Eager to find 4 math problem solutions with detailed steps for each step, !! today 5

1) (200+205) (kg).

2) yuan) 3) 160 yuan).

4) 81 squared.

Why can't you use the equation, o o"…

There is also a fourth question that I may have misunderstood...

Is it 94 to the power or 9 to the 4th power?

1: 200 + 205 = 405 kg, 30% + 25% = 55% 100% - 55% = 45% 405 45% = 900 kg.

2: 10,000 yuan. 10,000 yuan 10,000 yuan

3: 160 divided by 8 10 = 200 yuan. 200*9 10=180 yuan.

1. (205+200) divided by (1-30%-1 4)=900kg4 times 2 5 times 5% = 10,000 yuan; Multiply (1-2 5) multiply 8%=; 10,000 yuan

Divide by (yuan; 800 times multiplied by dollars.

Words to the second power are gone! Still 9 to the 4th power.

A B 32 32

Initially, there were 43 piles of A and 21 piles of B.

With the backward method, before the second time, A 32 2 = 16. B = 32 + 16 = 48, so before the first time, B = 48 2 = 24, A 16 + 24 = 40. Then at first A 40, B 24

If you plan to travel for five days in October, the sum of the dates of the five days is (5a).

If the sum of the dates of the five days is a multiple of 30, they may depart on October (4). Because 30 is a multiple of 30, the middle day is 30 5=6, and the departure day is 6-2=4.

It may also depart on October (10). Because 60 is a multiple of 30, the middle day is 60 5 = 12, and the departure day is 12-2 = 10.

It may also depart on October (16th). Because 90 is a multiple of 30, the middle day is 90 5 = 18, and the departure day is 18-2 = 16.

It may also depart on October (22nd). Because 120 is a multiple of 30, the middle day is 120 5=24, and the departure day is 24-2=22.

(1) Fill in 5a

A-2, A-1, A, A+1, A+2(2)4 or 10 or 17 or 22

From (1) 5a = 30 or 60 or 90 and other 120 or 150 ......a = 6 or 12 or 18 or 24 or 30 ......

a-2>=1, a+2<=31

Therefore a>=3 and a<=29

So a = 6 or 12 or 18 or 24

Get a-2 = 4 or 10 or 16 or 22

Because it is five consecutive days, the sum of these five days is: a-2, a-1, a, a+1, and a+2 is 5a

Because 5a = 30, then a = 6, so it is from a-2 = 6-2 = 4 or, 5a = 60, then a = 12, so it is from a-2 = 12-2 = 10 or, 5a = 90, then a = 18, so it is from a-2 = 18-2 = 16 or, 5a = 120, then a = 24, so it is from a-2 = 24 - 24 = 22 so, it may start from 4, 10, 16, 22.

5a, 5a is a multiple of 30, then a is the smallest is 6, or it may be , 30;30 (does not fit the topic, discard).

So the time of departure is these four numbers minus 2.

I don't know if I understand.

1, (1 6 + 1 4) * x = 1 1 3 solution x = 2, (1), set: welcome x sheets. 3*x-40=x+40 solution: x=40, so Huanhuan has 120 Yingying has 40

2), set: Yingying x sheets. 3*x-40=xSolution:x=20So Huanhuan has 60 Yingying has 20

3. Set: ballpoint pen x yuan. Solution: x=so fountain pen ballpoint pen.

1,（1-1/3）/(1/6+1/4)=8/52.(1) Set welcome as x and joy as 3x. x+40=3x-40, x=40 huan=120

2) Set welcome to x, and huan to 3xx=3x-40, x=20 huan=60

3.Let the price of the circle be x and the price of steel be x= steel=

1,（1-1/3）/(1/6+1/4)=8/5

2.Set welcome as x and joy as 3x. x+40=3x-40, Yingying=40 Huan=120

3.Let the price of the circle be x and the price of steel be x= pen=

|b+c-12|+(b-c-5) squared = 0 then: b+c = 12

b-c = 5 because: b-c so: 5

|b+c-12|The square of +(b-c-5) = 0, so b+c-12=b-c-5=0

b+c=12,b-c=5

Because b-c 5

48, then the number of men is 48-18=30

Women make up 40 per cent of the total population

60% for men

30 60% = 50 is the total number of people.

2 women were transferred.

Let the number of transferred women be x

The original number of women: 48*), the number of women after the transfer is 48*) because the number of women is exactly 40% of the total number, and the total number of women after transfer (48+x)*40% (person).

48* = （48+x）*40%

It can be solved with x=2

In the second question, if AO is extended to the other branch at the point A', it is easy to know that AO=A'O, S A'AB=2S AOB (the height is B perpendicular line to LAO, the difference at the bottom is doubled, and the area is doubled), and after A' as L is parallel to AB, then the area of the triangle formed by any point on L and AB is 2 times that of AOB. The first question of the analytic formula of a function has been solved, and the analytic formula of l is very simple, and the intersection point with the coordinate axis can be taken. Similarly, extend OA to A''(3,9), cross A'' to make the parallel line of Lab, and take the intersection point.

I haven't thought of an easier way for the time being.,Visual inspection of this question is a simple number for you to calculate.。。。

The second question is divided into two cases, p is on the x or y axis, let p(x,0) on the x axis, the primary function intersects with the y axis at c and the x axis at d, then the triangle apb can be divided into triangle pdb and triangle pda to calculate the area, and the coordinate difference should be added to the absolute value when calculating the bottom value, that is, the division is discussed on the left or right side of d, p is similar on the y axis. If you don't understand it, please adopt.