it is a fake ** ornament is a mold product.

2. Principle: Iron and copper nitrate are replaced to form copper and ferrous nitrate. So the solid composition may be a mixture of iron and copper, or it may be copper only.

Experiment: Take a sample, put it in a small test tube, and add an excess of finch hydrochloric acid.

Phenomenon and conclusion: If there are bubbles next to the branches, and there are solids left, it means that there is both iron and copper (if possible, the gas can be collected to verify whether it is hydrogen).

If there are no bubbles and the solid does not dissolve, it means that only copper remains.

1. It's not enough to bite the mask with your teeth, people in ancient times were bitten. Kim's first and blind malleability is relatively strong.

2、cu。The replacement reaction between iron and copper nitrate occurs (note: full reaction). Phenomenon: The copper nitrate solution becomes lighter and there is a precipitation of solid products.

1.If the ornament is placed in vinegar, the presence of bubbles proves that it is doped with brass. Yunnayou zn+2h+=zn2+ +h2

2.Copper acacia. Put the powder into salt sensitive acid, if there are bubbles, it means that it contains iron, and if there is none, it means that it is completely copper.

After the reaction of oxide and sulfuric acid, sulfate replaces the original position of oxygen, and both sulfate and oxygen are -2 valence, and the amount of their substances is the same. Find the amount of sulfate is , so the amount of oxygen is , find the mass of oxygen in the original mixture is , so the mass of copper and iron is , and the case is b.

B Add 2 moll of sulfuric acid to consume 50ml, indicating that the reaction consumes H+, iron ions and copper ions all enter the solution, and the consumed hydrogen ions just produce water, and all the oxygen in it comes from the oxide, so the mass of oxygen lost after reduction is option B

Select B from the sulfuric acid can be pushed out of the mixture containing O 1·6g