Are the solution questions the same as the application questions? Urgent!!!!! If there is, then give

If each group has one blue flower, there should be 2 yellow flowers and 6 red flowers.

So a group of flowers is 1 + 2 + 6 = 9 flowers.

There are a total of 360 flowers, 360 9 = 40 groups, so it is divided into 40 groups, then there are 40 blue flowers; 80 yellow flowers; 240 safflowers.

If the orchid is x, then the yellow flower is 2x, and the red flower is 6x

x+2x+6x=360

x=40 2x=80 6x=240, so 40 blue flowers, 80 yellow flowers, and 240 red flowers.

r=3y

y=2br+y+b=360

Solve this system of equations.

b=40 y=80 r=240

Blue flower 40, yellow flower 80, red flower 240

Li Gang rode a bicycle from A to B, first riding a section of uphill road, then riding a section of flat road, after he arrived at place B, Hongda immediately returned to place A, and shared 3 hours back and forth. Li Gang rode 6 kilometers per hour more on the flat road than on the uphill road, and 3 kilometers more per hour on the downhill road than on the flat road. It is known that the first hour is 5 km less than the second hour (the second hour is a section of uphill road, a section of flat road), and the second hour is 3 km less than the third hour, then:

1) How many minutes did it take Li Gang to go uphill?

2) How many minutes did it take to go downhill?

3) What is the distance between A and B?

Analysis: The first hour is uphill, while the second hour is uphill and then flat, and the third hour is flat and then downhill.

1) The first hour is 5 kilometers less than the second hour, the reason is that the second hour is fast, the second hour is 5 6 * 60 = 50 (minutes), the second hour uphill time: 60-50 = 10 (minutes).

2) If the flat road speed is x km h, the uphill speed is x-6 km h, and the downhill speed is x+3 km h

Downhill distance = uphill distance = (x-6) (1+1 6)=7 6*x-7 (km).

Flat road taken in the third hour = distance in the first hour + 3 + 8 - downhill distance.

x-6)+3+5-（7／6*x-7）

9-1／6*x （km）

The speed of going downhill in the third hour: x+3=(7 6*x-7) 7 6-9 x)

Solve the equation and get: x=18

The flat road speed of 18 km h is obtained

3) The distance between A and B = uphill road + half of the flat road taken.

Uphill: 7 6*18-7 = 14 (km).

The flat road taken in the second hour: 5 6 * 18 = 15 (km).

Flat road taken at the third hour: 9-1 6*x =9-3=6 (km).

The distance between A and B: 14 + (15 + 6) 2 = 14 + km).

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The decimal point of the small money is shifted to the right by one place, and her money is equal to the money of Xiaoya, that is, the money of Xiaoya is ten times that of the small money.

Small money = small money = small Asian money =

Let the average speed be x and the distance on the mountain is s, then.

x*（s/15+s/45)=2s

x*(4s/45)=2s

x=45/2x=

Average speed = total distance and total time.

Solution: Let the ascent time be T1, the return time be T2, and the one-line journey is SS=15T1 and S=45T2

15t1=45t2

t1=3t2

Average velocity = 2s (t1+t2).

15t1+45t2)/(t1+t2)

45t2+45t2)/(3t2+t2)=90t2/(4t2)

25 km h.

Solution: 30 (3 5-1 2).

300 km.

A: A and B are 300 kilometers apart.

The distance between the two places is x kilometers.

3/5)x-(1/2)x=30

Solve the equation to get x=300

The midpoint is the 1 2 of the whole process.

The 3 5 of the whole course is more than the 1 2 of the whole course (3 5)-(1 2) = 1 10.

Therefore, the distance between A and B = 30 [(3 5)-(1 2)=30 (1 10)=300 km.

Solution: Let Xiao Ming run x meters and mother run y meters, then Dad runs (2x-20) meters or (2y+10) meters, then: 2x-20=2y+10

x-y=15 meters.

That is, Xiao Ming ran 15 meters more than his mother.