When an object is placed in a container, how to find the pressure of the liquid on the bottom of the

The force exerted on the container before it is placed in the object is the pressure of the liquid on it. After putting in the object, the object itself has weight, and will be subject to the buoyancy of the water, the direction of gravity is vertically downward, and the direction of buoyancy is up, then the pressure added to the container is the gravity of the object minus the buoyancy of the water on the object, g thing-f floating. And the quality of the container itself, of course, does not change.

The pressure of the liquid in the container on the bottom of the cup p=pgh, that is, if the water in the container is full, there will be water overflow after putting it into the object, and the depth remains unchanged, according to the formula, the pressure is only related to the density and depth of the liquid (g is quantitatively constant), then the pressure of the liquid on the bottom of the cup is unchanged; However, if the liquid is not full, the liquid level will rise and the depth will increase when the object is inserted, and the pressure will increase according to the formula.

The pressure of the container on the ground is the net force generated by the container and all the things attached to it, and when an object is put into it, it is the force of the g-f float, according to the formula p=f s, so the pressure p also increases.

You can also remember one thing, there are often two situations to calculate pressure and pressure: one is to calculate the liquid to the bottom of the container, the other is to calculate the container to the table, the first is generally according to the formula p=pgh first calculate the pressure, and then use f=ps to calculate the pressure, the second is just the opposite, first calculate the pressure, then calculate the pressure, so it is better to calculate.

The pressure change of the liquid level comes according to the formula p=gh.

1: First of all, find the change of the liquid level, that is, ΔH, to see if the liquid level has increased, and how much? The pressure can be found out, the pressure f capacity = p capacity * s bottom. :

2: The pressure on the ground is f ground = mg + mg (mg: the total gravity of the original container and also quite a lot; mg: the gravity of the object is put behind it), the pressure p ground = f ground s bottom.

It should be noted that f is not necessarily equal to f capacity, and p is not necessarily equal to p capacity.

The increased pressure of the liquid on the bottom of the container is: GH2- GH1

The increased pressure is the weight of the block.

The liquid level rises after the five pieces sink to the bottom, and the pressure on the bottom of the container is divided into three parts, one part is the place where there are no blocks, how big it is or how big, the other part is the weight of the block, and the third part is the pressure of the water on the block to the bottom of the container.

Score Discussion:

1) No water overflow.

Increased pressure = increased pressure (weight) The area at the bottom of the beaker.

2) Originally, the water was full, the object floated (suspended) in the water, and the water overflowed.

The pressure does not increase.

3) The water is full, the object sinks to the bottom, and the water overflows.

Increased pressure = (weight of the object - buoyancy of the liquid on the object) The area of the bottom of the beaker.

p=f s is the definition of pressure, which is true in any case, but it should be noted that this f must be perpendicular to s (if it is not perpendicular, it can only be counted as a component perpendicular to s). For the three containers A, B, and C, although the walls are cambered, tilted, and vertical, F is equal to the weight of the liquid directly above S. In this case, the formula p = density * g * h (on the top side of the bottom of the container), and f is of course the total weight of the container and the total liquid when calculating the pressure between the bottom of the volume and the table.

Why the pressure between the bottom of the liquid and the bottom of the container can only be f.

What about the weight of the liquid part on the top of the s, and the extra liquid weight ** of the outward tilted container? The weight of the insufficient liquid in the inverted container is **?

It turns out that the inverted container, not only the bottom of the container bears the weight of the liquid, but also the wall bears part of the weight of the liquid (the pressure on the wall is perpendicular to the wall, there is a downward component, and the wall has an upward reaction force on the liquid), and in the case of inversion, the bottom of the container not only bears the weight of the liquid itself, but also the wall bears the force transmitted down by pressing the liquid downward, (at this time, the pressure on the wall is perpendicular to the wall, there is an upward component, and the wall has a downward reaction force on the liquid, which can be transmitted to the bottom through the liquid).

The container is cylindrical in shape to calculate:

The increased pressure, by magnitude equal to the force to which the object is subjected;

The increased pressure is equal to the increased pressure divided by the bottom area of the vessel, i.e., the increased pressure of P F float S is also equal to: liquid GH'，h'is the depth at which the liquid increases.

I don't know what to ask.

None of them are right. To find the pressure of the liquid on the bottom of the cup, we must first calculate the actual depth h after the liquid surface rises after putting it into the object, and then calculate it according to the formula of the liquid pressure fiber slowdown p= gh;

If you want to calculate the increase in pressure, you must first calculate the height h of the liquid level rising after putting in the object, then calculate the increase in pressure according to p= g·h, and then calculate the increase in pressure by f=ps.

The increase in the pressure of the cup on the ground is equal to the gravitational force of the object, which should be: f = g object = m object g = object vg

So the increase in the pressure of the cup on the ground is p=fs.

The former is not right, first seek pressure and then seek pressure.

The container is cylindrical in order to calculate the hidden bucket: carry the shot.

The increased pressure, by magnitude equal to the force to which the object is subjected; Dan grinding.

The increased pressure is equal to the increased pressure divided by the bottom area of the vessel, i.e., the increased pressure of P F float S is also equal to: liquid GH'，h'is the depth at which the liquid increases.

I don't know what to ask.

The increased pressure is equal to the gravitational force of the object, and the increased pressure is equal to the increased pressure divided by the area at the bottom of the container.

When the container is heated with an alcohol lamp, the water in the container gradually increases due to the endothermic temperature and reaches the boiling point, and the water in the beaker absorbs the heat of the water in the container, and the temperature will also rise to the boiling point; After the temperature of the water in the container reaches the boiling point, it continues to absorb heat, so it will boil, and the water will continue to turn into water vapor and emit into the air;

Because the temperature of the water in the beaker does not change when boiling, when the water in the beaker reaches the boiling point, it is the same as the temperature outside, and it can no longer absorb heat, and the temperature cannot continue to rise, but the air above the beaker increases due to the increase in temperature and air pressure, so the boiling point of the water in the beaker also increases, so the temperature of the water in the beaker will be lower than the boiling point and cannot boil

So choose AC