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Xiaojun + Xiaohong = 67 kg.
Creep + Minion = 65 kg.
The sum of the two formulas yields: 2 small army + small red + small soldier = 132 kg.
And the small soldier + small army + little red = 97 kg.
The two formulas were subtracted to a small army weight of 35 kg.
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Method 1: From Figure (1) and Figure (2), the weight of Chuanchuan can be calculated: 97 kg - 65 kg = 32 kg.
From Figures (1) and (3), the weight of Bei Bei can be calculated: 97 kg - 67 kg = 30 kg. Huanhuan's weight:
97 kg - (32 kg + 30 kg) = 35 kg.
Method 2: According to Figure (2) and Figure (3), we can know that the total weight of the two Huanhuan and Chuanchuan and Beibei is 65 kg + 67 kg = 132 kg. The total weight of the three is 97 kg, and subtracting 97 kg from 132 kg is Huanhuan's weight: 132 kg - 97 kg = 35 kg.
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Xiaobing, Xiaojun, and Xiaohong weighed a total of 97 kilograms, and Xiaojun and Xiaohong weighed a total of 67 kilograms, and subtracted to get a small soldier weighing 30 kilograms; The minions and the minions weighed 65 kilograms together, and the subtraction yielded a small army weighing 35 kilograms.
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Jun + Bin + Red = 97
Army + Red = 67
Bin + Jun = 65
Army = 35
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Xiaojun 35Subtracting the second sentence from the first sentence gives the soldier 30 kg, and subtracting the third sentence from the first sentence yields that the little red is 32 kg, and you can know that the small army is 35 kg.
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Creeps: 97-67 = 30 (kg).
Small army: 65-30 = 35 (kg).
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According to the meaning of the title, there is and believes in the world.
Peach + apple = 84
4 peaches + 6 apples = 398.
Multiply peach + apple = 84 by 4 at the same time, and get: 4 peach + 4 apple = 84 4 = 336, that is, 4 times the number of peach trees and 4 times that of apple trees is 336.
We use 398-336 = 62 trees, and these 62 trees are 6 times the size of the apple tree minus 4 times the apple tree to leave the open cavity, that is, 62 trees are 2 times the size of the apple tree (peach tree 4-4 = 0), so there are apple trees:
62 2 = 31 (tree).
There are peach trees: 84-31 = 53 (trees) comprehensive formula:
31 (trees).
84-31=53 (trees).
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A fountain pen is twice as much as a ballpoint pen.
Then (yuan, then the ballpoint pen is yuan.)
The fountain pen is the meta.
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The price of a ballpoint pen: (yuan.)
The price of the fountain pen: yuan.
In the third grade, I haven't learned equations yet, and it's easier to use them.
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Subtract more than 3 times the price of a ballpoint pen
The price of a ballpoint pen).
The price of the fountain pen).
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Ballpoint pen x yuan.
The price of the fountain pen is 2x+
x+2x+3x=x=
Ballpoint pen element. The price of the fountain pen: yuan.
-
Solution: Set a ballpoint pen x yuan and a fountain pen (2x + yuan.
2x+3x=
x=x=2x+yuan).
Answer: One ballpoint pen yuan, one fountain pen yuan.
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The price of a ballpoint pen: (yuan.)
The price of the fountain pen: yuan.
-
Set the fountain pen x yuan and the ballpoint pen y yuan.
x+y=x=2y+
x= y=
-
Let the fountain pen = x and the ballpoint pen = y, then.
x+y=x-2y=
The solution is x=y=
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1 freezer weighs as much as 2 freezers for lean meat.
4 freezers and 4 refrigerators are equivalent to 8 + 4 = 12 refrigerators, each refrigerator can hold 240 lean meat, 12 = 20 kg.
4 freezers and 4 refrigerators are equivalent to 4 + 4 2 = 6 freezers, each freezer can hold 240 6 = 40 kg of lean meat.
A: Each refrigerator can hold 20 kg of lean meat, and each freezer can hold 40 kg of lean meat.
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Since 1 freezer weighs as much as 2 freezers with lean meat, all containers are converted into refrigerators, 4 freezers and 8 refrigerators.
A total of 8 + 4 refrigerators 12 pcs.
240 12 20 kg (refrigerator).
The freezer is the weight of 2 refrigerators, 20x2 40kg (freezer) hope it helps you.
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4 2 = 8 (pcs).
8 + 4 = 12 pcs.
1 refrigerator: 240 12 = 20 kg.
1 freezer: 20 2 = 40 kg.
