Find a few one time function analytic questions with answers

Fill-in-the-blank questions.

3,4) The coordinates of the point with respect to the x-axis symmetry are The coordinates of the point with respect to the y-axis symmetry are The coordinates with respect to the origin symmetry are

The distance from point b(5, 2) to the x-axis is the distance to the y-axis and the distance to the origin is

With the point (3,0) as the center of the circle, the coordinates of the intersection point of the circle with the x-axis of radius 5 are the coordinates of the intersection point with the y-axis

If the point p(a3,5 a) is in the first quadrant, then the range of values of a is

Xiaohua uses 500 yuan to buy a commodity with a unit price of 3 yuan, and the remaining money y (yuan) and the number of pieces of this commodity purchased x (pieces).

The function relationship between x is that the value range of x is

The value range of the independent variable x of the function y= is

When a=, the function y=x

is a proportional function.

The image of the function y= 2x 4 passes through the quadrant, and the area of the triangle enclosed by the two axes is the perimeter of

Once the image of the function y=kx b passes through the point (1,5) and intersects the y-axis at 3, then k= b=

10 If the point (m, m 3) is in the function y=

x 2, then m=

y is proportional to 3x, and when x = 8 and y = 12, then the analytic formula for y and x is

12 function y=

The image of x is a line that crosses the origin and (2,

, this straight line passes through the first quadrant, and when x increases, y follows

The function y=2x 4, when x y<0

14 If the area of the triangle enclosed by the image of the function y=4x b and the two axes is 6, then b=

2. The image of a known primary function is found through points a(1,3) and points (2, 3),(1); (2) Determine whether point c(2,5) is on the function image.

3. It is known that 2y 3 is proportional to 3x 1, and when x = 2, y = 5, (1) find the functional relationship between y and x, and indicate what function it is; (2) If the point (a)

2) On the image of this function, find a

4. The image of a primary function, the abscissa of the intersection point m with the line y=2x 1 is 2, and the ordinate of the intersection point n with the line y=x2 is 1, find the analytic formula of this primary function.

It is known that the line y=kx+1 intersects with the x-axis at the point a, with the y-axis at the point b, and with the parabola y=ax*x-x+c at the point a

and points c (1 2, 5 4), the vertex of the parabola is d. Problem 1: Find the analytic formula of straight line and parabola;

The straight line y=kx=1 passes through the dot(1 2,5 4), so k=(1 2), y=1 2x+1 so a(-2,0),b(0,1).

So the parabola y=ax*x-x=c passes through the points a(-2,0) and c(1 2,5 4), bringing the two points a and b into y=ax*x-x=c, resulting in a=-1, c=2

So the parabolic analytic formula is y=-x*x-x=2

1.There are two straight lines, l1:y=ax+b and l2:y=cx+5. Student A finds their intersection as (3,-2); Student B finds the intersection of C because he has copied them incorrectly (,, try to write the analytic formula of these two straight lines.

A solves their intersection as (3,-2), -2=3a+b, -2=3c+5 B solves their intersection as ( because he sloppily copied C wrong, but this point still satisfies the straight line l1:y=ax+b, so there is:

Combining the above three equations, we get:

a=-1，b=1，c=-7/3

So, the analytic formula for these two lines is:

l1:y=-x+1 and l2:y=-7 3x+5

The coordinates of b on the graph should be (0,2) The first question on the graph is wrong: Let the analytical formula of the primary function be y=kx+b and know that a( -3k+b=0 is solved to obtain b=2 b=2 k=2 3 so the analytical formula of the primary function is y=2 3x+2

Second question: The area of the triangle is 8 s = base * height 2 so base * height = 2s = 16

That is, ac*b0=16 because the coordinates of point b are (so b0=2 ac=16 b0=16 2=8

Since the a coordinate is (so ao is equal to 3

co=ac-ao=8-3=5 So the coordinates of point c are (and then find the analytic formula according to the way of the first question.

Get y=-2 5+2

Solution: (1) From the title, the cost of going to supermarket A to buy N rackets and kn table tennis balls is yuan, and the cost of going to supermarket B to buy N rackets and K table tennis balls is [20N+N(K-3)] yuan, and the solution is K 10;

From, the solution is k=10;

From, the solution is k=10;

When K is 10, it is more cost-effective to go to supermarket A to buy it;

When k = 10, it is the same to go to both supermarkets A and B;

When 3 k 10, it is more cost-effective to go to supermarket B to buy it

2) When K = 12, the purchase of n rackets should be accompanied by 12n table tennis balls If you only buy it in A supermarket, the cost is yuan);

If you only buy in supermarket B, the cost is 20n + (12n-3n) = 29n (yuan);

If you buy N rackets in supermarket B, and then buy insufficient table tennis balls in supermarket A, the cost is 20N+ yuan).

Obviously, the most cost-effective purchase plan is: buy N rackets at supermarket B and get 3n table tennis balls for free, and then buy 9n table tennis balls at 10% off at supermarket A

Let x=0 y=1,; Let y=0 x= 3, so a(3,0), b(0,1), so ab=2

So d( 3 2, 1 2).

