20 Mathematics Real Numbers 20, Mathematics 2 Real Numbers Problems

Updated on educate 2024-02-08
19 answers
  1. Anonymous users2024-02-05

    m 2 + 2n - 20 + (n-2) root number 5 = 0, m, n, are rational numbers So m 2 + 2n-20 is a rational number.

    And because 0 is a rational number (n-2) and the root number 5 is a rational number.

    Therefore n-2=0 n=2

    Substituting m 2+2*2-20=0

    m^2=16

    m = 4 or -4

    m+2n=8 or 0

  2. Anonymous users2024-02-04

    m 2 + 2n-2 is a rational number.

    m 2 + 2n - 20 + (n-2) root number 5 = 0, (n - 2) root number 5 is a rational number, n - 2 = 0, n = 2, n = 2 substituting m 2 + 2n - 20 + (n - 2) root number 5 = 0

    m 2 + 2 2-20 + (2-2) root number 5 = 0 m 2 = 16

    m = 4 or -4, n = 2

    So m+2n=8 or 0

  3. Anonymous users2024-02-03

    Because m and n are both rational numbers.

    So the value of m 2+2n-20 is a rational number.

    And because m 2 + 2n - 20 + (n-2) root number 5 = 0 root number 5 is an irrational number.

    So the value of (n-2) is 0, i.e. n=2

    Solving the equation m 2+2n-20 yields m=+4 or m=-4 if m=+4 m+2n=8

    If m=-4 m+2n=0

  4. Anonymous users2024-02-02

    Since m and n are rational numbers.

    According to the closedness of the four operations of rational numbers, it can be known:

    n-2=0 and m2+2n-20=0

    The calculation yields n=or +4

    When m=-4, m+2n=0

    When m=+4, m+2n=8

  5. Anonymous users2024-02-01

    (n-2) root number 5

    How to express it?? Don't understand.

  6. Anonymous users2024-01-31

    m 2 + 2n-20 + (n-2) root number 5 = 0, the first three items are rational numbers, for the term "(n-2) root number 5", if n is not equal to 2, this term is not equal to zero, n-2 is a rational number, the root number 5 is irrational number, "(n-2) root number 5" should be an irrational number, which leads to a contradiction, because rational numbers plus irrational numbers cannot be equal to zero. So n=2, m=plus/minus 4, the answer is 8 or 0.

  7. Anonymous users2024-01-30

    Coordinates: a(-1, 2 2).

    c(3, -2√2)

    b(-1, -2√2)

    d(3, 2√2)

    ab = cd = 4√2

    ad = bc = 4

    When the time of motion of the point p is t1=1s, it moves 2 meters and 2<4 (ad length), so the point p is on the ad. The bottom of BCP is BC, and the height is ABThe area is bc*ab2 = (4*4 2) 2 = 8 2 m2 = m2

    When the motion time of point p is t2=4s, it moves 4 2 meters. 4 (AD length) <4 2 < 4+4 2 (AD+DC length), so the P point is on DC. cp = ad + dc -4√2 = 4 + 4√2 -4√2 = 4.

    The bottom of BCP is BC, and the height is CPThe area is BC*CP2 = (4*4)2 = 8 m2

    When the motion time of point p is t2=6s, it moves 6 2 meters. 4 (AD length) <6 2 < 4+4 2 (AD+DC length), so the P point is on DC. cp = ad + dc -6√2 = 4 + 4√2 -6√2 = 4 - 2√2.

    The bottom of BCP is BC, and the height is CPThe area is BC*CP2 = 4*(4 - 2 2) 2 = 2(4 - 2 2) m2 = m2

  8. Anonymous users2024-01-29

    Solution: 9 11 16

    That is, the integer part of 5 + 11 is 8

    The decimal part of 5+ 11 is 5+ 11-8= 11-3, i.e. a= leased base 11-3

    The same goes for 1 5 - buried oak 11 2

    i.e. 5-11 next to the decimal part of the bend is 5-11-1=4-11, i.e. b=4-11

    1)a+b=√11-3+4-√11=1

    2)a-b=√11-3-(4-√11)=2√11-7

  9. Anonymous users2024-01-28

    5 + (root number 11) = 3 + a, 5 (root number 11) stove source = 1 + b

    10=4+a+b,a+b=6

    3+a-1-b=5+ (root number 11) positive limb -5+ (root number 11) hidden clear state, a-b = root number 11

  10. Anonymous users2024-01-27

    A circle with a diameter of 1 unit length rolls from the origin point to the right along the number axis, and the point on the circle reaches the point 0 from the origin'Then 0'The coordinates of , the purpose of doing this exercise is to illustrate that the formula for the circumference of a circle is the product of the diameter of this method of research and problem solving, which embodies the mathematical method of thinking by straightening the curve.

  11. Anonymous users2024-01-26

    I'll copy the question again for the time being!!

    If you make a mistake, .........

