In the second year of junior high school, the average speed of physical measurement is asked

1. If it is a simple uniform linear motion, then the velocity of this motion at any moment is equal, and the average velocity is equal to the total distance s divided by the total time t.

2. If it is a linear motion composed of several uniform linear motions, it should be solved in sections. The average speed of the first leg of the journey v1=s1 t1; The average speed of the second leg of the journey v2=s2 t2; The average speed of the third leg is v3=s3 t3; ......In junior high school, the type of rectilinear motion that I was exposed to would not exceed 3 paragraphs, and even 3 paragraphs were very rare); And if you ask the average velocity of the whole motion v total = (s1 + s2 + s3) (t1 + t2 + t3) !Note that it is not equal to (v1+v2+v3) 3 !!

3. In all linear motion, there are two special cases, one is called the intermediate moment speed, and the other is called the intermediate distance speed, both of which are applicable to the second situation I talked about above. The average velocity of the intermediate type v=(s1+s2) (t1+t2)=(s1+s2) 2t [because t1=t2] =s1 2t + s2 2t [take the molecule apart] =v1 2 +v2 2=(v1+v2) 2;

Similarly, the average velocity of the intermediate distance type v=(s1+s2) (t1+t2)=s (t1+t2) [because s1=s2=s 2,t1=s1 v1=s 2v1, t2=s2 v2=s 2v2] =s (s 2v1+s 2v2) [about all s].

1 (1 2v1+1 2v2) [numerator denominator ventilation, multiply by 2v1v2] = 2v1v2 (v1+v2).

The above are all the situations of finding average speed encountered in junior high school for your reference!

By definition, the average speed is equal to the total distance traveled divided by the total time.

Frequently asked questions are: The speed of the first half of the distance is v1, and the speed of the second half of the distance is v2, then the average speed is v=

On the other hand, if the speed of the first half of the time is v1 and the speed of the second half of the time is v2, then the average speed is v=(v1+v2) 2

In fact, no matter how you come up with the question, you can definitely figure it out according to the definition.

Total distance divided by total time = average speed.

The total distance is divided by the total time, and the key is in the total.

Average speed by definition.

Equal to the total distance divided by the total time.

There are often questions about early ignition and repentance: Yes, the speed of the first half of the journey is v1, and the speed of the second half of the distance is v2

then the average velocity v=

On the other hand, if the speed of the first half of the time is v1 and the speed of the second half of the time is v2, then the average speed is v=(v1+v2) 2

In fact, no matter how you come up with the question, you can definitely figure it out according to the definition.

1. Knowledge and skills.

1.Learn to correctly measure time, distance, and average speed with a stop watch and scale.

2.Deepen your understanding of average speed.

2. Process and methodology.

1.Master the basic skills of using physical instruments – stops and scales.

2.Experience the overall process of designing experiments, operating experiments, recording data, and analyzing experimental results.

The physical quantities we need to know are the distance traveled and the time taken during the motion of the object. The distance can be measured with a ruler, and the time can be measured with a meter. Today we will use a watch and ruler to measure the average speed ourselves.

In physical experiments, we generally use stop watches and photoelectric timers to keep time. Mechanical stop meters can be read, while more advanced electronic systems can read it, even 10 -6 s or less. When observing the stop watch, how many minutes does each scale represent when each hand is turning?

How many seconds? Imagine measuring the average speed at which you are walking normally, what quantities do you need to measure? Just measure the distance traveled and the time it takes, and then utilize the formula.

Just do the math.

Experimental Procedure: 1 Group: At least 6 people in each group or adjusted according to the actual number, no less than 6 people.

3. Instruct each group to select a starter, a tested player, and one person to be responsible for recording.

4 After one person completes the measurement, the roles are rotated in order, and the tested students can also race walk or run.

5.Instruct students to design data** and calculate the average velocity.

6.Let the students design an experiment plan and actually measure the average speed of a bicycle, record the corresponding data, and the teacher will guide them. The average speed of the measuring bicycle can be a little farther, and the teacher can determine it according to the size of the playground or the actual situation.

1.Purpose, principle and equipment of the experiment.

Purpose: To measure the average speed of the trolley with a scale and a stop gauge.

Experimental principle: v=st The physical quantities that need to be measured are distance and time.

Equipment: inclined planes, trolleys, scales, stop watches, metal sheets.

