4 math questions! Urgent! Solved with equations .

1) Set the skirt x yuan, the top y yuan, then there is y=2x+26;y-x=106.The solution is x=80 and y=186

2) Set the length to be x meters, the width to be y meters, if the side against the wall is long, then there is x=2y; x+2y=solution x=,y=

If the side against the wall is wide, then there is x=2y; 2x+y=solution x=,y=3) if there are x stamps, and there are y stamps in red, then there are x=, x-20=y+20The solution is x=90 and y=50

4) If the two people have the same amount of money after x days, then there is, and the solution is x=20

Blouse x, skirt y

1）x-2y=26

2）x-y=106

x=106+y substituting (1) gives y=80So x=186 is x in length and y in width

x=2yx+2y=

x=;y=Obviously x, red is y

x=y=x-20

x=45 and y=25 are obtained

Missing the fourth question, x=20 so it is 20 days.

1) "Buy a set of clothes" refers to a blouse, or a skirt, or a blouse and a skirt.

2) If the width is x, the length is 2x

x*2+2x＝

x＝ 2x＝

or x+2x*2

x＝ 2x＝

Normal people should take the long side against the wall, but the person who asks the question is not necessarily.

If there are x sheets in red, then there are obviously them.

x 50 set x days later, the two of them have the same amount of money left.

x＝20

Untie; Set the skirt x yuan.

2x-26-x=106

1x-26=106

1x=136

2x136+26=298 yuan.

298 + 136 = 434 yuan.

A: It costs 434 yuan to buy a set of clothes.

Untie; If the width is x meters, the length is 2 x meters.

2x+2x=

4x=x=x=m.

The width is meters, and the length is meters.

1) Solution; Set the skirt x yuan.

2x+26=x+106

2x -x=106-26

x=80 80+106=186 (yuan).

186 + 80 = 266 (yuan).

Answer... 2) solution; Set the width to take x meters.

2x+x+x=

4x=x=A... 3) solution; If there are x stamps in red, there are obviously (stamps.

x=A;. 4) solution; Set up x days later, the two of them have the same amount of money left.

x=20A...

I don't know, right? -

Solution: Set the price of the skirt to be X yuan, and the price of the top to be Y yuan.

2x+26 =x+106 2x+26=y

2x=x+80 2*80+26=186

x=80

This is a very simple question! Think about it.

24. In the official volleyball game, there are strict regulations on the weight of the volleyball used. Check the weight of 5 volleyballs, the number of grams exceeding the specified weight will be recorded as a positive number, and the number of grams less than the specified weight will be recorded as a negative number, and the inspection results are as follows:

40 Point out which volleyball is the most *** (i.e. the weight closest to the stated weight)? How do you illustrate this with the absolute value knowledge you've learned?

25.Known;

1) Fill in the blanks with conjecture:

2) Calculate 23+43+63+983+......100326 Exploring the law will be a continuous even-2, 4, 6, 8 ,..., arranged in the following table: 2468

1) What is the relationship between the sum of the five numbers in the cross box and the number and 16 in the middle?

2) Let the middle number be x

The sum of the five numbers in the cross box is expressed algebraically.

3) If you move the cross box up and down, left and right, you can frame the other five digits, can the sum of the other five digits be equal to 201? If you can, write these five digits, and if you can't, explain why.

1. The decimal point of the smaller number is moved to the right by one place, which is equal to the larger number, that is, the smaller number is 1 10 of the larger number

So the smaller number is.

The larger number is.

a+18b=9(a+2b)

Therefore, a+2b is a number of squares that does not exceed 3, that is, 1, 4 or 9 Because a and b are coprimous, the possible values of a and b are:

a=1,b=4

a=2,b=1

a=5,b=2

a=7,b=1

A total of 4 to 3, at least how many trees to plant, that is, when the interval between each two trees is the largest, when the interval is 12, the distance is the largest.

So at least 5 + 6 + 8 + 7 = 26 (trees).

4. (1 2-1 and 3 5) (1 2) 15=3 (yuan) I hope it can help you! Okay** points, thank you!

1. Let A be x and B be y

x+y=10x=y

The solution is x=, that is, A is.

a+18b=9(a+2b)

Therefore, a+2b is a number of squares that does not exceed 3, that is, 1, 4 or 9 Because a and b are coprimous, the possible values of a and b are:

a=1,b=4

a=2,b=1

a=5,b=2

a=7,b=1

A total of 4 pairs, 72,96,84, the least common multiple is 1008010080 60=168

168 + 140 + 105 + 120-4 = 533 (trees) 4, assuming that the original sales volume is 1, the sales volume is 15;

If the current sales volume is increased by 2 times on the basis of the original sales volume, the current sales volume is 3, and the current sales volume is;

Let the markdown be x, then there is:

15-x)*3=24

Get x=7

1. The number of A is 10 times that of B,,, so B is, A is.

The maximum square of the number is 81, so a+2b=81 9=9, that is, 1,4 or 9Because a,b are coprime, a,b may take the value as:

a=1,b=4

a=2,b=1

a=5,b=2

a=7,b=1

A total of 4 pairs of 3, because the distance is equal, so find the common divisor of the four sides, that is, 12, each side should be loaded with , and because there are two repeats at the junction of each side, so at least 22 trees.

