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This problem is very strange, the second floor is good, but what is missing is, for example, [0 9]=5, not a true solution, because it may also be 4, 6, etc., to say that [0 9] is not necessarily = 5. The same goes for the others. Only [5 5] can guarantee that it is 5, and you can't take 5 if you want x or y, so there is no solution.
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No solution. x y]=5There is only one case where there is a solution, that is, x=y=5, to ensure that the equal sign is followed by 5. However, since x and y cannot be taken to 5, there is no solution to this problem.
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x y] = 5 means that 5 is between x and y, and because x is between 0 and 4, and y is between 6 and 9, so any x, y can be taken, that is, with the principle of multiplication: 5 * 4 = 20 kinds, that is, there are 20 sets of solutions: (x, y) = (0, 6), (0, 7), (0, 8), (0, 9), (1, 6) ......4,6),(4,7),(4,8),(4,9)
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From x=[0 4], y=[6 9], any x and y can satisfy [x y]=5
That is, x=0,1,2,3,4 for a total of 5.
y=6,7,8,9 for a total of 4.
According to the principle of multiplication, there is a total of .
5 4 = 20 group solutions.
Such as [0 6], [0 7] ......4~8]、[4~9]
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Three equations are denoted as.
From Equation A we get 40x+40y 58
Bring in the equation separately and obtain.
20z 37y, 20z 68x, that is, 37y=68x is brought into equation a, and x and y can be solved
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One formula with two unknown quantities, you can't find it!
400+2s=560t+400
s=280t
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What topic? You guys are so annoying, you have to answer, don't send questions! Alas, what a waste of my talent!
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A and B do a total of one job, A works for 5 days, B does it in 20 days, and if A is asked to do it for 20 days, B does it in 8 days. So how long does it take for A and B to do it together.
A's work efficiency is A, and B's work efficiency is B
5a+20b=1(1)
20a+8b=1(2)
72b=3b=1/24
5a=1-20/24
5a=1/6
a=1/30
It takes 1 (1 24 + 1 30) = 24 30 54 = 40 3 days.
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Solution: (8-x) = x -16x+64
From the square of x + the square of 4 = the square of (8-x), we get x -16x + 64 = x +16
Solve x=3
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The land area is x square meters.
40% *5x = 10*15
x=75
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One: 8x+8 5 (eight-fifths) = 16 5
8x=8/5
x=1 5 two: 4 5y=28 5
y=7.Three: 3 5x = 2 5
x=2 3 IV: 30 100x=3
x=10
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Xiao Zhang and Xiao Lin together with the solution of the equation x(3x+2)-6(3x+2)=0 Xiao Zhang decides the left side of the equation into a factor, and obtains (3x+2)(x-6)=0 So 3x+2=0 or x-6=0We get x1=-2 3, x2=6Kobayashi's solution is like this:
Shift the term to get x(3x+2)=6(3x+2), and divide both sides of the equation by (3x+2) to get x=6Kobayashi's solution is wrong!! Pay attention to Peiqin:
When both sides of the equation are divided by one formula, there will be a rootless phenomenon! Kobayashi divides both sides of the equation by (3x+2) and loses a root x= -2 3 Ah! The correct way is Xiao Zhang!
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Kobayashi's solution is flawed, and he should discuss that when 3x+2=0, it can't be divided, and when 3x+2≠0, that's the answer just now.
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No, because there is a solution that is 3x+2=0, and 0 cannot be divided, and if it is reduced, there is one less solution.
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Move backwards and divide by 3x+2 on both sides
The case of 3x+2=0 is not taken into account, so it leads to one less solution, and the second method is wrong.
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