2.Experimental Procedure.

1.Keep the inclined plane at a certain slope, put the trolley at the top of the inclined plane, and place the metal sheet at the bottom of the inclined plane, and measure the distance s that the trolley will pass

2.The time t1 from the top of the inclined plane to the impact of the metal sheet was measured.

3.According to the measured s and t, the average speed v of the trolley through the inclined plane is calculated.

4.Move the metal sheet to the midpoint of S, measure the time T taken by the trolley to slide from the apex of the inclined plane to the half of the inclined plane S, and calculate.

The average speed of the trolley through the first half of the journey v

The average velocity is equal to the time of bit removal, v x t

The ratio of the displacement x of the object to the time t it takes for this displacement to occur is called the average velocity. The average velocity corresponds to a displacement over a period of time or a period of time, and the direction of the average velocity is the same as that of the displacement. The unit is: Ant let m s (or m·s).

Note the difference between the average velocity, which is the time it takes for an object to travel a distance and the time it takes to occur, and the average simple velocity which is the ratio of the displacement of the object's retaining nucleus to the time it takes for this displacement to occur. The average velocity is a completely different concept from the magnitude of the average velocity. The magnitude of the average velocity is always less than or equal to the average velocity.

Hope it helps

What you do is called the "velocity average".

The physical average speed is equal to the total distance traveled divided by the total time. The average speed and the average speed are different.

In this problem, v=s total t total = 100m (6s+7s)=

The physical average speed is equal to the total distance traveled divided by the total time. The average speed and the average speed are different. So just divide the total distance of 100m by the total time of 13 seconds.

v=s total t total = 100m 13s=

In the physics of the flat problem, v=s total t total = 100m (6s+7s)=

The average speed is equal to the total distance traveled divided by the total time. The average speed and the average speed are different.

No, divide the total distance by the total time.

No, it should be: let's set the total distance to be s, and the other half to be 2 s

Find the first half of the velocity first, then find the second half of the velocity, and then use the formula v 2 times v1 v2 v1 v2

If it's not right, just ask.,Thank you for the reference!!(Formulas are suitable for this kind of question).

No, divide the entire distance by the time it takes to complete the journey.

It should be (50m+50m) (6s+7s)=

No, it's like finding an average score, dividing the total distance by the total time.

The average speed of the whole journey should be 100 meters divided by the total time of 13 seconds.

Wrong. The average velocity is removed with bits with time. That is, the distance divided by the time. Just 100 13 and you'll be done.

No, divide the total distance by the total time.

No, because the problem is the average speed of the entire journey, and it is enough to divide the total distance by the time taken. 100÷（6+7）＝？

Divide 100m directly by the time 13 seconds. That's it.

Wrong, that's not an average speed. (50+50) 13=100 13 should be used

The total distance divided by the total time is the average speed...

No, the total displacement (distance) should be divided by the total time, i.e. 100 13 =

Your algorithm is not right!

Average speed physically = total distance traveled The time taken.

So the correct answer should be 100m 13s is about equal.

Average speed = the time taken for the entire journey. For example, if a car is driving from A to B, the speed of the first half of the journey is 15 km h, and the speed of the second half of the journey is 10 km h. Find the average speed for the entire distance.

Let the whole distance be s, then the time taken for the first half is t1=s 15h, and the time taken for the second half is t2=s 10h

The average velocity v=s t=s (s 15+s 10)=12km h.

The linear change of velocity is averaged, and the nonlinear change can be considered as integral.

It must be made clear that there is a strict correspondence between distance s and time t in the average speed. Specify which leg of the road (or average speed over time) you are looking for. Formula:

For example, a train travels from A to B at a speed of 54 km/h for an hour, stops for an hour, and then travels at a speed of 72 km/h for one hour to reach its destination. Find the average speed of the train over the course of the train.

Analysis: The average speed of the whole journey is by no means the average of the two speeds (54+72) 2, and the total distance must be divided by the total time taken in the whole process.

The first leg of the journey is S1

s1=v1t1=54 km).

The second leg of the journey is S2

s2 = v2t2 = 72 1 = 72 (km).

Total distance s=s1+s2=135+72=207 (km) time t=t1+t'+t2=hours).

v=s t=207 km 4 hours = km hours.

In junior high school physics, average speed is defined as the ratio of distance and time.