Why is it wrong to add a small amount of sodium bisulfite 2HSO3 Ba2 2OH BaSO3 to precipitate SO32 2H

I feel that because a small amount of sodium bisulfite is added to the barium hydroxide solution, it means that BA(OH)2 is excessive, and the HSO3 roots should be used up, so there should be no SO3 roots left, and the equation should be HSO3-+(BA2+)+OH-)==BASO3 (precipitation) + H2O. If barium hydroxide is added to the sodium bisulfite solution in reverse, it is the formula in the title above.

Pay attention to who is in small amount and who is excessive, this kind of question is often made here.

Whoever has more can write ionized ions without proportional coefficients, such as (Ba2+)+OH-), and a small amount cannot, such as excess sodium bisulfite 2HSO3-+2OH-+BA2+=BASO3+SO32-+2H2O.

It is still a matter of quantity, a small amount of sodium bisulfite, so in the reaction formula, the bisulfate is completely reacted, and the hydroxide or barium ions do not have to be fully reacted according to 2:1.

A small amount of sodium bisulfite HSO3-+OH-+BA2+=BASO3+H2O

Excess sodium bisulfite 2HSO3-+2OH-+BA2+=BASO3+SO32-+2H2O

You wrote about sodium bisulfite overdose.

It should be Ba(OH)2+2NaHSO3===NA2SO3+2H2O+BASO3

Summary. The sodium bisulfate solution reacts with the barium hydroxide solution until the sulfate is completely precipitated and shouts, why is the barium hydroxide missing a hydroxide root, so don't you Zheng Shouchong become one-half.

I know, how do you look at the complete precipitation of an ion like this, is it a few to a few, is there a one-to-one?

If the valence state of the two is slightly equal, then it is 1 to 1, otherwise it is not 1 to 1.

The second question is why the solution added in the air must be nitric acid.

Why is it certain that there are chloride ions, so why are they determined to have chloride ions, which are barium chloride ions.

Summary. Not reacting. There are no equations.

Because barium sulfite is soluble in hydrochloric acid. If it is barium nitrate, it will react with sodium bisulfite, and what is produced is barium sulfate precipitation and NO gas. The reason is that the partially ionized H+ of nitrate ions and HSO3- ions forms a strongly oxidizing nitric acid.

Not reacting. There are no equations. Because barium sulfite is soluble in hydrochloric acid.

If it is barium nitrate, it will react with sodium bisulfite, and what is produced is barium sulfate precipitate and no gas. The reason is that nitrate ions and H+ partially ionized with Hso3- ions per mu form a strong oxidizing nitric acid.

I don't have nitrate in my question.

In the solution, pure rubber HSO3-reversible=H+ SO32- is said to have BA2+ SO32-=BASO3 There is no need to consider that BaSO3 is suppressed by H+ lysoids, because the acidity is not strong enough.

Didn't make it clear.

Not reacting. It is not reactive, because the precipitated baso3 produced will dissolve in the resulting hydrochloric acid.

Why does excessive barium hydroxide solution occur immediately when an excess barium hydroxide solution is added to a mixed solution of dilute hydrochloric acid and sodium sulfate? Isn't the priority response followed?

Hello. For chemical reactions, there is no such thing as a preferential reaction, if a chemical reaction can occur, it should be a reaction at the same time, but the difference is that the rate of the chemical reaction is affected according to the concentration, temperature, pressure, etc. For example, as you mentioned, when barium hydroxide is added, it will react with dilute hydrochloric acid and sodium sulfate at the same time, so it will immediately produce precipitation, and the concentration of barium hydroxide will gradually decrease.

The 2nd floor is nice, I'll correct it.

1.Barium bicarbonate and a small amount of sodium in the hydroxide wheel.

React. ba2+ +hco3- +oh- =baco3↓ +h2o

2.Barium bicarbonate reacts with excess sodium hydroxide.

ba2+ +2hco3- +2oh- =baco3↓ +co3 2- +2h2o

Barium bicarbonate is insufficient in amount, completely reacts, barium ions with bicarbonate.

The ratio of ions should be 1:2).

3.Reaction of sodium bisulfate with a small amount of barium hydroxide.

The ionization of sodium bisulfate is: NaHSO4 = NA+ +H+ +SO4 2-(acid salt.

Only bisulfate can be written like this, everything else has to be written as cationic.

acid ion).

So the ionic equation for this reaction.