    To do these questions must be mastered: the simplification of absolute values, the removal of parentheses, the simplification of the simplest quadratic radical, the approximate value of the quadratic radical, the operation of the quadratic radical, if you don't understand, just read the book first, the following is my thinking process and solution process. )

    I'm a graduate of junior high school.,There are a lot of math terms in the second year of junior high school that I may not remember clearly.,Please forgive me.,Also,There are a lot of details in these questions.,You have to do more questions.,In order to grasp it firmly.,My QQ is 804010899.,If you still have questions.,Just ask me.,(Hehe,It seems to be a little self-inflicted))).

    Analysis: (1): Simplification of absolute value: |√3-√6|, because 6 is greater than 3, so |√3-√6|=√6-√3

    2√3-3√5|, because 3 is greater than 2, 5 is greater than 3, so 3 5 is greater than 2 3, so |2√3-3√5|=3√5-2√3

    2): Remove parentheses: (3 3+ 6) 3 3 6

    Then they do the math in turn.

    Analysis (1) 12 can be reduced to 3 4 2 3

    2 48 can be turned into 2 16 3 8 3

    Calculate again.

    Analysis: 3 (8 729) 3 8) (3 729) 2 9

    Calculate 3 (8 729) 3 64+ (16 9)+1

    4 ¼(2√2+√3)-⅔pai

    Analysis: Calculated using the multiplicative distributive property.

    2 and 3 also have a pai approximation (I seem to have forgotten what the approximation is, please forgive me, but your math books should have it, or there is also an approximation of the quadratic radical, you can look through it).

    5 Analysis: When x 2 is.

    Original (1

    Because 1 is less than 2, it belongs to type A is less than B.

    Therefore, 1 because 3 is greater than 2, it belongs to type A greater than or equal to B.

    So 3 2 2 squared 4

    So the original formula 1 4 3

    Hope it helps!!

  12. Anonymous users2024-01-25

    1.Solution: Original = 3 6 2 3 3 5+3 3- 6 = 3 3+3 3-3 5-2 6

    2.Solution: Original = 36 + 2 144

    303.Solution: Original formula = -2 9 + 2 + 4 3 + 1 = 37 9

    4.Solution: Original = ---4 3

    5.Solution: x=2

    Original (1

    3Let me tell you,These mathematical symbols can be typed out with special symbols in the Sogou Pinyin input method! It doesn't have to be so troublesome.

  13. Anonymous users2024-01-24

    Very bracket 1 is very simple: first simplify, simplify 6- 3+3 5-2 3+3 3- 6

    That's 3 5 parentheses 2 12 = 2 3 48 = 4 3 original = 3 * 6 3 = 18 3

    The bracket 3 cube root will not be hit(Cube root 8/729 = 9 8 Cube root -64 = 2.)

    16/9 of the root number = 3 16 Original = 9 8-2+3 16+1 Calculate by yourself.

    Bracket 4 Hehe, hey, there's an accurate computer, anyway, the initial elevation can be used.

    Brackets: 5 1 x=1 3 x=2 Element=-1

    Give points to the tired symbol is difficult to hit Hold down the shift button (alt key) with your left hand, then press 41420 in turn, then release your left hand, and the root number will come out. I'm tired.

  14. Anonymous users2024-01-23

    Please, do your math homework yourself

  15. Anonymous users2024-01-22

    Use your own brain! I haven't learned yet.

  16. Anonymous users2024-01-21

    According to the nature of the radical a+1 0 a -1 (1)1-b 0 b 1 (2) because of the left 0, the right b-1 0 b 1 (2) has only one unique value that meets the condition, i.e., b=1 at this time a+1=0 a=-1

    Therefore, a 2009-b 2009=(-1) 2009-1 2009=-1-1=-2

  17. Anonymous users2024-01-20

    1 + 1 / 1 + 1 / 2) + (1 + 1/2 + 1 / 1 / 3) = 3 2 + 7 6 = 8 3 = 2 + 2 3

    1+1/1 + 1/2) sum of square root + (1+2/1 + 1/3) square root + (1+1/3 + 1/4) sum of square root = 3 2+7 6+13 12=15 4=3+3 4

    1+1/1 + 1/2) and the square root + (1+2/1 + 1/3) of the square root + (1+1/3 + 1/4) and the square root + ......1 + 1/2009 + 1/1 of 2010).

  18. Anonymous users2024-01-19

    A and c are negative, b is positive, and |c|Greater than |b|Greater than |a|Original formula = -(2c-a)+[c-b)]-a+b)-[a-c-b).

    a-2c+b-c-a-b+a-c-b

    a-b-4c

  19. Anonymous users2024-01-18

    1.Don't look at the two minus signs, think of it as 2 and compare the size, and the two numbers are multiplied, that is, 2 and, 2 , 2 plus the minus sign becomes - 2

    Next, I will do it in this way, I won't write too much detail) 2(2√7)²=28

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