The contradiction between mass energy conversion and the basic properties of light in special relati

You misunderstood, light is an electromagnetic wave and has no mass. And it can only move at the speed of light, and it can't stop, and it can't accelerate or slow down.

A photon is not a particle, it's a piece of energy, and the so-called mass is just a meaningless value derived from the mass-energy equation, and that "mass" itself is its mass moving at the speed of light.

Your infinite mass is for matter with a mass at rest.

Light pressure is the pressure calculated by absorbing energy, a force that is subjectively created for the purpose of study, because light has the same effect on an object as it does when such a force is added.

I really don't know how to explain to you, the polar particle duality is just a research method that equates some properties of two substances because of some experimental phenomena, in fact, waves and particles are still different things. Take 10,000 steps back and say, do particles have all the properties of light?

At a point in space, light can be superimposed, but why is it that where one particle occupies it, other particles cannot occupy the space occupied by this particle, and particles have volume, why don't waves?

Motion does increase the mass of the object.

But only when the rest mass is not zero.

It is the movement of an object at the speed of light that makes the mass infinite.

A stationary mass like light has zero.

There will be no such problem.

Chivalrous relativity also tells us.

It is impossible for a particle with a non-zero mass at rest to move at the speed of light.

By substituting e=eo with p=mv, we can obtain the energy equation of the particle:

E2 (pc) 2 mo2 c 4 or more is suitable for any particle.

Requiring the velocity of the particle to maintain a constant velocity c (the speed of light) then we must have the rest mass of the particle to be zero:

For photons, e=h

And the momentum of the photon is assumed by the matter wave:

p=h／λ=hν／c (∵c=λ*ν

p e c we know earlier: e 2 (pc) 2 mo 2 c 4so that e 2 (e) 2 mo 2 c 4 In order for the equation to hold, we must assume that the rest mass of the photon is zero, because the speed of light is not zero.

Particles do not necessarily have mass, and the particles here are no longer particles in the classical sense. In fact, not only photons, but neutrinos in the microscopic world have long been considered to be massless (although recently it has been thought to have a very small mass), and the particle nature of photons mainly refers to the way it moves, that is, the way light moves sometimes like a particle, not like a wave. In a narrow sense, mass is energy, and photons can be regarded as a special case in which all of their mass is converted into energy.

Also, you are talking about light pressure not because light has mass, but because light has momentum. It can be said that light is both a particle and a wave, or it can be said that light is neither a particle nor a wave.

In addition, the upstairs statement is false, the speed of light in the medium can of course be reduced, and now it can even be as many meters per minute. It should be said that the speed of light in a vacuum is constant.

The mass of a photon at rest is 0 Are you talking about an object having a mass of 0 at rest?

Define =v c, which is the ratio of velocity to the speed of light, and define the reciprocal of the square = 1- squared.

The energy of matter is equal to the (moving) mass multiplied by the square of the speed of light, and the moving mass is equal to the times the rest mass.

So the difference in energy between the two velocities is the work that needs to be done.