How to solve the mathematical fraction, solve the mathematical fraction

Updated on educate 2024-03-12
11 answers
  1. Anonymous users2024-02-06

    Divide and merge.

    Be careful, the fraction is very simple.

  2. Anonymous users2024-02-05

    For the equation, you can first see if the denominator can take zero, if not, you can multiply it to the other side of the equation, and then the solution is OK.

  3. Anonymous users2024-02-04

    The addition of the first pass differentiation to the same denominator fraction. The numerator and denominator in the resulting fraction are integers (mononomial or polynomial).

  4. Anonymous users2024-02-03

    Solution, suppose the ship's velocity in still water is x kilometers per hour.

    Rule. The downstream time is 150 (x+3).

    The silver flow time of retrograde stockings is 150 (x-3).

    According to the title, there are: 150 (x+3) 4 noisy 3 = 150 (x-3). 4x - 12 = 3x + 9

    Solution. x = 21 (kilometers per hour).

    A: The speed of the boat in still water is 21 km/h.

    Thank you

  5. Anonymous users2024-02-02

    Set the speed of the teasing in still water at x km/h.

    150 (x-3) = 4 3 * 150 repentance (x+3).

    x=21

  6. Anonymous users2024-02-01

    The square of the brightness of b is -2b + 1/a-ab = (a-ab) [b 2-2b+1] = a(1-b) (b-1) 2=a (1-b).

    The cube of 9(y-2x) is divided into the square of 12(2x-y) of hail and the source key hui (y-x) = 12(2x-y) 2(y-x) [9(y-2x) 2(x-y)].

    4(2x-y) 2(x-y) [3(2x-y) 2(x-y)]xy+2y)-(x+2)-4 squared of x

    xy+2y)-(x^2-4)/(x+2)(xy+2y)-(x-2)(x+2)/(x+2)y(x+2)-(x-2)

    x=3,y=7

    y(x+2)-(x-2)

  7. Anonymous users2024-01-31

    Greater than 1 and less than 9. That's how you understand a b 0 then a, b heterogene.

  8. Anonymous users2024-01-30

    First of all, x≠1, otherwise it is meaningless, and secondly, because 0, it means a different sign, so 1< 9, or x 9, x 丨, does not meet the requirements, and the answer is 1 x 9

  9. Anonymous users2024-01-29

    1<x≤9。First x≠1, and then in two cases, when x 1, there is x 9,; x 1, there is x 9, contradictory; So last 1 x 9

  10. Anonymous users2024-01-28

    It's a question of ab unequal signs. Analyze whether the fractional denominator numerator is different and the same number.

  11. Anonymous users2024-01-27

    When (2+x) (2-x)=0, x=-2

    When (2+x) (2-x)>0, the equation is equivalent to (2+x)*(2-x)>0 and the range of x is (-2,2).

    The value range of x is [-2,2).

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