Sophomore Chemistry I want to know how to write twenty questions in detail

Hello. SO2 + O2 = Reversible = 2SO3

From A B to 2x x 2x

Ping 8 4 so x=2, so a=12, so b=82, the reaction of SO2 4mol is 392, 2mol is 1962SO2 (g) + O2 (g) = 2SO3 (g) H=-196kJ mol

4. The amount of the substance before the reaction is 20mol, and the amount difference after the reaction is 20* The difference in the amount of the substance is 2SO+O2=reversible=2SO3 N

Then the amount of SO3 in equilibrium, the concentration is.

The conversion rate is greater than. Originally, it was a reaction to the decrease in the volume of the gas, and the pressure would decrease when the volume was constant, and the constant pressure was equivalent to pressurizing under the condition of constant volume, so it moved in the positive direction, so it was greater than.

b=8mol SO3=4mol then the original SO2=8+4=12mol, 196kJ mol

SO2 reacted 4mol volume 5l time 10min4 5x10=

PV=Nrt after nrt.

12+8=20mol before reaction

After the reaction = decrease = O2 is SO3 = SO2 is involved in the reaction A=

Air O2

Fill the test tube with a sufficient amount of nitrogen, drain the air and start heating until all the black solids turn red, stop heating, and stop introducing nitrogen after cooling.

n2 o2 co

Replace the clarified lime water with a sufficient amount of sodium hydroxide solution.

There are difficult questions to ask.

Secondary HSO4- can be completely ionized.

nahso4=na++h++so42-

CaCO3 is insoluble in water and cannot be disassembled.

CaCO3+2H+=Ca2+ +H2O+CO2 gas sulfuric acid and barium hydroxide are both strong electrolytes, and both are soluble in water, and the strong electrolyte is disassembled 2H+ +SO42- +BA2+ +2OH-===BASO4 +2H2O

Calcium hydroxide is a strong electrolyte, although the solubility is not high, but it refers to clarified lime water, indicating that calcium hydroxide is completely soluble in water. co2+ca2++2oh-=caco3↓+h2o

According to reaction 2, ch2 = according to the equation measurement, the decomposed chi = so said by reaction 1, the actual decomposition of chi = 4 + 1 = 5 moll - according to reaction 1, calculated according to the equation measurement number, decomposition cnh3 = chi = 5 moll - according to the reaction 1 actual gaseous product concentration k = cnh3xchi = 5x4 = 20

Wrong. The pH change of a certain electrode should be judged according to its electrode reaction, and the electrode reaction of electrode B should be SO2+4HO--2E-=SO42-+2H2OHydroxide is consumed, and the pH should be reduced.

3,5,8

8kno3 == k+ ＋no3－

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species, number of protons, number of neutrons, number of electrons are all.

1. It can be composed of up to 3 kinds of water; 10mol of protons; 10mol of neutrons; 10mol of electrons (in H2O, the number of electrons = the number of protons).

2. The second question, I can't see the left and right superscripts of x, so I will tell you about it and do it yourself.

Number of nuclear charges = number of protons = 18 - the number of the right superscript of x (take a positive number) and the number of neutrons = the left superscript value of x - the number of nuclear charges.

21（1） hno3；reddish-brown; N2 + 3H2 = high temperature, high pressure, catalyst = 2nH3 (reversible reaction).

2）so2；Equation for the reaction of iron with concentrated sulfuric acid, 2Fe 6H2SO4 Fe2(SO4)3 3SO2(gas) 6H2O

Procedure: (1) NH3-NO-NO2-HNO3 (2)H2S-SO2-SO3-H2SO4

Procedure: 2NaHCO3 CO2

2） mol/l；；

Process: omitted; ba(oh)2~baco3；hcl~nahco3