The master helps me, online and so on, urgent。。。。。

Right-click the local connection --- attributes--- Internet protocol--- write IP (generally intranet, it is casually behind) and then the most important thing is the DNS server address, generally you can search for the DNS server in your area, try to see if it is normal, if not, you can change it, so it is basically solved.

Note: Configure the IP address, gateway, and DNS

The IP address is in the same period as the server.

Enter the IP address of the server in the gateway

DNS also fills in the IP of the server

Is the other computer a dual network card?

You'll need to set it up on both computers.

Open the Start program Accessories Communication Network Installation Wizard in turn.

To the "Select Connection Method" are:

Select "This computer connects to the Internet through a gateway in a residential area or another computer on the network" for your computer

For the other computer, you need to select "This computer is connected directly to it, just follow the steps step by step, and the workgroup should be the same, and after restarting, see if it can access the Internet." No, find the local connection on the computer with direct Internet access, and select "Qiaolian" from the context menu.

Connected to other machines? That should be able to see each other's sharing, if any

The main reason why you can't access the Internet is that you have to go to his machine, right-click on his Internet connection > Properties > Advanced > Allow other network users to connect to the Internet connection through this computer and check OK.

Connecting with other machines?

Ping the local IP address to see.

If that is a ** service, then you can set the client configuration.

If it's a direct connection, then you need to make the twisted pair into the T568B standard.

Connected to the same device).

Configure the IP address, gateway, and DNS

The IP address is in the same period as the server.

Enter the IP address of the server in the gateway

DNS also fills in the IP of the server

Make a ** service on what you call "other machines", such as ccproxy, and don't forget to set the IP address.

If not, take a look here.

Is the host (the machine you said) set up??

The area of the square ABCD is 160cm, and the side length of the curved square of the positive section is 4 10, and the diagonal is 4 10 * 2 = 4 20 = 8 5

e, f are the midpoints of the edge bc and dc, respectively, and ce, cf=2 10

Then in the isosceles right triangle CDE, the hypotenuse EF=2 10* 2=2 20=4 5, and the higher on the hypotenuse is higher than 1 2EF=2 5

The height of the shaded part at the base of the or ridge EF is (square ABCD diagonal) minus (the height on the hypotenuse of the isosceles right-angled three-grip clump cde).

i.e. 8 5 - 2 5 = 6 5

So the area of the shaded part s=1 2*ef*h=1 2*4 5*6 5=60cm

The long side of the square is a, s=s abcd-s adf-s abe-s cef

a 2 - (1 2) * a * (a 2) - (1 2) * a * (a 2) - (1 2) * (a 2) * (a mask 2).

3a^2/8

If the side length of the square is a, a 2=160, then the area of the shadow triangle brother cherry is coincidental.

s=s□abcd-s△adf-s△abe-s△cefa^2-(1/2)*a*(a/2)-(1/2)*a*(a/2)-(1/2)*(a/2)*(a/2)

3a 2 8

Name each of the four formulas in the question ABCD

a gives a pair of shoes = 10

b derives person = 5

c gives two bottles of water = 4

So, d translates to:

One shoe + (one person + 3 bottles of water + one pair of shoes) * 1 bottle of water = 5 + (5 + 6 + 10) * 2 = 47

There is something that can be sent out ** or questions, but it is difficult to get formal protection here, because most people think that they will answer the Vida question.

One shoe is 10 and one shoe is 5

A square is 5

Two bottles of water are 6 and one bottle is 3

So it's 5+5 3=20