The full chemistry equation for aluminum in high school

Updated on educate 2024-02-11
10 answers
  1. Anonymous users2024-02-06

    1.Aluminum and hydrochloric acid: 2al+6HCl=2alCl3+3H2 gas.

    2.Aluminum and sulfuric acid: 2Al+3H2SO4=Al2(SO4)3+3H2 gas.

    3.Aluminum and sodium hydroxide: 2Al+2NaOH+H2O=2Naalo2+3H2 gas.

    4.Aluminum hydroxide pyrolysis: 2Al(OH)3 = (heating) Al2O3+H2O

    5.Aluminium sulphate with ammonia: Al2(SO4)3 precipitates 3(NH4)2SO4

    6.Alumina and hydrochloric acid: Al2O3 6HCl=2ALCL3+3H2O

    7.Alumina and sodium hydroxide: Al2O3 + 2NaOH = 2Naalo2 + H2O

    8.Aluminum chloride and sodium hydroxide: AlCl3 + 3NaOH = Al(OH)3 precipitate + 3NaCl

    9.Aluminum hydroxide and sodium hydroxide: Al(OH)3 NaOH=Naalo2+2H2O

    10.Aluminum chloride and sodium hydroxide: AlCl3 + 4NaOH = Naalo2 + 2H2O

    11.Sodium metaaluminate and hydrochloric acid: Naalo2 + HCl + H2O = Al(OH)3 precipitation + NaCl

    12.Sodium hydroxide and hydrochloric acid: Al(OH)3+3HCl=ALCL3+3H2O

    13.Sodium metaaluminate and hydrochloric acid: Naalo2+4HCl=AlCl3+2H2O

  2. Anonymous users2024-02-05

    Al reacts with acid to produce hydrogen, reacts with alkali to form Al(OH)3 with hydrogen, reacts with water at high temperatures, and thermites with metal oxides that are inactive than it.

  3. Anonymous users2024-02-04

    13 are aluminum hydroxide, not sodium hydroxide.

  4. Anonymous users2024-02-03

    1.Aluminum and hydrochloric acid: 2al+6HCl=2alCl3+3H2 gas.

    2.Aluminum and sulfuric acid: 2Al+3H2SO4=Al2(SO4)3+3H2 gas.

    3.Aluminum and hydrogen are buried in sodium oxide.

    2al+2naoh+h2o=2naalo2+3h2 gas.

    4.Aluminum hydroxide.

    Heating is divided into 2Al(OH)3 = (heating) Al2O3 + H2O

    5.Aluminium sulphate with ammonia.

    Al2(SO4)3 precipitates 3(NH4)2SO4

    6.Alumina and hydrochloric acid: Al2O3 6HCl=2ALCL3+3H2O

    7.Alumina and sodium hydroxide: Al2O3 + 2NaOH = 2Naalo2 + H2O

    8.Aluminium chloride.

    With sodium hydroxide:AlCl3+3NaOH=Al(OH)3 precipitate+3NaCl

    9.Aluminum hydroxide and sodium oxide splitting: Al(OH)3 NaOH=Naalo2+2H2O

    10.Aluminum chloride and sodium hydroxide: AlCl3 + 4NaOH = Naalo2 + 2H2O

    11.Sodium metaaluminate and hydrochloric acid: Naalo2+HCl+H2O=Al(OH)3 precipitation+NaCl

    12.Sodium hydroxide and hydrochloric acid: Al(OH)3+3HCl=ALCL3+3H2O

    13.Sodium metaaluminate and hydrochloric acid: Naalo2+4HCl=AlCl3+2H2O

  5. Anonymous users2024-02-02

    1.Aluminum and hydrochloric acid: 2al+6HCl=2alCl3+3H2 gas.

    2.Aluminum and sulfuric acid: 2Al+3H2SO4=Al2(SO4)3+3H2 gas.

    3.Aluminum and sodium hydroxide: 2Al+2NaOH+H2O=2Naalo2+3H2 gas.

    4.Aluminum hydroxide heating is divided into 2Al(OH)3=(heating)Al2O3+H2O

    5.Aluminum sulphate and ammonia: buried Al2(SO4)3 precipitates 3(NH4)2SO4

    6.Alumina and hydrochloric acid: Al2O3 6HCl=2ALCL3+3H2O

    7.Alumina and sodium hydroxide: Al2O3 + 2NaOH = 2Naalo2 + H2O

    8.Aluminum chloride and sodium hydroxide: AlCl3 + 3NaOH = Al(OH)3 precipitate + 3NaCl

    9.Aluminum hydroxide and sodium hydroxide:Al(OH)3 split number NaOH=Naalo2+2H2O

    10.Aluminum chloride and sodium hydroxide: AlCl3 + 4NaOH = Naalo2 + 2H2O

    11.Sodium metaaluminate and hydrochloric acid: Naalo2 + HCl + H2O = Al(OH)3 precipitation + NaCl

    12.Sodium hydroxide and hydrochloric acid: Al(OH)3+3HCl=ALCL3+3H2O

    13.Sodium metabialuminate and hydrochloric acid: Naalo2+4HCl=AlCl3+2H2O

  6. Anonymous users2024-02-01

    2al+3cl2 2alcl3

    4Al+3O2===2Al2O3 (passivated by forming a dense oxide film at room temperature, burning in oxygen).

