Kneel down and ask a question to the top of the Internet!!

Some routers can be controlled, and the other is software control.

There is a lot of software, and a lot of P2P terminators can be controlled.

It is recommended that you find an ARP firewall to install, and you are looking for an anti-P2P control software, which you can find on the Internet.

I'm also Tietong's broadband, but I'm at home, only 2 computers, usually**, if there are more resources, they are all above 400k; There have been more than a dozen ks like yours. But that's very little resource

You're normal. So slow, I don't know how you got on, can you still get on. Hehe.

Tietong is not as good as telecommunications. 、Plus you're 1m broadband.、That's not to mention the speed.、The router can control the speed of other people's Internet access.。。 Hehe.

1m divided by 8=== actual internet speed.

You can try it with P2P Terminator.

To be honest, Tietong is just like this, the speed is not fast, let alone so many people. It's okay to say you want to limit the speed.,You can log in to the router.,You have the admin account password.,That's it.,You can set it up.。 Or you can install a P2P terminator, or you can set it up, and the operation is simple.

It's certainly not going to be fast. Tietong is enough for one person. You 4 people routed.

I can explain it to you responsibly.

2。The router used by the landlord's Tietong can divide the bandwidth, with an average of more than KB per person.

3。Through the ARP software, the network bandwidth is limited, this kind of software, no matter which machine in the LAN can be used, one can control the bandwidth of the machine in the entire internal LAN, 4. Other machines in the LAN, ** movies or something, or watching QQ, pp live broadcast, fast broadcast software to watch movies, occupy bandwidth.

Question 1 11a=t:13b=t; (a+b-28)*25 4=t Solve it yourself, and the answer is t

Question 2 (40+100 3)*a=x ; 90*b=x；a+b=30 d, the answer is x, solve it yourself.

If 6 LEDs are connected in series, the operating voltage is about 120-150mA), the voltage drop across each resistor is about (24-20) 2=2V, and the current: 2 220=. This is inconsistent with assumptions.

The resistance should be 22 ohms (i.e. 220 instead of 221), and the operating current is 2. The resistors are connected in series where they are the same. Separating the resistors is just a matter of heat dissipation.

That is, the working voltage of the actual LED is about:. Operating current: approx. 110mA.