Mathematics Problem Classes 1 and 2 of Year 6 have equal size. The number of boys in Class 1 is one

Suppose the female in class 2 is a person, and the female in class is a person b, then the male in class 1 is 1 3a, and the male in class 2 is 1 4b, since the number of people in the two classes is the same, then 1 3a+b=a+1 4b gets 8 9a=b, then the ratio of the number of people in the two classes is b:a=8:9.

Or the girls in the first class are eight out of nine in the second class.

We can set up a class with G1 boys and M1 girls; The number of boys in class 2 is G2 and the number of girls is M2.

The total number of students in the two classes is equal, which means that g1+m1=g2+m2; The last two conditions state that g1 = 1 3m2 and g2 = 1 4m1.

From this, these two conditions can be brought into the first equation: 1 3m2+m1=1 4m1+m2.

Solving this equation gives us m1:m2=8:9.

In other words, the girls in the first class are eight-ninths of the girls in the second class. Hope.

8:9 is correct.

The reasons are as follows: Suppose the first class boy x1, the girl y1, the second class boy x2, the girl y2x1+y1=x2+y2

From the meaning of the title. x1=1/3 y2

x2=1/4 y1

Substitute x1 and x2 into the equation.

1/3 *y2 +y1=1/4 *y1 +y23/4 *y1=2/3 *y2

y1：y2=2/3 *4/3=8/9

Or. Suppose the female in class 2 is a person, and the female in class is a person b, then the male in class 1 is 1 3a, and the male in class 2 is 1 4b, since the number of people in the two classes is the same, then 1 3a+b=a+1 4b gets 8 9a=b, then the ratio of the number of people in the two classes is b:a=8:9.

8:9 is right: If there are x males in a class, and there are 4y females in a class, then there will be y males in the second class, and there will be 3x females in the second class, and the total number of the two classes is equal, then x+4y=y+3x, so y:x=2:

3 The ratio of women in the first class to the second class is 4y:3x= 4 3 *2 3 is 8:9.

Suppose the first class boy is x1, the girl is y1, the second class boy is x2, and the girl is y2x1+y1=x2+y2

From the meaning of the title. x1=1/3 y2

x2=1/4 y1

Substitute x1 and x2 into the equation.

1/3 *y2 +y1=1/4 *y1 +y23/4 *y1=2/3 *y2

y1：y2=2/3 *4/3=8/9

There are 60 students in the class, 1 3 of the number of boys = 1 2 of the number of girls, then 100% of the number of girls = 2 3 of the number of male Zhen Shen Yuan

2 3 If you add the boy filial piety (1+2 3) to 5 3, then:

Boys have (60 5 3) = 36 peopleThere are (60-36)=24 girls.

If a boy is a student, then a girl is 60-a A 3=(60-a) Nucleus Zheng Zi2 2A = 3(60-A) 5A=180 A = 36, so 36 boys and 24 girls are changed.

There are 28 boys in the first class of the sixth grade, which is equivalent to 4 7 of the class size (i.e. 4 7 for boys) and 3 7 for girls

There are girls in a class of 6th grade (3 7) = 21 students.

Sixth grade should have learned the unknown, let's say.

The number of boys in classes 1, 2 and 3 is x, y, and z respectively.

The number of girls in the first, second and third classes is y, x, x+y-z, respectively (according to the first and second conditions of the question), so according to the third condition to write the equation z=3 8(x+y+z), z=3 5(x+y), the final question can be expressed as: the number of girls in the whole grade y+x+(x+y-z) is compared with the total number of students in the whole grade 3 (x+y) and the answer is 7 15

This is the solution to the problem of the number setting method in the Olympiad of Mathematics in Primary Schools. There are a total of 8 boys in three classes, 3 boys in the third class, and 5 boys in the first and second classes, which is also the total number of girls in the first and second classes at the same time, so there are 2 girls in the third class. Therefore, there are a total of 7 girls in the three classes, and the total number of girls in the whole grade is 5*3=15, so the answer is 7 15.