    4al(hg)+3o2+2xh2o===2 (aluminium and mercury coarse).

    4al+3mNO2 2al2o3+3mn 2al+cr2o3 al2o3+2cr (thermite reaction).

    2al+fe2o3 al2o3+2fe 2al+3feo al2o3+3fe

    2al+6hcl===2alcl3+3h2↑ 2al+6h+=2al3++3h2↑

    2al+3h2so4===al2(so4)3+3h2↑ 2al+6h+=2al3++3h2↑

    2Al+6H2SO4 (concentrated) ==Al2(SO4)3+3SO2+6H2O (Al,Fe passivated in cold, concentrated H2SO4,HNO3).

    AL+4HNO3 (rare) ==AL(NO3)3+NO3+NO3+2H2O AL+4H++NO3 =AL3++NO+2H2O

    CO2 + 3H2O + AlO2 = Al(OH)3 which branch + CO32

    CO2 (foot) + Naalo2 + 2H2O === Al(OH)3 + NaHCO3

    CO2+2H2O+AlO2 Digging Slow Town=Al(OH)3 +HCO3

    co2+c6h5ona+h2o===c6h5oh↓+nahco3

  7. Anonymous users2024-01-31

    2al+3h2so4=al2(so4)3+3h2↑

    2al+2naoh+2h2o=2naaio2+3h2↑

    AL+6HNO3 (concentrated) ==δ==AL(NO3)3+3NO2 +3H2O

    AL+4HNO3 (dilute) ====AL(NO3)3+NO +2H2O

    8AL+30HNO3 (a little thinner)====8AL(NO3)3+3N2O +15H2O

    AL+ HNO3 (very thin) ====AL(NO3)3+N2 + H2O

    8AL+30HNO3 (very rare) ====8AL(NO3)3+3NH4NO3 +9H2O

    8Al+3Fe3O4==4Al2O3+9Fe (thermite reaction is usually ignited with magnesium strip).

    2al+6hcl=2alcl3+3h2↑

  8. Anonymous users2024-01-30

    2al+3cl22alcl3

    4Al(3O2===2Al2O3 (passivated by forming a dense oxide film at room temperature, burning in oxygen) 4Al(Hg)+3O2+2xH2O===2 (aluminum) 4Al+3Mno22Al2O3+3Mn 2Al+Cr2O3Al2O3+2Cr (thermite reaction).

    2al+fe2o3al2o3+2fe 2al+3feoal2o3+3fe

    2al+6HCl===2alCl3+3H2 2AL+6H+=2AL3++3H2 2AL+3H2SO4===AL2(SO4)3+3H2 2AL+6H+=2AL3++3H2 2AL+6H2SO4 (concentrated) ===AL2(SO4)3+3SO2+6H2O (AL,Fe passivated in cold, concentrated H2SO4,HNO3) AL+4HNO3 (dilute)===AL(NO3)3+no +2h2o al+4h++no3 =al3++no +2h2o

    2al+2naoh+2h2o===2naalo2+3h2↑ 2al+2oh–+2h2o=2alo2–+3h2↑ al2o3+3h2so4===al2(so4)3+3h2o al2o3+6h+=2al3++3h2o

    Al2O3+2NaOH ===2Naalo2+H2O Al2O3+2OH =2alo2 +H2O (Al2O3 amphoteric oxide).

  9. Anonymous users2024-01-29

    2al+3o2=2al2o3 ignited.

    2al+3cl2 =2alcl3 ignited.

    2al+3br2=2albr3

    2al +2naoh +2h2o =2naalo2+3h2

    2Al+Fe2O3=Al2O3+2Fe high temperature.

    4al+3mNO2=2al2O3 +3mn high temperature.

    2al+3h2so4=al2(so4)2+3h2

    2al+6hcl =3alcl3+3h2

    4Al2O3=4Al+3O2 is energized.

    al2o3+3h2so4=al2(so4)3+3h2o

    al2o3+2naoh=2naalo2+h2o

    al(oh)3+3hcl =alcl3+3h2o

    al(oh)3+naoh =naalo2+2h2o

    al2(so4)3+

    2al(oh)3=al2o3+3h2o δ

    naalo2+co2+2h2o=nahco3+al(oh)3

    naalo2+4hcl=alcl3+2h2o

    naalo2 +hcl +h2o =nacl +al(oh)3

    naalo2+nahco3+h2o =na2co3 +al (oh)3

    alcl3+3naalo2+6h2o =4al(oh)3+3nacl

    al2(so4)3+6nahco3 =2al(oh)3 +6co2 +h2o+3na2so4

    Note: Some versions of naalo2 are written as: na[al(oh)4]; If the product has gas and the reactant has no gas, it should be marked with a gas mark.

    The ion equation is also very easy to rewrite, it should be noted that insoluble substances such as Al2O3, Al, and gas cannot be disassembled into ionic form.

  10. Anonymous users2024-01-28

    Amphoterior of aluminum, thermite reaction, reaction of aluminium with oxygen group elements and halogen elements.

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