Why are there more men than women with color blindness?

Color deficiency and color blindness are both genetically determined, so it is necessary to understand what genes determine color blindness!

The gene that determines color blindness is recessive and is present on the sex chromosome of humans – the X chromosome.

The sex chromosome is XY for males and xx for females.

The Y chromosome is very short in a male pair's sex chromosome, so there are few homologous segments of the Y and X chromosomes.

As mentioned earlier, if a male has a gene on the X chromosome that determines color blindness, then because there is no dominant gene on the Y chromosome (in fact, there is no recessive gene), the male is color blind.

And if a female has a gene on the X chromosome that determines color blindness, because the female has a pair of X chromosomes, then if there is a relative dominant gene on the other X chromosome that determines not to have color blindness, then the female is not color blind.

In other words, women with color blindness need a pair of recessive genes, while men only need one recessive gene, which is why in people with color blindness, both men and women are separated.

This is because the color blindness gene is present on the X chromosome of the sex chromosome, and it is inherited in a companion recessive manner. Men are usually colorblind, while women are carriers of the normal-looking color blindness gene.

It is not that the gene frequencies are the same because of the cosexual inheritance that males will exhibit color blindness if they have a color blindness gene, whereas females with color blindness genes do not necessarily exhibit color blindness, only homozygous genes manifest themselves, and heterozygous does not.

The color blindness gene is on the X chromosome and is recessive.

Males only have one X chromosome, so as long as they carry the color blindness gene, they are color blind.

A woman has two X chromosomes, and if one of them is carried, she is not color blind, and both X chromosomes must carry the color blindness gene to be color blind.

No, if there are 6 AAs, 3 AAs, and 1 AA in 10 people, then the gene frequency of AA = (3*1+1)2) (2+7+1)= because 10 (the total number of males and females in the population) is fixed, so the gene frequency mainly depends on the number of genes.

Another example is color blindness, the male is XAY, the female is XAXA, and each male patient carries one color blindness gene, and each female patient carries two color blindness genes, note that there are still female carriers (XAXA does not develop the disease) but carry one color blindness gene, so the total number of all color blindness genes in female individuals is relatively high, not necessarily inferior to male, and thus gene frequencies are not necessarily inferior to males.

Bayesian formula: p(dj x) = p(x dj) p(dj) p(x di)p(di).

Let event A1 be that the person is female, event A2 that the person is male, and Event B which means that the person is colorblind.

p(a1 b) indicates the probability that the person with color blindness is female, p(a1 b) = p(b a1)p(a1) [p(b a1)p(a1)+p(b a2)p(a2)].

p(b a1) indicates the incidence of female patients with color blindness, and p(a1) indicates the probability that the person is female p(a1)=p(a2)=

p(a1/b)=

There is still a condition for this question, and the ratio of men and women must be told in reality, so let's assume that it is 1:1.

The rest of the steps are pretty much the same as the 2nd floor, although it's a bit wordy, but it's very detailed, so I won't say more.

The denominator should be the probability that the person is colorblind, 1 2*5%+1 2*

The numerator is the probability that the person is a male color blind patient, 1 2 * 5% =

I won't forget about it, but I'm not sure, I haven't been in contact with it for years.

a, b, and x represent events: male, female, with color blindness, then:

p(x|a)=5%, p(x|b)=, p(a)=p(b)= and: events a and b are mutually exclusive, p(a)+p(b) =1;

The probability that a person with color blindness is male:

p(a|x) = p(ax)/p(x) = p(x|a)*p(a)/p(x)

where p(x) = p(xa) +p(xb) = p(x|).a)*p(a) +p(x|b)*p(b) = 5%* =

p(a|x) = 5%* =

People with color blindness are only different in terms of gender, and a lot of them are confusing to you, and the male-to-female ratio is generally considered to be 1 to 1, so the male probability is 50

I can't stand it anymore. This should be done using the Bayesian formula. Let a = happen to be a colorblind patient, b = selected male, then the inverse event b = selected female.

So p(b|a)=p(ab)/p(a)=p(b)p(a|b)/p(b)p(a|b)＋p(⌒b)p(a|⌒b)=1/2*5%÷(1/2*5%+1/2*

For a person with a male-to-female ratio of 22:21, there are 220 men and 210 women.

Thus, the number of men with color blindness is 220 times five percent = 11, and the number of women with color blindness is 210 times the number of people. The probability of saying that this person is male is 11 11+

A analysis of the chromosomes that control sex in which XX binds females and XY binds males. A woman must have both X chromosomes to have a disease-causing gene to be red-green color blind, while a male with only one X chromosome will be red-green color blind as long as he carries the disease-causing gene. Therefore, there are more males than females with red-green color blindness, so a is chosen.

Famous Teacher of Huatu Online School This question tests the common knowledge of biology. Color blindness is the inability to distinguish colors, that is, the loss of the ability to distinguish colors. According to the doctrine of the three primary colors, those who cannot distinguish red are red blind, those who cannot distinguish green are green blind, those who cannot distinguish blue are blue blind, and those who cannot distinguish all three colors are total color blindness.

Someone who can distinguish all colors, but is slow to distinguish colors, or can only recognize them after repeated consideration, is a person who is color weak, which refers to a weakened ability to distinguish colors. Color blindness and color deficiency is a congenital genetic disorder for which there is no effective ** method so far.

Option A because red-green color blindness is associated with X recessive genetic disease.

Color blindness is a recessive genetic disease with X chromosome, the genotype of male patients with color blindness is XBY, and the genotype of female patients with color blindness is XBXB, and the survey found that male color blindness accounts for about 7% of the male population, that is, the probability of XB is 7%, then the proportion of female color blindness in the female population is about 7% 7%=

The genotype of male color blindness is XBY, where XB comes from the mother, and male color blindness accounts for 7%, so the probability of female producing XB gametes is 7%; And among the X gametes produced by males, the probability of XB is 7. If the genotype of female color blindness is XBXB, then female colorblind patients make up 7% 7% of the total female population in the region=

Passerby A in the third year of junior high school came up with the answer?