2-(1+3 5) (1 2) 15=3 (yuan).

9a+18b>27

The single digit is 6789

The square of a single digit is 36 49 64 81

a, b are coprime numbers a<=7(7*9+18*1=81) b<5a=1 2 3 5 7

b=1 2 3

ab can be taken to the number pair 1,2 1,3 2,3 3,1 3,3 7,1

Because the distances are equal, the common divisor of the four sides is found, that is, 12, and each side should be loaded with , and because there are two repeats at the junction of each side, a minimum of 22 trees is required.

1.A decimal point is moved to the right by one place to equal the number B.

The number B is ten times the number of A.

Number A = Number B =

2.9a+18b=9 (a+2b) is a single digit squared a+2b=9

a, b are co-prime numbers, and from the above equation, we can know that a is an odd number.

a=1,b=4; a=5,b=2;a=7, the greatest common divisor of b is 12, and there is one tree at each of the four corners.

The resident's monthly water consumption is 20m (the water consumption in May is more than that in April), indicating that the water consumption in April is less than 10m, and the water consumption in May is greater than 10m. If the water consumption in April is x(<0x<10), then the water consumption in May is 20-x

The water fee in May is 6*2+4*4+8(20-x-10)=108-8x, and since <0x<10, it is 28<108-8x<108

Since <0x<10, assuming <0x<=6, the water bill in April is 2x, so the water bill in April and May is 2x+(108-8x)=64, and the solution is x=22 3>6, and the assumption is not valid.

Hypothesis 6 is therefore used in April 8 and May 12

Let the water consumption in April be Y1 and the water consumption in May be Y2;

then there is y1+y2=20

And because there is more water in May than in April, there is:

2y1+8y2=64 or 4y1+8y2=64, but 4y1+8y2=64 is manifest but not true.

So there is: y1+y2=20

2y1+8y2=64

The solution is y1=16 y2=4

Question 1:

Let the velocity of A be x and B's y

4x+2y=28（14x+7y=98）

The output is 7x=42, x=6, y=2

In the second question, the number of hundreds, the number of tens, and the number of single digits are x=x+z

y-z=2100*z+10*y+x-100*x-10*y-z=9999z-99x=99

z-x=1z=x+1

y=z+2=x+3

x+3=x+x+1

x=2，z=3,y=5

This number is 253

The third question assumes that after x years, Xiaojie surpasses Dad's 1 3

13+x)*3>(45+x)

39+3x>45+x

2x>6

x>3 Therefore, it can be known that at least 3 years later, that is, Xiaojie is 16 years old, and when his father is 48 years old, he can exceed 1 3 of his father's age

1A 6 km/h, B 2 km/h.

132 In another four years, Xiaojie 17His dad 49

Think about it yourself, you're still a primary school student, this kind of thing has to think independently.

If x people produce type A, then the number of people type B is 62-x

12x 3=23(62-x) 2 x=46 people, 46 people in production A, 14 people in B.

Let car B meet x hours after driving 360-60=x(40+46) x=3 hours.

Meet 3 hours later.

Let the team leader x the communicator advance with a relative velocity of 12-8=4 and return relative velocity = 12+8=20x 12+x 20= x=216 meters.

The length of the team is 216 meters.

Let the distance between the two places be x, and the speed of the car = 36 * 2 = 72 (x 3) 36 + (2 x 3) 72 = x = 81 km.

Here's how to solve it:

1. Solution: If the production of a kind of parts x people, then the B kind of parts (62-x) people according to the meaning of the topic;

12x/3=23(62-x)/2

Solution: x=46 people.

There are 46 people in the production of type A parts, and 16 people in type B parts.

2. Solution: Set car B to meet x hours after driving.

360-60=x(40+46)

Solution: x=3 hours.

So meet 3 hours later.

3. Solution: Set up a team leader x

The relative velocity of the correspondent is 12-8=4 and the relative velocity of the return = 12+8=20x 12+x 20=

Solution: x=216 meters.

The length of the team is 216 meters.

4. Let the distance between the two places be x, and the speed of the car = 36 * 2 = 72 (x 3) 36 + (2 x 3) 72 =

Solution: x=81

So the distance between the two places is 81 km.

If x people produce type A, then the number of people type B is 62-x

12x 3=23(62-x) 2 x=46 people, 46 people in production A, 14 people in B.

There are 46 people in the production of type A parts, and 16 people in type B parts.

Let car B meet x hours after driving 360-60=x(40+46) x=3 hours.

Meet 3 hours later.

So meet 3 hours later.

Set: Team Leader X

The relative velocity of the communicator is 12-8=4 and the relative velocity of the return = 12+8=20x 12+x 20= x=216 meters.

The length of the team is 216 meters.

Let the distance between the two places be x, and the speed of the car = 36 * 2 = 72 (x 3) 36 + (2 x 3) 72 = x = 81 km.

Formula: Rise = Profit - Fixed Amount.

Judging from the data of the first week, the fixed number used for this comparison should be = (-20)-15=-350,000, so the profit of the second week is 280,000, and there is an increase = 28-(-35)=630,000, and then according to the increase of 250,000 in the third week, the profit of the third week is:

25 + (-35) = -100,000.

That is, a loss of 100,000.