Find the value of the algebraic formula 2a square b 2ab square 2 a square b ab square when a 0 5, b

2A square B - [2AB square - 2 (A square B + AB square)].

2a²b-2ab²+2a²b+2ab²

4a bWhen a=-1 2 b=1, the original formula = 4*(-1 2) *1=1

It took a little bit of time to b, and I didn't calculate m over the time. a+b=3 ab=-4 a3b+ab5? 0a to the 1st power 0b + 5ab to the 4th power 2 ?

The square of a is 8b + ab squared 1 a times 4a times 1b + ab is multiplied by 7ab a squared 3b + ab squared 2 a times 2 (-0) + (2) times 8 (-2) a squared 8b + ab squared 3 -4a + 4 a squared 2b + ab squared 1 7a 0 power 4b + 4ab 4 power 1 3a 8 power 6b + [7 times 3 (-3)] 8 2a 2 power 6b + 3 ab 1 power 4 4a 5 power 2b++(-371) 3a to the 8th power 6b + 4ab to the 0th power 1-3a to the 4th power 4b -852

It took o a little time, and I didn't b over-calculate the g. a+b=4 ab=-2 a's square1b+ab's square4 ? 2a to the 1st power 8b + 8ab to the 6th power 4 ?

The square of a2b+ab is squared by 5 a times 0a times 8b + ab is multiplied by 5ab the square of 0b + ab 3 a times 0(-4)+(4) times 2(-8) a squared 7b + ab squared 4 -1a + 4 a squared 5b + ab squared 7 + 8a 5 5a square 8b + 3ab to the 7th power 6 2a 8 b+[2 times 0(-8)] 0 power 6 2a to the 5th power 2b + 5ab to the 6th power 2b + 5ab 2 2a to the 2b 2a 2b 2b 2a to the 2b 2b 2b 2 2a to the 2b 2b+(-021) 7a to the 5th power 4b + 7ab to the 2nd power 0-7a to the 8th power 8b -617

2 (a-b) is changed to cubic-4a-4b

2 (a-b) cubic-4 (a+b).

2 2 The verdict is as follows: -4 5

a-2).b-1|=0, so Jane takes a-2=0; b-1=0;

a=2;b=1;

5ab-[2a^2b-(4ab^2-2a^2b)]

Step 1: Because a +2ab+b = 0

Launch (a+b) =0, that is, a+b=0 second step: a(a+4b)-(a+2b)(a-2ab)=(a+4ab)-(a-4b)=4ab+4b=4b(a+b).

Because the first step has been introduced a+b=0

So 4b(a+b)=0

0 The previous formula is equivalent to (a+b) squared = 0 Equivalent to (a+b)=0 The latter formula is equivalent to 4b(a+b) so the result is 0

Solution: Made by the special value method.

Because (a+2ab+b) = 0

So: when a=-1, b=-1

So: a(a+4b)-(a+2b)(a-2b)=4b(a+b)=4(-1)[(1)+(1)]=8

You can also directly substitute the values of a and b into the equation you are looking for.