It should be 2H+ +SO4 2- +Ba2+ +2OH- =2H20 + BaSO4 (barium hydroxide does not mess with the sufficient amount, complete reaction, the ratio of barium ions to hydroxide ions should be 1:2).

4.Sodium bisulfite.

It reacts with dilute sulfate bent acid.

hso3- +h+ =h2o + so2↑

5.Sodium bisulfate reacts with barium hydroxide to neutralize just that.

ba2+ +2oh- +2h+ +so4 2- =baso4↓ +2h2o

First of all, barium hydroxide is also a base, and the reaction of sulfuric acid and barium hydroxide is also a neutralization reaction.

Secondly, even if the sulfuric acid reacts with sodium hydroxide first, sodium sulfate and water are obtained. Sodium sulfate will immediately react with barium hydroxide to obtain barium sulfate precipitate.

Third, these substances are ionic compounds, and they become ions when they enter the water. In essence, this reaction is a reaction between hydrogen ions and hydroxide ions, and a reaction between sulfate and barium ions.

The reaction of insoluble bases and acids is also a neutralization reaction, and the reaction to obtain insoluble salts is also a neutralization reaction.

As long as acid + alkali = salt + water, and no redox occurs, almost all of them are neutralization reactions.

You can't rote memorizing concepts. The so-called neutralization reaction first refers to the reaction of hydrogen ions and hydroxide groups in the solution first. After adding H2SO4, the hydroxide in the solution will react with the added hydrogen ions, and the barium ions in the solution will react with the added sulfate, which is macroscopically reflected in the reaction of barium hydroxide and sulfuric acid.

This is equivalent to the solution has sodium ions, hydroxide ions, barium ions, dilute sulfuric acid can be regarded as hydrogen ions and sulfate ions, when dilute sulfuric acid is added to the solution, hydrogen ions and hydroxide ions react, sulfate ions and barium ions react, this is artificially thought that sulfuric acid reacts with barium hydroxide first, and indeed in the solution, barium hydroxide has been dissociated.

The resulting BaSO3 is soluble in acids.

The principle of the reaction: sulfur dioxide is introduced into the barium hydroxide solution to produce precipitation. SO2 + BA (OH) 2 = = BASO3 + H2O, white precipitate, continue to pass SO2, under acidic conditions, BASO3 can be dissolved in acid, and the acid barium sulfite BA(HSO3)2 soluble in water is obtained

When sulfur dioxide is introduced into the barium hydroxide solution, a small amount of sulfur dioxide is produced, resulting in Baso3 precipitate SO2+

ba(oh)2

baso3↓+

H2O continues to pass SO2, and under acidic conditions, BaSO3 can be dissolved in acid, and the acid sulfite Ba(HSO3)2 that can be dissolved in water is obtained, so the precipitation is dissolved, and the reaction is as follows:

so2+ba(oh)2

baso3↓+

h2obaso3

so2h2o

ba(hso3)2

Sulfur dioxide is introduced into a barium hydroxide solution to produce a precipitate.

SO2 + BA (OH) 2 = = BASO3 + H2O, white precipitate, continue to pass SO2, under acidic conditions, BASO3 can be dissolved in acid, and the acid barium sulfite BA(HSO3)2 soluble in water is obtained

I'm here to answer your questions.

The mixed gas of sulfur dioxide and sulfur trioxide gas is passed into a sufficient amount of barium hydroxide solution, and the following two reactions occur.

Ba(OH)2+SO3+=BASO4 +H2OBA(OH)2+SO2 BASO3 H2O, so the formation is barium sulfate and barium sulfite precipitation.

Barium hydroxide, barium ions react with sulfate first, and barium sulfate precipitates are generated, and there is no barium, which is equivalent to reacting with barium hydroxide first.

Sodium hydroxide and barium hydroxide are dissolved in water as Na+

ba2+oh-

The ionic form exists, so after the addition of sulfuric acid, it is the reaction of OH- in the solution with H+ in sulfuric acid, and the reaction of BA2+ with SO42- in sulfuric acid.

Neutralization reactions are prioritized.

Therefore, sodium hydroxide first reacts with sulfuric acid to form weaker electrolyte water "as opposed to barium sulfate".

This reaction.

It doesn't matter what the order is, because the two bases given are both strong bases

It can be completely ionized.

Oh - while. The essence of acid and base reactions is:

Reaction of oh- and H+.