The integrated arithmetic amplification circuit has several states in the output for nonlinear appli

Updated on technology 2024-03-12
9 answers
  1. Anonymous users2024-02-06

    Because the open-loop voltage gain of the op amp is very large, in the tens of thousands or even higher.

    At such a high voltage gain, as long as there is a very small change in the input terminal, or even external interference noise, the output terminal voltage will be saturated, so that the op amp can not work normally.

    Only by adding a negative feedback link (that is, closed-loop application) to the op amp circuit can make the op amp work in a closed-loop state, reduce the amplification gain, and improve the stability and anti-interference ability of the circuit.

    At this time, the output signal of the op amp will change accordingly with the change of the input signal. This workspace is often referred to as the linear zone, which is the linear application of the op amp.

  2. Anonymous users2024-02-05

    Answer]: There are two situations in the working state of rolling and grinding in the form of a fixed spike.

    1) The integrated op amp itself is in an open loop (i.e., no feedback);

    2) Integrated op amp with positive feedback.

    Its output has a non-linear relationship with the net input, and there are only two possibilities for the output: either at a positive saturation value or at a negative bucket saturation value. Voltage comparators fall into this category.

  3. Anonymous users2024-02-04

    For nonlinear applications with integrated op amps, other circuits can be used. The main reason is that although the integrated op amp has the advantages of high gain and stability, there are also some problems in nonlinear applications, such as saturation distortion, cross distortion and temperature drift. Therefore, we need to use other circuits to supplement and extend the capabilities of the integrated op amp to meet different application needs.

    Here are some common nonlinear circuits:

    1.Comparators.

    A comparator is a circuit that compares an input signal to a reference level and outputs a high or low level. It can be used to detect the rising and falling edges of the signal and trigger corresponding events, such as switch control, timing, etc. The advantages of comparators are fast speed, high accuracy, and low power consumption, making them suitable for high-speed digital circuits and precision instruments.

    2.Limiter.

    A limiter is a circuit that restricts an input signal to a certain range. It can be used to eliminate excessive or small amplitude of the input signal, preventing signal distortion and damage. The advantages of the limiter are that it is easy to use and low implementation cost, and it is suitable for audio amplifiers, power amplifiers and other fields.

    3.Filter.

    A filter is a circuit that filters out or retains specific frequency components in an input signal. It can be used to remove noise, filter interference, enhance signals, and more. The advantages of the filter are that it has the characteristics of frequency selectivity, strong ability to suppress interference, and can realize high-impedance input, and is suitable for audio amplifiers, communication systems, and other fields.

    4.Oscillator.

    An oscillator is a type of circuit that converts DC energy into alternating current energy. It can be used to generate signals of specific frequencies and waveforms, such as sine waves, square waves, pulse waves, etc. The advantages of the oscillator are self-oscillator, good stability, clean output waveform, suitable for signal source, frequency meter and other fields.

    In summary, for nonlinear applications with integrated op amps, we can use other circuits to achieve this. Different circuits have different advantages and scope of application, and we need to choose the right circuit according to the specific application needs.

  4. Anonymous users2024-02-03

    The integrated gear tremor release can only be applied to ordinary arithmetic circuits. ()

    a.That's right. b.Mistake.

    Correct answer: B

  5. Anonymous users2024-02-02

    It can be seen as zero for the following reasons:

    It is known from uo=aod(u+ -u-) that when the aod is large enough, the value of the differential mode input voltage (u+ -u-) of the integrated op amp is small and negligible compared to other voltage values in the circuit.

    However, the actual integrated op amp AOD is not equal to infinity, so u+ and u- cannot be exactly equal.

    An integrated op amp, abbreviated as an integrated op amp, is an integrated circuit with a high magnification.

    Inside it is a multi-stage amplifier that is directly coupled, and the whole circuit can be divided into three parts: input stage, intermediate stage, and output stage.

    The input stage uses differential amplification circuitry to eliminate zero drift and suppress interference; The intermediate stage generally uses a common emitter circuit to obtain a sufficiently high voltage gain; The output stage generally adopts a complementary symmetrical power amplifier circuit to output a sufficiently large voltage and current, with small output resistance and strong load capacity.

  6. Anonymous users2024-02-01

    The amplitude of the output signal vo is equal to the product of the amplitude vi of the input signal and the voltage gain a of the amplification circuit formed by the op amp, i.e., vo = vi*a, but vo is limited by the maximum output amplitude of the amplification circuit, and the maximum output amplitude of the amplification circuit is determined by the difference between the supply voltage and the minimum lost voltage of the op amp. For example, when the supply voltage of LM358 is 5V and the ambient temperature is 25, the high-level loss voltage difference is 5 20mV, and the low-level loss voltage difference is 5 20mV.

    Let's assume that the voltage gain of an amplifier circuit made of LM358 is 100, and if the amplitude of the high level of the input signal VI is exceeded at a certain time, it is . Then according to VO=VI*A to calculate, the output voltage of the amplifier circuit should be equal to 4V, but because the upper limit of the output voltage of the amplifier circuit is only, so when VI reaches and exceeds, the output voltage is always limited and cannot change with the input voltage, this situation is usually called "clipping" or "peak clipping", that is, the distortion caused by the amplitude of the input signal is too large.

  7. Anonymous users2024-01-31

    If the amplitude of the input signal is too large, the output may exceed the power supply voltage after amplification by op amp, but the actual output amplitude cannot exceed the power supply voltage, so the output signal will be distorted.

  8. Anonymous users2024-01-30

    There are two voltage sources for integrated op amps: positive and negative. The output stage is a complementary output stage.

    Both positive and negative models can be output. AC can be regarded as direct current whose size changes with time, and since it can amplify DC, of course AC can also be used What's the problem (o o)?

  9. Anonymous users2024-01-29

    The problem is inexplicable, the op amp can basically be divided into voltage or current amplifiers, there is no AC and DC difference.

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