Senior 1 Chemistry Is there a correct answer to this question?

Answer: First of all, according to the periodic table, we can know:

X is the He element, Y is the F element, Z is the S element, and M is the Cl element.

Because only this place conforms, this structure (which has three periods) then: a option: non-metallicness: the ability to attract electrons. The closer to the top right, the stronger. So: f>cl>s, i.e., y>m>z

Option B: Atomic Radius: The higher the right corner, the smaller it is.

So: s>cl>f, i.e., z>m>yc option:

Gaseous hydride stability. The more stable the non-metallicity (i.e., the ability to attract electrons), the more stable it is, and the more stable it is in the upper right corner. So:

f>cl>s, i.e., y>m>z

Option D: SCL2

Compliant with 8 electrons stabilized.

Therefore d is correct. Hope you understand.

The correct answer is that it should be y>m>z , b should be z>m>y, the stronger the non-metallic property, the stronger the stability of the gaseous hydride. Therefore c should be y>m>z. The title has been explained as a short-period element, that is, the first three period elements, so it is not difficult to judge that z is a sulfur ion, and the sulfur ion can show positive valence.

m is a chloride ion, so the outermost shell of each atom in the zm2 molecule satisfies the 8-electron stable structure.

S in d has +2 valence.

What do you think, what is the price of S in SO2, the most ** state of S is +6 price (SO3).

D is correct, Scl2 is a covalent compound, and although the electrons are biased towards Cl, the covalent bond electrons are still common.

D is correct, right? The structure is as follows.

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The first question, dear.

This whole question. Thank.

Uh-huh. 1.The pyrite is crushed to increase the contact area.

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(1) Option B, hydrochloric acid is easily soluble in water, while halogenated hydrocarbons are organic substances and are insoluble in water.

2) Options A and D have been analyzed and can be ruled out, but I think there is some truth in both B and C. In item b, the mouth of the test tube is tilted downward to prevent the generated water droplets from bursting to the bottom of the test tube, and the preheating is also to prevent the test tube from bursting. C, the upward tilt of the test tube mouth is to prevent the liquid from boiling and injuring the operator when it is heated, and there is really no safety consideration for preheating the outer wall after drying.

Therefore, I tend to choose C

Analysis: According to the last sentence, D2C2 reacts with water to form the elemental element of C, and the solution turns phenolphthalein red, D2C2 is Na2O2 (sodium peroxide), that is, D is Na, and C is O. Because the outermost electron number a:

c = 2:3, then, a is c (carbon) or si (silicon), because, adjacent, then a is c (carbon) and b is n (nitrogen). c, e are the same as the main group, then e is s (sulfur).

In summary, A is C (carbon), B is N (nitrogen), C is O (oxygen), D is Na (sodium), and E is S (sulfur).

Answer: 1, s

Covalent bonds, ionic bonds, ionic crystals, Na+[:o:o:o:]2-Na+ (dots around oxygen atoms).

4. The solid substance component is excess sodium peroxide and sodium carbonate obtained by reaction, sodium peroxide reacts with water to generate oxygen and sodium hydroxide, sodium hydroxide reacts with hydrochloric acid, sodium carbonate and hydrochloric acid generate carbon dioxide, water, sodium chloride, and the collected gas components are oxygen and carbon dioxide. Let the sodium peroxide be x and the sodium carbonate be y, and the equation is calculated as x=, y=

If the ratio of the number of electrons in the outermost shell of a,c is 2:3, then the number of electrons in the outermost shell of a,c is 2,3 or 4,6The common compound D2C2 reacts with water to form the elemental substance of C, and the solution turns the phenolphthalein test solution red

The solution turns the phenolphthalein test solution red to a base and D2C2 reacts with water to form a C element.

Then d is sodium, c is oxygen, a is adjacent to b, b and c, and the number of outermost electrons in b is 1 a less than the outermost number of electrons in c, and the ratio of the number of outermost electrons in c is 2:3, then b is nitrogen, a is carbon, c and e are in the same main group, then e is sulfur.

1) E s (2) H2ONA+[O:O]2-Na+ (3) A, C, D to form a compound of sodium carbonate Carbonate ions and water react to form bicarbonate ions and hydroxide ions, the second step is the reaction of bicarbonate ions and water to form carbonic acid molecules and hydroxide ions CO3 2- +H2O==HCO3- +OH-

HCO3 - H2O==H2CO3 +OH- (4) reacts with hydrochloric acid with gas should be O2 Yes The others are Na2CO3

e is the element sulfur.

d is the element sodium.

c is the element oxygen.

A is the carbon element.

b is the nitrogen element.

a：c b：n c：o d：na e：s

The element symbol is: s

The hydride stability order of b,c is: H2O NH3 CH4 Then the chemical bond types in z are: covalent bond and ionic bond The compound type of z is:

Ionic compound 3Write the chemical equation for the reaction of D2C2 with AC2: 2Na2O2+2CO2=2Na2CO3+O2 D2C2 reacts with water to form the elemental ionic equation of C:

2na2o2+2h2o=4naoh+o2↑

Unreliable because the mixed solution may contain carbonate combined with barium ions to produce barium carbonate, which is also a white precipitate.

A few drops of dilute hydrochloric acid should be added to the mixed solution first, and then the barium chloride solution should be added, at this time if there is still a white precipitate formed, it indicates that the mixture contains sulfate, and if no white precipitate is formed, it means that there is no sulfate in the solution.

There is another method, which differs in the second natural segment, so to speak:

After the white precipitate is found, continue to add dilute hydrochloric acid to the mixed solution, if the white precipitate disappears, it indicates that there is no sulfate).

Maybe the language isn't too rigorous......I'm no longer familiar with this kind of hypocritical question......Excuse me, you still need to revise it.

Unreliable, it is also possible that the carbonate and barium chloride solution form a barium carbonate precipitate, first sample, add a sufficient amount of dilute hydrochloric acid, and then add barium chloride, if the precipitate is still there, then it is the precipitate formed by sulfate, and the precipitate is not there, it is the precipitation of carbonate.