Solve a high school chemistry calculation problem and ask several high school chemistry calculation

Hello Suppose there is xmolCu in the mixture, ymolag3cu + 8Hno3 (dilute) = 3Cu (no3) 2 + 2no (gas) + 4H2O

3 2 x2x|3 3ag+4hno3=3agno3+no+2h2oy y|3

So we get: 64x+108y=

2x|3+y|3=

The mass of x=,y=cu is m(cu)=

Amaranth. 7-valent Mn ions become.

2mn ions, a kmno4 has a mn ion.

3 valence c becomes.

4 valence C, a H2C2O4 has two C atoms.

The amount of KMno4 obtained by the change of chemical valence is a multiple of H2C2O4.

Oxalic acid has. So use kmno4 for.

As only 5 ml of 25 ml is used, I share it in total, and I share it. So the mass score of kmno4 = so late with a mobile phone code word, begging the landlord for charity.

This is simple, you let the amount of potassium sulfate be a, the precipitate generated is barium sulfate, and the amount of its substance is n, so the amount of ammonium sulfate is , and because the mass of the fertilizer is m, the following calculation formula can be obtained: 174a+(n-a)132=m, so get.

a=(m-132n)/42

Trim chemical equations.

Find out the correspondence between Cu2O and KMNO4.

m/144m/144=

M = titer of Cu2O for this KMno4 solution is.

1.Make a list of equations.

Let O2 react to xmol

Then SO2 reacts by 2x

Produces 2xmol

SO3 can be obtained as (8-2x)*100=40*(12-2x)x=2 at equilibrium NSO2=4mol is proportional to the volume by pressure p=

It is due to the electrolysis of oh- at the cathode all the time

So 896mlo2 transfers electrons.

The anode first decomposes the Cu ions.

Then dissolve the H ions.

Cu produced

In solution. So the acres of skin digging finally increased.

H ions remaining.

ph=3.It should be asked about the degree of detachment of the electric grip.

The degree is a comparative value of the degree of ionization ( ).

The number of ionized weak electrolytic fast nucleoplasm molecules The number of protoweak electrolyte molecules)*100%k=

1.Let the oxygen wax gas react a

mol, then the sulfur oxide reaction of diluqing 2a

mol, so 2a is also produced at the same time

mol sulfur trioxide, sulfur dioxide accounts for 40% of the total volume at equilibrium, and there is a total gas of (8 2a) (4 a) 2a 12 a when the balance is held, then there is (8 2a) (12 a) 40%, and the solution is a 2, so the amount of sulfur dioxide in equilibrium is copper sulfide should be an insoluble substance, is it possible to have a mole per liter?

The first c is -ch, which can be seen to be sp hybridization, so the A and D options can be excluded; Using the more familiar knowledge of acetylene, we can see that -c c- is sp hybridization, so excluding option c, the answer is determined to be b.

Choose B, methyl carbon is sp3 hybrid, carbonyl carbon is sp2 hybrid, planar triangle, three-dimensional structure, and the last 2 carbons are sp hybrid, straight type.

1.Your question is in a leaky state, but it should be liquid, otherwise it won't count.

co2（g）+2h2o（g）= ch4（g）+2o2（g）△h5=

C (graphite) + O2 (g) = CO2 (g) H2 = —393 5kJ mol

2h2(g)+o2(g)=2h2o(l) △h3= kj/mol

C (graphite) + 2H2 (G) = CH4 (G) ΔH4 = H5 + H2 + H3

Starting 2 1 0

Change the final stateFrom the final state, it can be seen that the concentration of SO3 is.

v=△c/△t

So v=3It is known that the molar mass of the hydrocarbon m= formula m= ·vm, where vm=

The relative molecular mass of this hydrocarbon is 72

2)∵n(h2o)=，n(co2)=11/44=

and n(hydrocarbon)=,n(h)=2·n(h2o)=,n(c)=n(CO2)=

n(h)=，n(c)=

The molecular formula of this hydrocarbon is C5H12

Graphite) + 2H2 (G) = CH4 (G) Heat of reaction ΔH4 can be determined by:

2) +(3)-(1) can be obtained, so the δh4 of this reaction is:

h2+△h3- △h1= —393．5kj/mol+─ =211kj/mol2.

This problem should be solved with poor quality. NaCl (, I2 has been sublimated) was generated from Nai(150). Solids mass reduction.

Nai in the original solution: 300 g*

2Nai + Cl2 == 2NaCl + I2 solid mass reduced by 2*150g--71g---2*

--x---

-x=71*5g/183=

300g of nai has nai in it, and the equation is:

2nai + cl2 =2nacl +i2300 71 117 254― = ―

xg is solved to get x=

1.is the answer.

2.n=m= is the answer.

3.n=26 zinc molecular weight, v= is the answer.

4.That is, it is composed of 3 parts of potassium chloride mixed with 1 part of sodium chloride, so w = 3* (3 * potassium chloride molecular weight + 1 * sodium chloride molecular weight) is the first answer.

That is, there is potassium chloride + sodium chloride: m = potassium chloride molecular weight + sodium chloride molecular weight is the answer.

v=vm*n=

m=m/n=

So the relative molecular mass of this gas is 64