The chemical equation is matched with 2 kinds of results

Upstairs this is a bad story, and this happens all the time.

Methanol is an organic substance (covalent compound): the reason why there are two situations if it is not involved in the charge transfer reaction, do not use it as one of the reducing agents, and the oxidant requires less If it is used as one of the reducing agents according to the participation in the charge transfer reaction, the oxidant needs a lot Of course, the direct product of methanol is carbon dioxide, not other organic substances, so it participates in the charge transfer reaction, and this reaction is a redox reaction

I don't know how you matched, it shouldn't be a dead match.

Left: ammonia n-3 valence, oxygen is 0 valence, c energy in methanol is -2 valence right: nitrogen n is 0 valence, oxygen is -2 valence regardless of carbon dioxide and water, carbon dioxide c + 4 valence The reason why your second formula is like this is because C in methanol is regarded as 0 valence, but the high school chemistry requirements should not be so high, we also encountered it at the time, and both answers were correct during the exam.

Typing is slow.,Please forgive me.。。。

I didn't expect there to be so many, but here I mean, the upstairs I mean is the 1st floor.

This is very normal, there are different proportions of reactants with different proportions of products, in fact, this reaction can be regarded as two separate products.

4NH3 + 3O2 ====2N2 + 6H2O and.

2CH3OH+3O2====2CO2+4H2O, and then it's easy to understand.

Because the oxidizing agent or reducing agent can be different substances in a reaction, there are various coefficients of the equation.

For example, A can oxidize B, and A itself can also undergo redox reaction under certain conditions, so there should be many coefficients for this reaction equation.

Just do the math and see if the sum of the atoms on both sides of the equation is equal.

5CH3OH+12O2+6NH3===3N2+5CO2+19H2OIn the above formula, the number of electrons gained and lost is not equal, so it is wrong.

CH3OH+3O2+2NH3====N2+CO2+5H2OIn the above formula, the number of electrons gained and lost is equal, so it is correct.

Conservation of Atoms, Conservation of Electrons Check!

First of all, there is a conservation of electricity (for the equation you give):

3*x + 6*y = 4*z ……1)

From this equation we know that there are (mathematically) infinite solutions:

Chemical reactions: Depending on the amount of participation, the same reaction will occur.

In fact: all the equations you listed are correct. Because they can be the solution of equation (1).

It's just that, (because the amount is different) the first formula is the second formula plus.

Reaction of CH3OH with O2.

Let's put it this way: the equation you're going to match is actually a combination of two oxidation reactions!

Oxidation reaction of amino acids with oxygen plus.

Oxidation reaction of ammonia with oxygen.

So: it's not surprising that there are two different equations. There may be a few more (which can be proven in mathematics, and if you are interested, you can try it yourself.) let's try...

See if the coefficient can be dated, if you can't make an appointment, it means that you have a mismatch!

n2h4+2h2o2==n2+4h20

The gas has arrows.

I'm not good at labeling. You add it yourself.

c+o2→co

2c+o2=2co

When balancing the chemical formula, the number of protos contained in the substances produced after the reaction should be equal to the number of protos (ions) of each substance before the reaction.

I don't see what you mean!

The trim of the chemical equation includes three aspects: conservation of mass, conservation of charge (ion equation), and conservation of electron gain and loss (redox reaction equation).

For example: Fe3+ +Cu = Fe2+ +Cu2+: This equation is balanced from the point of view of conservation of mass, but from the point of view of conservation of charge and conservation of electron gain and loss, there is no trim!

Another example: 2kmNO4 + 3H2SO4 + 3H2O2 = K2SO4 + 2MNSO4 + 6H2O + 4O2

2kmno4 + 3h2so4 + 5h2o2 = k2so4 + 2mnso4 + 8h2o + 5o2

2kmno4 + 3h2so4 + 7h2o2 = k2so4 + 2mnso4 + 10h2o + 6o2

There can be many, it seems that every equation is right, but only the second one is correct because it satisfies the conservation of electron gain and loss!

c of cn- provides 2e and n provides 3e both of which give clo-, changing it from +1 to -1 cl-.

The 5:2 relationship is then judged based on the equality of the ascending electrons.

Then according to the conservation of elements, the number of atoms in the front and back is equal to 2 carbonate and 5 chloride ions, and then according to the conservation of the total charge, a total of 9 negative charges from the back are negatively charged, and the 7 negative charges of the first two reactants are subtracted, and oh- is deduced to have 2. This is trimmed.

Hope it helps.