Wrong, the answer is 4 9

The number of boys in Class 1 and the number of girls in Class 2 are equal, indicating that the total number of boys in Class 1 and Class 2 is equivalent to the number of students in a class; The number of boys in class 3 is 40% of the total number of boys, and the number of boys in class 3 can be regarded as 4, and the number of boys in class 1 and class 2 is six, that is to say, the number of boys in class 1 and class 2 is 6, so the number of girls in class 3 is 6-4 = 2; The total number of copies in the three classes is 6+6+6=18, and the total number of shares for girls is 6+2=8, and the answer is 8 18=4 9

Since the number of boys in class 1 is equal to the number of girls in class 2, the number of girls in class 1 is equal to the number of boys in class 2.

The total number of boys in two classes = the total number of girls in two classes = the number of students in one class, the boys in two classes account for 1 3 of the whole grade, the boys in the whole grade (1-3 7) = 4 7, and the total number of boys in the whole grade: 1 3 (4 7) = 7 12

Therefore, girls make up 1-7 12 = 5 12 of the total number of students

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1, each class a, 2, the boys in the first class are equal to the girls in the second class b, a-b=b i.e. a=2b 3, the boys in the third class account for the whole class 2 5 i.e. girls = 3a 5

4, Class 1 girls a-b = Class 2 girls = b = total number of girls for the whole grade.

Suppose the number of boys is x of the total number of people (I know this assumption is a bit strange = =), because the number of boys in the first class and the number of girls in the second class are equal, so the number of boys in the first class and the number of boys in the second class add up to just one class, that is, one-third of the total number of students (because according to the title, the number of the three classes is equal and the number of students in each class accounts for one-third of the total number of people, if you don't understand...).It is possible to replace the girls in the second class with the boys in the first class, and the number remains the same, so that it becomes a whole class of boys, that is, the first class of boys plus the second class of boys is one-third of the total number). The boys in the third class are 3 8 of the total number, so 3 8x+1 3=x, simplified to 9x+8=24x, solved to x=8 15. So the number of girls is 1-x = 1-8 15 = 7 15.

I don't know what level of understanding the landlord has...So it's a bit of nonsense, and the words in parentheses can be ignored ==

If the number of boys in class 3 is x and the number of girls is y, then the number of boys in the whole grade is 8 3x, and the number of girls in the whole grade is 3(x+y)-8 3x=3y+1 3x, because the number of boys in class 1 and class 2 is equal, then the number of girls in class 1 and class 2 is also equal, then the number of girls in class 1 and class 2 is x+y, and the number of boys in class 1 and class 2 is also x+y, then there is the equation x+y+y=3y+1 3x, and solving this equation obtains y=2 3x, then the proportion of girls in the whole grade is n=(3y+1 3x) 3(x+y) is substituted for y=2 3x, and n=(7 3x) (5x)=7 15

Suppose the number of students in each class is 1 and the number of boys in a class is x. The number of boys in the second class is 1-x, and the number of boys in the third class is [(1-x)+x]*3 5=3 5, the number of boys is (1-x)+x+3 5=8 5.

The rest are girls. 3-8 5=7 divided by 3 equals 7 15

Assuming that there are 3 boys in Class 3, there will be 8 boys in the whole grade, and there will be 5 boys in Class 1 plus Class 2. Because the three classes have equal numbers, the first class of boys and the second class of girls, there are 5 girls in the first class and 2 girls, and each class has 5 people. So it can be concluded that there are 2 girls in class 3.

So the ratio of girls is (5+2) (5 3) = 7 15

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Let's assume that all three classes have a 40 size

Suppose a class of boys is 20

The rest is your own.

The answer is right, right? How can I figure out that it's wrong?

Boys make up three-sevenths of the class in Class 1 and 24 boys in Class 2.

90-24 = 66 people.

Girls in a class make up 1-3 7 = 4 7 in the class

Therefore, the girls in the second class are also 4 7 out of the total number of students in the first class

66 (1+4 7) = 42 people in a class.

2nd shift 90-42 = 48 people.

There are x boys and girls (60-x) 1 3x=1 2 (60-x) 5 6x=30 x=36 boys and 24 girls.

Let boy a be 60-a girl a 3=(60-a) 2 2a = 3(60-a) 5a = 180 a = 36 so there are 36 boys and 24 girls.