Let c(x,y) because |ca|=|cb|=2, so (x- 3) +y =x +(y-1) =4, the solution gives x= 3 y=2, so c( 3,2).

The midpoint of the cd is (3 3 4, 5 4).

Because the crease EF is parallel to AB, it can be set to y=- 3 3x+b, and substituting the c coordinate to get b=3

So the analytical formula for the crease ef is y=- 3 3x+3

Answer: 1: m=-2

2：b=13：y=-2x-3

4：m=05：c

6：y=(-1/2)x-1

7：y=2x-4

Analysis: 1: 2m-1<0 m -3=1 m=-22: by the meaning of the title b(0,1) so b=1

3: Let the equation be y=-2x+p(-2,1), so p=-3 so y=-2x-3

4: m(0,4) Therefore, 2m+4=4, m=05: omitted, can be brought in one by one.

6: Make your own drawings.

7: y=2x-1 --y=2(x-2)-1 --y=2(x-2) i.e. y=2x-4

Give it to me!

If X is transported from place A to place A, then there are 16-x (0<=x<=16) to be transported to place B

15-x(0<=15-x<=12,x>=3) from B to A and 12-(15-x)=x-3 to B

0<=x-3<=12, 3<=x<=15)

The value range of x is 3<=x<=15

So the total shipping cost is: y=500x +400(16-x) +300(15-x)+600(x-3) =400x +9100

This is an incrementing one-time function, when x = 3, y has a minimum value, so.

A shipped to A 3 units, shipped to B 13 units; b Shipped to A 12 sets, shipped to B 0 sets to minimize the freight.

Suppose A to A transports X, you can get the total freight: 500X+400(16-X)+300(15-X)+600(X-3), simplified to 400X+9100, to make this value minimum, should make X the minimum value, that is, 3, so it can be obtained that A-> A 3, A->B 13, B-> 12.

It is known that the line y=kx+1 intersects with the x-axis at point a, with y-axis at point b, and with the parabola y=ax*x-x+c at point a and at point c(1 2,5 4), and the vertex of the parabola is d. Problem 1: Find the analytic formula of straight line and parabola; ；The straight line y=kx=1 passes through the dot(1 2,5 4), so k=(1 2), y=1 2x+1 is a(-2,0),b(0,1). So the parabola y=ax*x-x=c passes through the ode or the points a(-2,0) and c(1 2,5 4), and brings the two points a and b into y=ax*x-x=c, and the result is a=-1, c=2 So the parabolic analytic formula is y=-x*x-x=2

1.For the function y=(k-3)x+k+3 (k is constant), when k =-3 and k≠-3, it is proportional, and when m=3, the function y(m-1)x to the power m-2 + 2m represents a primary function, and its expression is y=2x+6

Analysis: It is a proportional function, which is defined by a proportional function as y=kx (where k≠0).

i.e. k-3≠0 and k+3=0

For a one-time function, the number of x must be 1, i.e. (m-2)=1

2.When the image of the function y=-2x+1 is translated upwards by 1 unit length, it passes through the 124th quadrant; Shifting between l1:y=1 2x downwards by 2 units will give you between l2:

y=1 2x-2 The straight line L2 does not pass through the second quadrant, and it can be judged from the above translation that the positional relationship between y=3x and y=2+3x is y=3x+2 is obtained by y=3x moving up 2 units, and the positional relationship between y=-x-1 and y=-x+3 is y=-x+3 is obtained by moving y=-x-1 upwards by 4 units.

Analysis: Solution: Let the primary function be y=ax+b, then.

If the image is moved up by one unit, then y=ax+b+1

If the image is moved down by one unit, then y=ax+b-1

If the image is moved one unit to the right, then y=a(x-1)+b

If the image is moved up one unit, then y=a(x+1)+b

3.If the image of the primary function y=kx+b passes through the first quadrant and intersects the negative half axis of the y-axis, then (b).

a. k>0 b>0 >0 b<0 <0 b>0 dk<0 b<0

Analysis: When x=0, y=b because the image intersects with the negative half axis of the y-axis, then b<0

Because y=kx+b passes through the first quadrant.

Draw to know. When the function image passes through the first three or four quadrants, the slope k>0

4 If the primary function y=kx+bmu where kb> 0, then all the images of the primary function that meet the requirements must pass through (b).

a, the first two quadrants, b, the second and third quadrants, c, the third and fourth quadrants, d, the first four quadrants.

Analysis: kb>0

k > 0 , b > 0 The image passes through quadrants: 1 2 3

k > 0 , b < 0 The image passes through quadrants: 1 3 4

k < 0 , b > 0 Image Quadrant: 1 2 4

k < 0 , b < 0 The image passes through quadrants: 2 3 4

There are two scenarios:

k<0 b<0 passes through quadrants 2nd, 34.

k>0 b>0 passes through the first, two, and third quadrants.