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2)n=(20*14%+30*24%)/(23+v=(20+30)/ c=n/v=
x = or 1000 :1
2 Let the volume of the liquid after the addition of NH3 be V, the unit is L, and the mass of the liquid is.
The solution is v = the second question: m =, mass fraction = 12g (
2) Cl2+2NaOH = NaCl + NaCl + H2O, where the amount of NaClo is . , then the NaCl produced by this reaction is the NaOH participating in the reaction.
The NaOH that reacts with HCl is HCl+NaOH=NaCl+H2O and the Cl- produced by this reaction is.
3) H2+Cl2=2HCl, HCl is H2, Cl2 is, the amount of Naclo is , then the Cl2 of the reaction is.
So the answer is (::2
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It's not very difficult, but I don't want to do the math, I'll tell you how to do it, you can do the math yourself.1) Conservation of solute means that the total mass of the solution and the total mass of the solute remain unchanged, and the mass fraction is divided.
c=n v v=m p (p is the density).
The third question is also to find the concentration of the amount of the substance.
2) From the concentration, the amount of the substance of ammonia is the volume.
The same goes for the bottom Sorry I went to sleep.
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I'm sorry, I'd love to help you, but no, hehe......Ask the teacher!
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This is the question of the structure and properties of matter in the 2012 new course standard paper, the first question is that the sulfur atom has two pairs of lone pairs of electrons, and the other two electrons can form covalent capacitive bonds, so it is sp3 hybridization.
The second question is that the stronger the non-metallic nature, the stronger the stability of the gaseous hydride and the more difficult it is to ionize The weaker the acidity The answer is strong.
The third question should be the focus of what you want to ask This is the most difficult question I have ever seen If you are a candidate from the province of the new course standard paper, I advise you to let go of this question When you encounter such a question in the college entrance examination, you must not do it by hand It will be a great waste of time The answer is as follows.
This is a question that many teachers won't do, and I'm not a shallow learner, and I'm sorry.
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It seems to be a college entrance examination question in Sichuan
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1. The reaction hg22+ +4i- =hgi4]2- +hg can be split into two and a half reactions:
hg22+ +2e = 2hg,e=
hgi4]2- +2e = 1/2hg22+ +4i-,e=?(This is required).
From e= we can find the total electrode potential of the reaction Hg22+ +4I- =Hgi4]2- +Hg as: E Total =
So e=2, hg2+ +4i- = reversible) [hgi4]2-,k stable=? (Requested).
From the reaction [hgi4]2- +2e = 1 2hg22+ +4i-, we can find k for this reaction:
lgk=2e/
k=[hg22+] i-] hgi4]2-].
hg22+]½hg2+]·i-]⁴hg2+]/hgi4]2-]
where [hg22+] hg2+] is the equilibrium constant k0 of the electrode reaction hg2+ +e = 1 2hg22+, and [i-] hg2+] hgi4]2-] is the reciprocal of the k stability we require. k0 can be found:
lgk0=2×
So lgk stable = lgk0-lgk =, k stable =
I'm dizzy, ......Write it backwards, thanks to Robbenlong!
O landlord, the e of hg22+ +2e = 2hg is based on the known reaction of two electrodes:
hg2+ +2e = hg
hg2+ +e = 1/2hg22+
calculated.
The electrode potential is a strength quantity, which is not additive, and must be multiplied by the electric charge (nf) before it can be added.
In fact, the essence of ENF is δg, for the electrode reaction, there is: δg=wmax=-nfe).
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The electromotive force of hg22+ (mercury ion) = hg2++hg is calculated first, and then calculated according to the Nernst equation.
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The solution on the second floor is very good, but there is a small error.
The first question is that the positive and negative electrodes are reversed when finding the electrode potential, resulting in an error in the calculation result, and I can't help you check the other processes of calculating with a calculator. e total = , e positive =
What is required is: e negative =
The second question is the right way.
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The mass is 38% * 50 * 44 73 = , the volume is 19 73 *, if you don't learn the molar volume, use the density you give to calculate the volume, 550 *, 550-55 = 495g
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a, the atmospheric pressure in the glass tube presses the liquid into the bottle, at this time, because of the syringe, the air pressure in the bottle becomes smaller, so the air will also enter, and bubbles will be produced at the bottom.
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