Inverse function of Y COSX 1, urgent !!!

y=cosx+1

cosx=y-1

Because x 0, so.

x=-arccos(y-1)

Swap x and y to get the inverse function.

y=-arccos(x-1)

This is the analytic formula, and then find the defined domain.

Because -pie=so-1=0=

The inverse of the function y=cosx+1 is: y=arccos(x-1), the x-range [0,2].

cosx=y-1

pi x 0 because the anticosine is defined on 0 x pi and the cosine is an even function.

So x=-acrcos(y-1).

The inverse function is y=-arccos(x-1).

The defined domain is the original function value range, i.e., (0,2).

It can be regarded as an addition to the 4th floor, mainly to understand that the definition of the inverse cosine function specifies the symbol ACRCOS.

Directly defined on (0,pi).

For example, if a=acrcos(x) then there must be 0 a pi

cosx=y-1

x=acrcos(y-1)

The inverse function is y=arccos(x-1) and the domain is defined as the original function value domain, [0,2].

y=-arccos(x-1)(0≤x≤2)

When x 0, the value range of the original function is 0 x 2 (the cosx value is -1 1), so the inverse function definition domain obtained is 0 x 2, so when you find the inverse function, you will encounter y-1=cosx, you need to find x, you can write x=arccos(y-1) firstAnd then.

Note that functions such as arccos and arcsin have a feature that not only the value range is limited, but also the definition domain, so as to keep a value corresponding to only one angle, arccosx defines the domain is -1 1, arccos-1= , arccos1=0, when finding the inverted function, the obtained x also needs to look at the specific situation according to y. Since substituting the current definition field 0 y 2 gives 0 x, the sign must be added back to - x 0, so there is this answer.

y=cosxarccosy = x

The inverse function y=arccosx

For a function f to be an explicit inverse function, it must be a bijective function, i.e.,

Monographic) must be mapped to each element of the field only once: otherwise its inverse function will map the element to a value greater than one.

Each element on the full field must be mapped to f: otherwise there will be no way to define the inverse function of f for some element.

x [Book Discussion File, 2].

2 -x Shi Shi [ , 2 ].

y=cosx=cos(2 -x), the value range.

y∈[-1,1]

2π-x=arccosy

x=2π-arccosy

Inverse functions. is y=2 -arccosx ,x state chaos[-1,1].

The inverse function of y=cosx,x [0, ] is y=arccosx,x [-1,1].

y=cosx,x∈[-0]

x [0, ] while y = cosx = cos(-x).

x=rarccosy

x=-arccosy

x,y transposition.

The inverse function of y=cosx,x [-0] is.

y=-arc cosx,x∈[-1,1]

y arccosx x [-1,1] image is a qingda yellow curve.

The inverse function of the graphy is a red curve. Namely.

y arccos -x - x dearly[-1,1].or y -arccosx x [-1,1].

x [ 3 2] 2 -x [ 2, ]y=cosx=cos(2 -x) 1,0] its inverse function is the spine chain x=cos(2 -y ) i.e. 2 -y=arccosx x [-1,0]y=2 -arccosx x [-1,0] The inverse function is to swap x,y, and the range of the original function is the domain of its inverse function, and the definition of the original function.

It is obvious that the inverse function of y=cosx is defined at [0, ] and the number of inverse cracks is y=arccosx

Thus the inverse function of y=cosx in Dan [-2 ,-" is.

y=arccosx-2π

y=2sinx 2(- x<0), then -2<=y<=0sinx 2=y2

x/2=arcsiny/2

x=2arcsiny/2

Then the inverse function is y=2arcsinx 2(-2<=x<=0)y=cosx x [-0], then 0<= x "ascending dispersion <=y<=1y=cosx=-cos( +x)".

cos(π+x)=-y

x=arccos(-y)=arccosyx=arccos(-y)-π

The number of inverse reeds is y=arccos(-x)- 1<=x<=1).

Summary. Hello, it is a pleasure to have your question, and according to the situation you have described, it is generally recommended that you refer to it at this time.

y=x2(cosx+√x)

y=x2cos(x)+x^(2+1/2)

y=x2cos(x)+x5/2

I suggest you refer to it, I hope it can help you, I wish you a happy life, and you can consult me if you have any questions

y=x²(cosx+√2)

Hello, very happy to be able to your question, stuffy shed code according to the situation you described, at present, it is generally recommended that you refer to it y=x2(cosx+ x)y=x2cos(x)+x (2+1 2)y=x2cos(x)+x5 2 I suggest that you refer to it, I hope to help you, I wish you a happy life, if you have any questions, you can consult me

Hello, you see if the question is x, usually this should be x.

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Root number 2 is not root number x

Okay, just wait a minute, I'll answer it right away.

Is it convenient for you to take a picture of the question?

I received it and will answer it for you right away

Hello, I suggest you refer to it.

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