There are 30 shuttlecocks in size, weighing a total of 550 grams, 20 grams each for large shuttlecoc

Assuming that all the big shuttlecocks are 20 30 600 grams, and the actual one is only 550 grams, then if you change the small shuttlecock, one can be less: 20-15 5 grams.

600-550 50 grams, so it takes 50 5 10 to change from a large shuttlecock to a small shuttlecock.

Answer: There are 20 large shuttlecocks and 10 small shuttlecocks.

Solution: If there are x large shuttlecocks, then there are (30-x) small shuttlecocks.

20x+15×(30-x)=550

20x+450-15x=550

5x+450=550

5x=550-450

5x=100

x=2030-x=30-20=10

Answer: There are 20 large shuttlecocks and 10 small shuttlecocks.

For a quadratic equation, let the large shuttlecock x and the small shuttlecock y, then.

x+y=30

20x+15y=550

x=20, y=10

20 large shuttlecocks and 10 small shuttlecocks.

Hope, thank you.

Solution: Let the large shuttlecock be x and the small shuttlecock be y

Get: x+y=30(1).

20x+15y=550（2）

From (1) we get x=30-y(3).

Substitute (3) into (2) to get:

20（30-y）+15y=550

Simplification yields 600-20y+15y=550

5y=50 gives y=10

Substituting y=10 into (1) gives x+10=30

Solution x=20

In summary, x=20, y=10

20 grams of large shuttlecock and 10 grams of small shuttlecock.

Establish a system of binary linear equations.

20 large shuttlecocks and 10 small shuttlecocks.

20 large shuttlecocks, 10 small shuttlecocks.

Arithmetic method: chickens and rabbits in the same cage problem, assuming that all are large shuttlecocks, then the total weight of 30 is 30x20 = 600 grams, so that it is 600 550 = 50 grams more than the actual total weight, because every mistake to take a small shuttlecock as a large shuttlecock will be 20 15 = 5 grams, so there are a total of 50 5 = 10 shuttlecocks, 30 10 = 20 shuttlecocks.

Equation: Solution: Let there be x large shuttlecocks and (30 x) small shuttlecocks.

20x+15(30−x)=550

20x+450−15x=550

5x=100

x = 20 small: 30 20 = 10.

Let there be x large shuttlecocks and y small shuttlecocks, then:

x + y = 30 (the total number of shuttlecocks is 30) 20x + 15y = 550 (the total weight of shuttlecocks is 550 grams) deformation of the first equation yields: y = 30 - x into the second equation, get:

20x + 15 (30 - x) = 550

5x = 200

Solve x and get: x=40 5=8

Therefore, the number of large shuttlecocks is 8, and the number of small shuttlecocks is 22.

Regarding this question, the first thing that should be done is 20-15=5, then 20 30-550=50, and finally 50 5=10, so there should be 10 shuttlecocks. There should be 20 shuttlecocks.

Summary. There are 6 groups of people, 1 group has two people, then there are 12 people in 6 groups, and there are 36 shuttlecocks in total, so each person has 3 shuttlecocks, and the equation is: 36 12=3

In this question, you only need to know how many people there are, and then divide the total number of shuttlecocks by the total number of people to get how many shuttlecocks each person has.

There are a total of 36 shuttlecocks. There are 6 groups of people kicking shuttlecocks on the playground, 2 people in each group. There are a few shuttlecocks per person.

Hello dear, there are 3 shuttlecocks per person.

There are a total of 6 groups of people, 1 group has two people, then there are a total of 12 people in the 6 groups of Tuanchen, a total of 36 shuttlecocks, so each Zen person has 3 shuttlecocks, the equation is: 36 12 = 3 This question only needs to know how many people there are, and then divide the total number of shuttlecocks by the total number of people to get how many shuttlecocks each person debates.

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There are 100 students in the fourth grade to participate in the shuttlecock kicking competition, and we need several boxes of shuttlecock 30 per box, so if we use 100 to divide 30 by 30, we will get three more ten, so we need four leather boxes of shuttlecock to make Xiangzi, otherwise if you only buy three boxes, there will be ten children who will not be covered, so we need four 40.

This question is the knowledge of the remainder of the 75 + 30 = 2 (pcs.) 15 (yuan) A: There are 15 yuan left.

100 x2 = 200 (pcs).

200 +30 7 (box).

Answer: A total of 7 boxes of feather shuttlecock are needed.

Summary. 4 pigeon eggs and 5 eggs weigh a total of 330 grams, 2 pigeon eggs and 6 eggs weigh a total of 340 grams, one pigeon egg and one.

I haven't started solving equations yet, and this is a problem that I sent in the third grade.

If you haven't learned the equation yet, draw a diagram and you wait a moment.

There are 20 children kicking shuttlecocks, and every five people use four laughs to prepare a button, how many shuttlecocks are needed?

20÷5x4

4x416 pcs.

The answer is that there are 20 children who are kicking the shuttlecock, and every five people use four keys, a total of 16 keys are needed to roll quietly.