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Hello classmates, I'm Mr. Xian, I think you have read so many answers, and the problem in your heart should be solved. Here, Mr. Xian wants to tell you: every time you encounter an application problem, you must first read the topic carefully, what is the topic about, what conditions are given, and what is asked?
Answer: This question should pay attention to "change" and "change".
The length remains the same, and the width is reduced by 3 meters, and the area is reduced by 36 square meters) Description: The length is 36 3=12 (meters).
The width remains the same, the length increases by 6 meters, and the area increases by 48 square meters) Description: The width is 48 6=8 (meters).
So, the original area is: 12 8 = 96 (square meters).
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Let the length be a and the width be b
then there is: a(b-3)=ab-36
a+6)b=ab+48
Solve the equation to obtain: a=12, b=8
The area of the original rectangle was equal to 96 square meters.
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Length = 36 3 = 12 meters.
Width = 48 6 = 8 meters.
Original area = 12 8 = 96 square meters.
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The length remains the same, and if the width is reduced by 3 meters, the area is reduced by 36 square meters, then the length = 36 3 = 12
The width remains the same, the length increases by 6 meters, and the area increases by 48 square meters, then the width = 48 6 = 8
Therefore, the area of the original rectangle = 12 * 8 = 96 square meters.
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If the length is x and the width is y, then the area is xy
According to the title: x(y-3)=xy-36
x+6)y=xy+48
The solution is x=12 and y=12.
So area = xy = 12 12 = 144 (square meters) Answer: .
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Because the width is reduced by 3 meters, the area is reduced by 36 square meters.
So length = 36 3 = 12 (m).
Because the length is increased by 6 meters, the area is increased by 48 square meters.
So width = 48 6 = 8 (m).
Because the area of the rectangle = length and width.
So the area of the rectangle = 12 8 = 96 (square meters).
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First, the reduced area = original length * reduced width, i.e. 36 = length * 3, the length of the original rectangle = 12;
Second, the increased area = the original width * the increased length, i.e. 48 = width * 6, the width of the original rectangle = 8;
Therefore, the area of the original rectangle s = original length * original width = 12 meters * 8 meters = 96 square meters.
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Let the length be a and the width be b, then there is ab-a(b-3)=36,a=12,a+6)b-ab=48,b=8
s=ab=12*8=96 (square meters).
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96 square meters because:
Length = 36 3 = 12 meters.
Width = 48 6 = 8 meters.
So the original area = 12 8 = 96 square meters.
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Solution: Let each football be X yuan, and each volleyball (X-5) yuan.
4x+2(x-5)=170
4x+2x-10=170
6x=180
x=30 volleyball=x-5=25 yuan.
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Solution: Set each volleyball x yuan.
2x+4﹙x+5﹚=170
Solve x 25
$25 per volleyball.
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Solution: Set each volleyball x yuan, football x + 5 yuan.
2x+4(x+5)=170
6x+20=170
x=25 football: x+5=25+5=30 yuan.
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Let each volleyball be x yuan, each football is x+5 yuan, 2x+4(x+5)=170
2x+4x+20=170
6x=150
x=25A: 25 yuan per volleyball.
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In the case of not listing equations, it can be like this:
Because each soccer ball is 5 yuan more expensive than each volleyball, then 4 soccer balls are 20 yuan more expensive than 4 volleyballs.
In this way, it can be calculated according to 6 volleyballs, and the ** of 6 volleyballs should be 150 yuan, and each volleyball ** will divide 150 by 6, that is, 25 yuan, and each football will be 30 yuan.
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Let the soccer ball be each x, then the volleyball is each (x-5) yuan, then 4x+2(x-5)=170
Solution x=30
30-5 = 25 yuan per volleyball.
-
Solution: Set each volleyball x yuan, football x + 5 yuan.
According to the question: 2x+4(x+5)=170
6x+20=170
x=25 then the football is x+5=25+5=30 yuan.
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(170-4*5) 6 = 25 (the amount of money in volleyball) 25 + 5 = 30 (the amount of money in football).
170 minus the 4*5 yuan more expensive from 4 soccer balls, divided by 6 (4 soccer balls + 2 volleyballs) to get the average amount of each volleyball.
Add 5 to the volleyball money to get the football money.
-
Solution: Set volleyball x yuan football 5 + x yuan.
4x+2(5+x)=170
x。 =25
Football: 25 + 5 = 30 yuan.
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Soccer is 5 yuan more expensive than volleyball, so soccer costs 4x5=20 yuan more, so there is 170-20=150 yuan, and an average of 6 balls are given, 150 per ball divided by 6 = 25 yuan, that is, volleyball is 25 yuan each. Detailed ideas are expected to be adopted.
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